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Error Overloading Ambiguity Between Built In Operator

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the company Business Learn more about hiring developers or posting ads with us Stack bool operator overloading c++ Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of the safe bool idiom 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up “ambiguous overload for 'operator[]'” if conversion operator to int exist up vote 11 down vote favorite 3 I'm

Bool Operator C#

trying to implement the vector like and the map like [] operator for a class. But I get error messages from my compilers (g++ and clang++). Found out that they only occurs if the class has also conversion operators to integer types. Now I have two problems. The first is that I don't know why the compiler can't distinguish between [](const std::string&) and when the class has conversion operators to ints. The

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second... I need the conversion and the index operator. Does anyone know how to fix that? thanks in advance and best regards from me works: #include #include struct Foo { Foo& operator[](const std::string &foo) {} Foo& operator[](size_t index) {} }; int main() { Foo f; f["foo"]; f[2]; } does not work: #include #include struct Foo { operator uint32_t() {} Foo& operator[](const std::string &foo) {} Foo& operator[](size_t index) {} }; int main() { Foo f; f["foo"]; f[2]; } compiler error: main.cpp: In function 'int main()': main.cpp:14:9: error: ambiguous overload for 'operator[]' in 'f["foo"]' main.cpp:14:9: note: candidates are: main.cpp:14:9: note: operator[](long int, const char*) main.cpp:7:7: note: Foo& Foo::operator[](const string&) main.cpp:8:7: note: Foo& Foo::operator[](size_t) main.cpp:8:7: note: no known conversion for argument 1 from 'const char [4]' to 'size_t {aka long unsigned int}' c++ share|improve this question edited Apr 6 '13 at 18:57 asked Apr 6 '13 at 12:17 r2p2 12511 There is no such thing as a "cast operator". The operator in question is a conversion. A cast is something you write in your source code to tell the compiler to do a conversion. –Pete Becker Apr 6 '13 at 18:46 Thank you @Pete Becker for pointing that out. –r2p2 Apr 6 '13 at 18:57 add

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more c++ operator about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up operator[](const char *) ambiguity up vote 11 down vote favorite The following code #include struct Foo { operator double() { return 1; } int operator[](std::string x) { http://stackoverflow.com/questions/15850840/ambiguous-overload-for-operator-if-conversion-operator-to-int-exist return 1; } }; int main() { Foo()["abcd"]; } Compiles fine with g++ but fails with clang and intel compilers because of an ambiguity between the declared method and native operator []. It would be clear for me if Foo had an implicit conversion to int, but here the conversion is to double. Doesn't that solve the ambiguity? c++ share|improve this question asked Aug 4 '14 at 7:27 6502 69.2k1076154 3 What happens if you remove the http://stackoverflow.com/questions/25113661/operatorconst-char-ambiguity conversion operator to double? –R Sahu Aug 4 '14 at 7:37 Works fine on clang without the conversion operator for me. –Ray Toal Aug 4 '14 at 7:41 This is pretty much the same problem as stackoverflow.com/questions/8914986/… –T.C. Aug 4 '14 at 8:45 Does it compile with icc when you remove Foo::operator[]? –n.m. Aug 4 '14 at 9:06 @n.m. Checked with icl (the Windows version of icc) on my computer, and it does compile. But then icl also wrongly compiles one of the examples in §13.3.1.2 [over.match.oper]/p7 that the standard says shouldn't compile, so... –T.C. Aug 4 '14 at 9:11 | show 2 more comments 1 Answer 1 active oldest votes up vote 6 down vote accepted §13.3.3.1.2 [over.ics.user]/p1-2: A user-defined conversion sequence consists of an initial standard conversion sequence followed by a user-defined conversion (12.3) followed by a second standard conversion sequence. If the user-defined conversion is specified by a constructor (12.3.1), the initial standard conversion sequence converts the source type to the type required by the argument of the constructor. If the user-defined conversion is specified by a conversion function (12.3.2), the initial standard conversion sequence converts the source type to the implicit object parameter of the conversion function. The second standard conversion sequence converts the result of the user-defined conversion to the target type for the sequence. In particula

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resources Windows Server 2012 resources Programs MSDN subscriptions Overview Benefits Administrators Students Microsoft Imagine Microsoft Student Partners ISV Startups TechRewards Events Community Magazine Forums Blogs Channel 9 Documentation APIs and reference Dev centers Retired content Samples We’re sorry. The content you requested has been removed. You’ll be auto redirected in 1 second. C/C++ Language and Standard Libraries C++ Language Reference Functions Functions Function Overloading Function Overloading Function Overloading Functions with Variable Argument Lists Function Overloading Explicitly Defaulted and Deleted Functions Argument-Dependent Name (Koenig) Lookup on Functions Default Arguments Inline Functions TOC Collapse the table of content Expand the table of content This documentation is archived and is not being maintained. This documentation is archived and is not being maintained. Function Overloading Visual Studio 2015 Other Versions Visual Studio 2013 Visual Studio 2012 Visual Studio 2010 Visual Studio 2008 Visual Studio 2005 Visual Studio .NET 2003  C++ allows specification of more than one function of the same name in the same scope. These are called overloaded functions and are described in detail in Overloading. Overloaded functions enable programmers to supply different semantics for a function, depending on the types and number of arguments.For example, a print function that takes a string (or char *) argument performs very different tasks than one that takes an argument of type double. Overloading permits uniform naming and prevents programmers from having to invent names such as print_sz or print_d. The following table shows what parts of a function declaration C++ uses to differentiate between groups of functions with the same name in the same scope.Overloading ConsiderationsFunction Declaration ElementUsed for Overloading?Function return typeNoNumber of argumentsYesType of argumentsYesPresence or absence of ellipsisYesUse of typedef namesNoUnspecified array boundsNoconst or volatile (see below)YesAlthough functions can be distinguished on the basis of return type, they cannot be overloaded on this basis. Const or volatile are only used as a basis for overloading if they are used in a class to apply to the this pointer for t

 

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