Error Called Object Is Not A Function Or Function Pointer

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Error Called Object Type 'int' Is Not A Function Or Function Pointer

with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the error called object type 'double' is not a function or function pointer Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: called object type 'double' is not a function or function pointer Sign up error: called object type 'int' is not a function or function pointer up vote 8 down vote favorite 1 I have a quicksort that I wrote here: void swap(int& a, int& b); int mid(int lo, int hi); // My quicksort

Called Object Type 'float' Is Not A Function Or Function Pointer

implementation void sort(int vec[], int lo, int hi) { int mid; if (hi > lo) { int i = lo + 1; int j = hi; int p = mid(lo, hi); swap(vec[lo], vec[p]); mid = vec[lo]; while (i < j) { if (vec[i] <= mid) { i++; } else { while (i < --j && vec[j] >= mid); swap(vec[i], vec[j]); } } i++; swap(vec[lo], vec[i]); sort(vec, lo, i); sort(vec, j, hi); } } void swap(int& a, int& b) { int temp = a;

Called Object Type 'nsstring *' Is Not A Function Or Function Pointer

a = b; b = temp; } int mid(int lo, int hi) { return lo + ((hi - lo) / 2); } I tried compiling to an object file with g++ -g -c array.cpp -o array.o I get this error: array.cpp:24:14: error: called object type 'int' is not a function or function pointer int p = mid(lo, hi); ~~~^ 1 error generated. Everything looks correct. Can anyone help me figure out what is wrong? c++ quicksort share|improve this question edited Nov 1 '13 at 18:32 chris 37.9k678137 asked Nov 1 '13 at 18:31 Pocketkid2 1431211 5 You declared int mid; but call mid(lo, hi)... –chris Nov 1 '13 at 18:33 add a comment| 2 Answers 2 active oldest votes up vote 14 down vote accepted Your local variable mid is declared in the scope that is closer to the point of use, so it "shadows" the mid() function; the compiler thinks that you are trying to "call" an integer, which is invalid. Rename the local variable to fix this problem: int midpoint; if (hi > lo) { int i = lo + 1; int j = hi; int p = mid(lo, hi); swap(vec[lo], vec[p]); midpoint = vec[lo]; ... } Note: you could also use ::mid(lo, hi) instead of renaming the variable, but that would confuse the readers of your program. share|improve this answer edited Mar 12 at 18:10 Jérôme Leducq 4,40241128 answered Nov 1 '13 at 18:33 dasblinkenlight 455k39492842 +1. Of course, the alternativ

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Called Object Is Not A Function C

us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is error called object time is not a function a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error: called object type int is not a function or function pointer up vote http://stackoverflow.com/questions/19733090/error-called-object-type-int-is-not-a-function-or-function-pointer 1 down vote favorite I get this error in my C code: error:called object type int is not a function or function pointer I have looked all over for an answer and everywhere I have checked confirms this code should be working, so what am I missing? I want to assign random numbers to two different variables. I've commented off the errors I'm getting in my IDE. (Note: this isnt http://stackoverflow.com/questions/30825390/error-called-object-type-int-is-not-a-function-or-function-pointer the full code, just the relevant section) #include #include #include int main(void){ int k, seed, mines, row, column, boom; int board[9][10]; printf("Please enter your seed: "); scanf("%d", &seed); getchar(); srand(seed); for(k = 1; k <= mines; k++) { row = rand() % 8; //error:called object type int is not a function or function pointer column = rand() % 8; //error:called object type int is not a function or function pointer if(board[row][column] == 0) { board[row][column] = boom; } } } c random share|improve this question edited Jun 14 '15 at 3:18 Evert 10.9k32640 asked Jun 14 '15 at 2:19 crushendo 715 4 In k; seed; mines; row; column, did you mean k, seed, mines, row, column (with commas)? –Peter O. Jun 14 '15 at 2:23 2 What is boom and board? declaration missing !! –Steephen Jun 14 '15 at 2:35 1 @crushendo board is a 2 dimensional array as per code, but declared as an int now –Steephen Jun 14 '15 at 2:58 1 Get the code to compile first –Ed Heal Jun 14 '15 at 3:01 3 It sounds like you've redefined rand somewhere, since the compiler mentions calling an object that is not a function. Do a search

function pointer? Page 1 of 1 New Topic/Question Reply 3 Replies - 8712 Views - Last Post: 16 November 2013 - 05:13 PM Rate Topic: #1 SonicSoundVW New D.I.C Head Reputation: 0 Posts: 35 Joined: 05-November 13 problem, called object http://www.dreamincode.net/forums/topic/334210-problem-called-object-type-not-a-function-or-function-pointer/ type not a function or function pointer? Posted 16 November 2013 - 04:52 PM My http://forums.devshed.com/programming-42/called-object-type-int-function-function-pointer-939805.html code will not compile due to 2 errors. called object type 'char *' is not a function or function pointer and expected unqualified-id. i have moved the brackets and to be honest, with my limited knowledge, i honestly don't see what is wrong. If somebody could point me in the right direction and or give any advice about my code it called object would be greatly appreciated. Thank you in advance. :-) #include using namespace std; int sentenceCount (char[]); void allCap(char[], int); void displaySentence(char []); void numVowels(char [], int&, int&, int&, int&, int&); void reverseSentence(char [],char []); int main() { const int SIZE = 50; char sentence[SIZE]; char reverseSentence[SIZE]; int a, e, i, o, u; int howMany = 0; cout << "Please enter a sentence of no more than" << endl; cout << (SIZE -1) << " is not a characters:\n"; cin.getline(sentence, SIZE); cout << endl; cout << "The sentence you entered is:\n"; displaySentence(sentence); cout << endl << endl; howMany = sentenceCount(sentence); cout << "There were " << howMany << " charcters entered." << endl; cout << endl; allCap(sentence, howMany); cout << "This is what the sentence would look like" << endl; cout << "with all capital letters: " << endl; displaySentence(sentence); cout << endl << endl; numVowels(sentence, a, e, i, o, u); cout << "This sentence contains:" << endl; cout << a << " As " << e << " Es " << i << " Is "; cout << o << " Os and " << u << " Us " << endl << endl; reverseSentence(sentence, reverseSentence); //This is marked with the called object type 'char *' is not a function or function pointer displaySentence(reverseSentence); cout << endl; return 0; } int sentenceCount (char array[]) { int howMany = 0; int count = 0; while (array[count]!='\0'){ howMany ++; count++; } return howMany; } void allCap(char array[], int numChar) { for (int i = 0; i < numChar; i++) { if((array[i] >= 97) && (array[i] <= 122)) // checking if character is lowercase. array[i] -= 32; // convert to uppercase. } } void displaySentence(char array[]) { int count = 0; while (array[count] != '\0') { cout << array[count]; count++; } } void numVowels(char array[

Search Username Password Remember Me? Register Lost Password? facebook google twitter rss Free Web Developer Tools Advanced Search  Forum Programming Languages C Programming Called object type 'int' is not a function or function pointer Thread: Called object type 'int' is not a function or function pointer Share This Thread  Tweet This + 1 this Post To Linkedin Subscribe to this Thread  Subscribe to This Thread February 12th, 2013,05:52 PM #1 No Profile Picture Miktor View Profile View Forum Posts  Registered User Devshed Newbie (0 - 499 posts)  Join Date Apr 2012 Posts 29 Rep Power 0 Called object type 'int' is not a function or function pointer I wrote this program to caesar encrypt a string (alphabetic characters only). (i.e. take all the characters in a sentence and rotate them key times - i.e. whatever number is entered as the key command line parameter) Code: #include #include #include #include #include char caesar_encode (char, int); // prototype of caesar_encode function // +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ int main (int argc, string argv[]) { int key = 0; int length, base, asciiCode; string sentence; char currentLetter, caesar_encode; // if wrong number of command line arguments, shout at user then quit if (argc != 2) { printf("Incorrect number of command line arguments.\n\n"); return 1; } // if key parameter is too low, shout at user then quit key = atoi(argv[1]); // printf("key = %i\n\n", key); if (key < 1) { printf("Key parameter is too low.\n\n"); return 1; } // since key values modulo 26 are equivalent for the purposes of our program // if a key value is larger than 26, reduce it to its modulo 26 equivalent // (i.e. a number from 0 to 26) if (key > 26) { // printf("Reducing key larger than 26 to its modulo 26 equivalent.\n"); // printf(