Mysql Database Error Cannot Create Table Errno 150
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Can't Create Table (errno: 121)Mysql. Can't create table errno 150 up vote 66 down vote favorite 7 I have to create a db with 2 tables in mysql but the script fails with errno 150 (Foreign key problem). I double-checked the foreign key fields to be the same on both tables and I can't find any error. Here is the script: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; error 1005 (hy000) can't create table (errno 150) SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `testdb`; CREATE SCHEMA IF NOT EXISTS `testdb` DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ; USE `testdb`; DROP TABLE IF EXISTS `testdb`.`table1` ; CREATE TABLE IF NOT EXISTS `testdb`.`table1` ( `id` INT UNSIGNED NOT NULL , `field1` VARCHAR(50) NULL , PRIMARY KEY (`id`) ) ENGINE = InnoDB; DROP TABLE IF EXISTS `testdb`.`table2` ; CREATE TABLE IF NOT EXISTS `testdb`.`table2` ( `id` INT NOT NULL AUTO_INCREMENT , `field1` VARCHAR(50) NULL , `date` DATE NULL , `cnt` INT NULL , PRIMARY KEY (`id`) , INDEX `FK_table2_table1` (`field1` ASC) , CONSTRAINT `FK_table2_table1` FOREIGN KEY (`field1`) REFERENCES `testdb`.`table1` (`field1` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; I've tried it in Windows and Ubuntu with different versions of Mysql and didn't work. Any ideas? Thanks a lot. mysql mysql-error-1005 share|improve this question edited Apr 30 '11 at 17:14 OMG Ponies 199k37360417 asked Nov 17 '09 at 14:40 David Espart 6,05662439 9 I also received this error by attempting to create a table with a FK constraint to another table that did not yet exist.
SQL Insertion Learn how web applications with access to your database (e.g. MySQL) may be used to poison, dump, or delete information in your database. MySQL Foreign Keys Learn all about MySQL foreign keys in this white paper. MySQL Foreign Key Errors and Errno: 150 Learn can t create table errno 150 django how to avoid MySQL foreign key errors, including the notorious Errno:150 in this white paper. MySQL/SQL can't create table (errno 150) foreign key constraint is incorrectly formed Data Validation (with PHP) Learn the importance of data validation in web applications when information is accepted from third parties, or even from internal error on rename of (errno 150) users. MySQL Foreign Key Errors: errno 150, errno 121, and others Diagnosing Errors SHOW ENGINE INNODB STATUS is Your New Best Friend: Click for solutionIf you get one of the really helpful errors (sarcasm) like the errno 150 or errno http://stackoverflow.com/questions/1749332/mysql-cant-create-table-errno-150 121, then by simply typing in SHOW ENGINE INNODB STATUS, there is a section called "LATEST FOREIGN KEY ERROR". Under that it will give you a very helpful error message, which typically will tell you right away what is the matter. What's the catch?You need SUPER privileges to run it, so if you don't have that, you'll just have to test out the following scenarios. Use Eliacom's MySQL GUI tool to catch most errors: Click for solutionYou can either http://www.eliacom.com/mysql-gui-wp-errno-150.php download the MySQL GUI to install on your own server, or you can use our free online demo of the MySQL GUI to do it. You can check out our video on how to create foreign keys and indexes using Eliacom's MySQL GUI tool.. MySQL errno 150 ERROR 1005 (HY000): Can't create table 'table' (errno: 150) ERROR 1025 (HY000): Error on rename of 'table' to 'newtable' (errno: 150) Causes and Solutions for errno 150 Data Types Don't Match: Click for solutionThe types of the columns have to be the same (usually). This is one of the most common reasons for errno 150. For instance, if the type of the child column is VARCHAR(50), the type of the parent column should be exactly VARCHAR(50) (since they're supposed to hold the same data). For numeric types, if one is UNSIGNED, then both have to be UNSIGNED. They should match exactly!. I have run into circumstances where it has let me create a foreign key where the child column was a VARCHAR(50) and the parent column was a VARCHAR(200). Interestingly, if I tried to do the opposite for the same tables, reference a child column that was a VARCHAR(200) to a parent column that was a VARCHAR(50), it threw the errno 150 error. This all might depend on the version of MySQL you are using, and really, the data types should match exactly since the same data is being sto
log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the http://dba.stackexchange.com/questions/5437/mysql-foreign-key-cant-create-table-error-150 company Business Learn more about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to https://mariadb.org/mariadb-innodb-foreign-key-constraint-errors/ improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted create table up and rise to the top MySQL, foreign key, can't create table error 150 up vote 5 down vote favorite 1 UPDATE: Sorry, it was because i forgot to add UNSIGNED attribute to the lang_id column. Original: I'm trying to create a table with foreign key in MySQL. I get this error: #1005 - Can't create table 'xy.trans' (errno: 150) Any ideas whats wrong with the following create statement? CREATE TABLE IF NOT EXISTS t create table `lang` ( `id` INT UNSIGNED NOT NULL AUTO_INCREMENT, `code` CHAR(2) NOT NULL, PRIMARY KEY (`id`) ) ENGINE = InnoDB; CREATE TABLE IF NOT EXISTS `trans` ( `id` INT UNSIGNED NOT NULL AUTO_INCREMENT, `something` TEXT NOT NULL, `lang_id` INT NULL, PRIMARY KEY (`id`), INDEX `index_trans_lang` (`lang_id` ASC), CONSTRAINT `fk_trans_lang` FOREIGN KEY (`lang_id` ) REFERENCES `lang` (`id` ) ON DELETE SET NULL ON UPDATE CASCADE ) ENGINE = InnoDB; mysql foreign-key share|improve this question edited Jan 14 '13 at 12:07 Akash 542318 asked Sep 6 '11 at 10:39 Ben 2613 Ah, +1 for solving your own problem !!! –RolandoMySQLDBA Sep 6 '11 at 15:00 3 @Ben, if you would be so kind as to post your answer as an answer proper, and mark it accepted, you'll get upvotes (higher rep) and it'll be more clear what transpired here. –jcolebrand♦ Sep 6 '11 at 18:08 add a comment| 2 Answers 2 active oldest votes up vote 1 down vote I've had a similar problem with this, and I finally resolved it by checking the field types of the two fields that were being referenced - they have to be exactly the same type - all the way down to the "Not NUll" and "Unsigned" settings... In your original post, the "lang" table has the "id" field defined as "INT UNSIGNED NOT NU
for Developers MariaDB Contributor Agreement MariaDB Contributor Agreement FAQs Community Ambassadors Events Past Events and Conferences Sponsor Sponsors List of Donors Blog About MariaDB Sponsors Governance Logos and Badges MariaDB Trademark Usage Statistics Service Providers Maintenance Policy Security Policy Download Learn Get Involved Social Media Getting Started for Developers MariaDB Contributor Agreement MariaDB Contributor Agreement FAQs Community Ambassadors Events Past Events and Conferences Sponsor Sponsors List of Donors Blog HomeGeneralMariaDB: InnoDB foreign key constraint errors MariaDB: InnoDB foreign key constraint errors 2015-08-07 4 Comments Written by Jan Lindstrom Introduction A foreign key is a field (or collection of fields) in one table that uniquely identifies a row of another table. The table containing the foreign key is called the child table, and the table containing the candidate key is called the referenced or parent table. The purpose of the foreign key is to identify a particular row of the referenced table. Therefore, it is required that the foreign key is equal to the candidate key in some row of the primary table, or else have no value (the NULL value). This is called a referential integrity constraint between the two tables. Because violations of these constraints can be the source of many database problems, most database management systems provide mechanisms to ensure that every non-null foreign key corresponds to a row of the referenced table. Consider following simple example: create table parent ( id int not null primary key, name char(80) ) engine=innodb; create table child ( id int not null, name char(80), parent_id int, foreign key(parent_id) references parent(id) ) engine=innodb; As far as I know, the following storage engines for MariaDB and/or MySQL support foreign keys: InnoDB (both innodb_