Java Divide By 0 Error
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problem occurs infrequently-if the "rule" is that a statement normally executes correctly, then the "exception to the rule" is that a problem occurs. Exception handling enables programmers to create java divide by zero exception applications that can resolve (or handle) exceptions. In many cases, handling an exception
Java Divide By Zero Infinity
allows a program to continue executing as if no problem had been encountered. A more severe problem could prevent a how to catch divide by zero exception in java program from continuing normal execution, instead requiring it to notify the user of the problem before terminating in a controlled manner. Exception handling enables programmers to write robust and fault-tolerant programs (i.e., programs
Divide By Zero Exception In C++ Program
that are able to deal with problems that may arise and continue executing). This tutorial demonstrates a program in which a exceptions occur. The program does not process these exceptions, which results in difficult-to-understand error messages being displayed to the user. In Part 2 of this tutorial, we demonstrate how to catch and handle these exceptions. This tutorial is intended for students and professionals who are java arithmeticexception familiar with classes and basic inheritance concepts in Java. Download the code for this tutorial here. [Note: This tutorial is an excerpt (Section 13.3) of Chapter 13, Exception Handling, from our textbook Java How to Program, 6/e. This tutorial may refer to other chapters or sections of the book that are not included here. Permission Information: Deitel, Harvey M. and Paul J., JAVA HOW TO PROGRAM, ©2005, pp.641-643. Electronically reproduced by permission of Pearson Education, Inc., Upper Saddle River, New Jersey.] 13.3 Divide By Zero Without Exception Handling First we demonstrate what happens when errors arise in an application that does not use exception handling. Figure Fig. 13.1 prompts the user for two integers and passes them to method quotient, which calculates the quotient and returns an int result. In this example, we will see that exceptions are thrown (i.e., the exception occurs) when a method detects a problem and is unable to handle it.
Fig. 13.1 Integer division without exception handling. 1 // Fig. 13.1: DivideByZeroNoExceptionHandling.java 2 // An application that attempts to divide by zero. 3 import java.util.Scanner; 4 5 public class DivideByZeroNoExceptionHandling 6 { 7 // demonstrates throwing an exception when a divide-by-zerhere for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us
Try Catch Block For Divide By Zero
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Divide By Zero Exception In C#
posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow try catch divide by zero Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up divide by zero error up vote 1 down vote http://www.deitel.com/articles/java_tutorials/20060408/DivideByZero/ favorite here is the code (java): class prime { public static boolean prime (int a, int b) { if (a == 0) { return false; } else if ((a%(b-1) == 0) && (b>2)) { return false; } else if (b>1) { return (prime (a, b-1)) ; } else { return true; } } public static void main (String[] arg) { System.out.println (prime (7, 7)) ; } } http://stackoverflow.com/questions/2414250/divide-by-zero-error This is the error message i get when i try to run it (it compiles fine): Exception in thread "main" java.lang.ArithmeticException: / by zero at prime.prime(prime.java:10) at prime.prime(prime.java:16) at prime.prime(prime.java:16) at prime.prime(prime.java:16) at prime.prime(prime.java:16) at prime.prime(prime.java:16) at prime.prime(prime.java:16) at prime.main(prime.java:27) So this means i devided by zero some how right? or does it mean something else? I don't see how i'm dividing by zero. What went wrong? java divide-by-zero share|improve this question edited Oct 1 '12 at 9:45 Aziz Shaikh 11.6k73954 asked Mar 10 '10 at 3:09 David 4,073195381 add a comment| 3 Answers 3 active oldest votes up vote 12 down vote accepted Try turning this around if ((a%(b-1) == 0) && (b>2)) to if ((b>2) && a%(b-1)==0) What's happening is that the a%(b-1) operation is being executed before the b>2 test. After the switch, you are taking advantage of short-circuit evaluation. Once the b>2 test returns false, then there's no need to calculate the modulus (hence avoiding the division) share|improve this answer edited Mar 10 '10 at 3:20 answered Mar 10 '10 at 3:13 Tom 23k1495145 that fixed it. thanks for your help. –David Mar 10 '10 at 3:42 add a comment| up vote 2 down vote
SOAEJB3SpringPDFEmailJ2MEJ2EE ApplicationXMLDesign PatternLogSecurityApache CommonAntJUnitcatch divide-by-zero error : try http://www.java2s.com/Tutorial/Java/0080__Statement-Control/catchdividebyzeroerror.htm catch«Statement Control«Java TutorialJava TutorialStatement Controltry catchpublic class MainClass { https://www.tutorialspoint.com/javaexamples/exception_multiple.htm public static void main(String args[]) { int d, divide by a; try { d = 0; a = 42 / d; System.out.println("This will not be printed."); } catch divide by zero (ArithmeticException e) { // System.out.println("Division by zero."); } System.out.println("After catch statement."); } } 4.10.try catch4.10.1.catch divide-by-zero error4.10.2.Handle an exception and move on.4.10.3.Demonstrate multiple catch statements.4.10.4.Catch different Exception types4.10.5.An example of nested try statements.4.10.6.Try statements can be implicitly nested via calls to methodsjava2s.com |Email:info at java2s.com|© Demo Source and Support. All rights reserved.
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