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Caused Divide Error Overflow Program

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by 0" or "Divide Overflow" error messages. The divide error messages are caused when the computer or software attempts run a process that attempts to perform a mathematical division by zero, which is an illegal operation. your program caused a divide overflow error This error message could also be caused by a computer or software limitation or conflict divide error overflow emu8086 with computer memory. Improper calculation If you or the program you are using performs a calculation in any program and experience a divide divide overflow in computer architecture error, ensure that the calculation being performed is possible. Some programs are not capable of verifying the accuracy of a calculation and may perform an illegal instruction. Programs such as Microsoft Excel, will generate a #DIV!0 error divide overflow error in assembly language indicating the formula or calculation is invalid, or you are attempting to divide by zero. Hardware or software incompatibility This issue can occur if software is being run on a computer that has hardware that is incompatible with the software. For example, this issue may occur with restore software designed for a specific computer and is being run on another computer or on the correct computer that has added hardware within it. Make sure all software

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installed on the computer is up to date and fully compatible with the system. Driver issue If you are encountering a divide error while using Windows, make sure you are running the latest drivers and software for all component hardware devices. Verify the video card, sound card, network card and modem drivers on the computer. You can find a listing of computer drivers on our driver page. Software issue If the divide error happens while in a game or program and the above recommendations does not resolve your issue, verify all software patches and upgrades have been obtained and applied. Also, verify no other program is running in the background that could be causing your problem by End Tasking all background programs and TSRs. External cache or 2nd level cache If you are encountering the divide error in an older software program or game it can be caused by compatibility issues with External cache or 2nd level cache. Temporarily disabling this feature in CMOS Setup may resolve your issue. Operating system issue If you continue to experience a divide errors and have followed all of the above recommendations, make sure it is not a problem with the operating system by reinstalling the operating system. Hardware issue Finally, if none of the above recommendations resolve or help to determine the cause of your issue the computer m

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Dos Divide Overflow Error

company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions what .startup stands for Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million divide error in c programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Causing a divide overflow error (x86) up vote 6 down vote favorite I have a few questions about divide overflow errors http://www.computerhope.com/issues/ch000396.htm on x86 or x86_64 architecture. Lately I've been reading about integer overflows. Usually, when an arithmetic operation results in an integer overflow, the carry bit or overflow bit in the FLAGS register is set. But apparently, according to this article, overflows resulting from division operations don't set the overflow bit, but rather trigger a hardware exception, similar to when you divide by zero. Now, integer overflows resulting from division are a lot more http://stackoverflow.com/questions/3892379/causing-a-divide-overflow-error-x86 rare than say, multiplication. There's only a few ways to even trigger a division overflow. One way would be to do something like: int16_t a = -32768; int16_t b = -1; int16_t c = a / b; In this case, due to the two's complement representation of signed integers, you can't represent positive 32768 in a signed 16-bit integer, so the division operation overflows, resulting in the erroneous value of -32768. A few questions: 1) Contrary to what this article says, the above did NOT cause a hardware exception. I'm using an x86_64 machine running Linux, and when I divide by zero the program terminates with a Floating point exception. But when I cause a division overflow, the program continues as usual, silently ignoring the erroneous quotient. So why doesn't this cause a hardware exception? 2) Why are division errors treated so severely by the hardware, as opposed to other arithmetic overflows? Why should a multiplication overflow (which is much more likely to accidentally occur) be silently ignored by the hardware, but a division overflow is supposed to trigger a fatal interrupt? =========== EDIT ============== Okay, thanks everyone for the responses. I've gotten responses saying basically that the above 16-bit integer division shouldn't cause a hardware fault because the quotient is still less than the register size. I don't

TechSpot RSS Get our weekly newsletter Search TechSpot Trending Hardware The Web Culture Mobile Gaming Apple Microsoft Google Reviews Graphics Laptops Smartphones CPUs http://www.techspot.com/community/topics/your-program-caused-a-divide-overflow-error.140536/ Storage Cases Keyboard & Mice Outstanding Features Must Reads Hardware Software Gaming http://www.oopweb.com/Assembly/Documents/ArtOfAssembly/Volume/Chapter_17/CH17-2.html Tips & Tricks Best Of Downloads Latest Downloads Popular Apps Editors Picks Device Drivers Product Finder New Releases New PC Games Laptops Smartphones Routers Storage Motherboards Monitors Forums Recent Activity Today's Posts News Comments TechSpot Forums Forums Software Apps & Software Today's Posts Your program caused a divide overflowerror divide overflow ByComputerGuy55 Dec 31, 2009 Ok, so, I got a computer here, power surge happend at their house. The computer POSTs but never gets to windows. It starts, showing the Windws Logo then restarts, even going into safe mode, loads the right files then just restarts. Now on to my main problem where this error shows: Since it is not booting I wanted divide overflow error to test the hardware first, to eliminate going any further on windows problems. I put in my Hiren's BootCD, and go to load a test (hard drive, RAM) and it gives me the error "your program caused a divide overflow error`` I looked up reasons this could happen and tried what I could but with no avail. Tried in the bios setting the chipset to a clockspeed of 266MHz rather then set to Auto, (http://support.microsoft.com/kb/240982/en-us) The RAM runs at 400MHz. Also tried switching out the ram, switching out the processor, as that could be an issue. The disc works fine on other computers, but not this one. So something, either hard ware or some setting is stopping this from being able to run. Another suggestion was to turn off firewalls, but theres no firewall check on bootup or anything.. I`m out of ideas, any suggestions appreciated. EDIT: Ok so, so far I've found out that while both hard drives are connected, I get this error, connected seperatly there is no error and I can run some tests. I haven't left any test ful

Single Step (Trace) Exception (INT 1) 17.3.3 - Breakpoint Exception (INT 3) 17.3.4 - Overflow Exception (INT 4/INTO) 17.3.5 - Bounds Exception (INT 5/BOUND) 17.3.6 - Invalid Opcode Exception (INT 6) 17.3.7 - Coprocessor Not Available (INT 7) 17.3 Exceptions Exceptions occur (are raised) when an abnormal condition occurs during execution. There are fewer than eight possible exceptions on machines running in real mode. Protected mode execution provides many others but we will not consider those here we will only consider those exceptions interesting to those working in real mode[4]. Although exception handlers are user defined the 80x86 hardware defines the exceptions that can occur. The 80x86 also assigns a fixed interrupt number to each of the exceptions. The following sections describe each of these exceptions in detail. In general an exception handler should preserve all registers. However there are several special cases where you may want to tweak a register value before returning. For example if you get a bounds violation you may want to modify the value in the register specified by the bound instruction before returning. Nevertheless you should not arbitrarily modify registers in an exception handling routine unless you intend to immediately abort the execution of your program. 17.3.1 Divide Error Exception (INT 0) This exception occurs whenever you attempt to divide a value by zero or the quotient does not fit in the destination register when using the div or idiv instructions. Note that the FPU's fdiv and fdivr instructions do not raise this exception. MS-DOS provides a generic divide exception handler that prints a message like "divide error" and returns control to MS-DOS. If you want to handle division errors yourself you must write your own exception handler and patch the address of this routine into location 0:0. On 8086 8088 80186 and 80188 processors the return address on the stack points at the next instruction after the divide instruction. On the 80286 and later processors the return address points at the beginning of the divide instruction (include any prefix bytes that appear). When a divide exception occurs the 80x86 registers are unmodified; that is they contain the values they held when the 80x86 first executed the div or idiv instruction. When a divide exception occurs there are three reasonable things you can attempt: abort the program (the easy way out) jump to a section of code that attempts to continue program executi

 

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