Postgres Relation Does Not Exist Error Code
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Netezza Error [42s02] Error: Relation Does Not Exist
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programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Cannot simply use PostgreSQL table name (“relation does not exist”) up vote 63 down vote favorite 15 I'm trying to run the following PHP script to do a simple database query: $db_host = "localhost"; $db_name = "showfinder"; $username = error relation does not exist hibernate "user"; $password = "password"; $dbconn = pg_connect("host=$db_host dbname=$db_name user=$username password=$password") or die('Could not connect: ' . pg_last_error()); $query = 'SELECT * FROM sf_bands LIMIT 10'; $result = pg_query($query) or die('Query failed: ' . pg_last_error()); This produces the following error: Query failed: ERROR: relation "sf_bands" does not exist In all the examples I can find where someone gets an error stating the relation does not exist, it's because they use uppercase letters in their table name. My table name does not have uppercase letters. Is there a way to query my table without including the database name, i.e. showfinder.sf_bands? php sql database postgresql share|improve this question edited Apr 29 '12 at 17:12 Ben 33k216499 asked Mar 29 '09 at 20:16 Keyslinger 1,22322446 1 Are you sure that the sf_bands table exists? Does showfinder.sf_bands work? –brian-brazil Mar 29 '09 at 20:26 showfinder.sf_bands works perfectly –Keyslinger Mar 29 '09 at 20:37 Perhaps I should note that my database was migrated from MySQL
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Relation Does Not Exist Postgres Java
about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered sql state: 42p01 Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and postgres relation does not exist grant learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Error http://stackoverflow.com/questions/695289/cannot-simply-use-postgresql-table-name-relation-does-not-exist 42P01: relation does not exist up vote 3 down vote favorite 1 I'm new at creating databases, and this error has me dumbfounded, as I am super new with DB admin things (I mostly do reporting type queries). I created a new database through pgAdmin3 GUI, and I'm trying to create DB objects in there using SQL but am getting a: ERROR: relation "replays" does not exist SQL state: 42P01 I looked through the manual but did not http://dba.stackexchange.com/questions/101570/error-42p01-relation-does-not-exist find anything very helpful, though I suspect it may have to do with search_path somehow. Here is a screenshot. Any idea what I'm doing wrong please? postgresql schema pgadmin share|improve this question asked May 15 '15 at 1:44 Phrancis 938317 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted +250 What you had originally was a correct syntax - for tables, not for schemas. As you did not have a table (dubbed 'relation' in the error message), it threw the not-found error. I see you've already noticed this - I believe there is no better way of learning than to fix our own mistakes ;) But there is something more. What you are doing above is too much on one hand, and not enough on the other. Running the script, you create a schema create a role grant SELECT on all tables in the schema created in (1.) to this new role_ and, finally, grant all privileges (CREATE and USAGE) on the new schema to the new role The problem lies within point (3.) You granted privileges on tables in replays - but there are no tables in there! There might be some in the future, but at this point the schema is completely empty. This way, the GRANT in (3.) does nothing - this way you are doing too much. But what about the future
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$db_name = "showfinder";
$username = "user";
$password = "password";
$dbconn = pg_connect("host=$db_host dbname=$db_name user=$username password=$password")
or die('Could not connect: ' . pg_last_error());
$query = 'SELECT * FROM sf_bands LIMIT 10';
$result = pg_query($query) or die('Query failed: ' . pg_last_error());
This produces the following error: Query failed: ERROR: relation "sf_bands" does not exist In all the examples I can find where someone gets an error stating the relation does not exist, it's because they use uppercase letters in their table name. My table name does not have uppercase letters. Is there a way to query my table without including the database name, i.e. showfinder.sf_bands? Bill Karwin Answer Email {} Share From what I've read, this error means that you're not referencing the table name correctly. One common reason is that the table is defined with a mixed-case spelling, and you're trying to query it with all lower-case. In other words, the following fails: CREATE TABLE "SF_Bands" ( ... ); SELECT * FROM sf_bands; -- ERROR! Use double-quotes to delimit identifiers so you can use the specific mixed-case spelling as the table is defined. SELECT * FROM "SF_Bands"; Re your comment, you can add a schema to the "search_path" so that when you reference a table name without qualifying its schema, the query will match that table name by checked each schema in order. Just like PATH in the shell or include_path in PHP, etc. You can check your current schema search path: SHOW search_path "$user",public You can change your schema search path: SET search_path TO showfinder,public; See also http://www.postgresql.org/docs/8.3/static/ddl-schemas.html Source (Stackoverflow) http://stackoverflow.com/questions/695289/cannot-simply-use-postgresql-table-name-relation-does-not-exist Comments Please enable JavaScript to view the comments powered by Dis