Error Duplicate Case Value In Switch

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Arduino Duplicate Case Value

Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 duplicate case label million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up switch statement duplicate error up vote -1 down vote favorite #include int main() { int a=5; switch(a) { case 1: ; case 2:; case 3+5:; case a:; } } Compiling this program, I get two errors: constant expression is required which is ok and expected. the second error says that duplicate case. Here case a: is duplicate with case 1:. Why second error is produced error? In a there is value of 5 and in case 1 it is 1. How 5 and 1 can conflict. c switch-statement share|improve this question edited Feb 26 '14 at 12:32 asked Feb 26 '14 at 12:16 user3335653 516 What do you want to achieve with: switch( a ) /* ... */ case a /* ... */ ? –Kiril Kirov Feb 26 '14 at 12:19 Not reproducable. –alk Feb 26 '14 at 12:23 1 with g++ I am getting second error error: expected ‘:’ before ‘;’ token , which compiler you are using ? –EmptyData Feb 26 '14 at 12:23 A case statments argument needs to be constant, so at least case a: is illegal. –alk Feb 26 '14 at 12:23 The second warning appears because your compiler is free to diagnose what it wants--especially for syntactically invalid input. –Jens Feb 26 '14 at 12:24 | show 1 more comment 5 Answers 5 active oldest votes up vote 2 down vote When a compiler encounters an error, it attempts to recover, and continue. This means that it tries to change the code to something it thinks was meant (or nothing at all) and just continue right after the erronous piece of code. Generally speaking, only the first compiler error is 100% correct, the following ones might just be "collateral damage" and have no real meaning at all. share|improve this answer answered Feb

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#include int main() { bool loop; loop = 1; bool looptwo; looptwo = 1; double box; box = 0; char action; char actionA; char actionC; do{ std::cout << "\n You awake in a dark cave. All you can see http://stackoverflow.com/questions/22041092/switch-statement-duplicate-error is a small fire in the distance.\n What would you like to do?\n"; std::cout << "\n[A] Walk to the fire.\n"; std::cout << "\n[B] Run to the fire.\n"; std::cout << "\n[C] Stay where you are. You are comfy, after all.\n"; std::cout << "\n[D] http://www.cplusplus.com/forum/beginner/101401/ POOP YOURSELF. WHAT IS GOING ON?\n"; std::cout << "\n\n\n (Tip) for any choice, press 'o' to start from scratch!\n"; std::cin >> action; switch (action) { case 'a': loop = 0; std::cout << "\n You carefully approach the fire. Your vision remains dark and dull, but not for long. Slowly, you can see more clearly. By the fire you notice that there is a small box.\n"; if ( box == 2 ) {std::cout << "\n During your examination of the box, you start to hear a grumbling coming from the box. It starts shaking in your hands, to the point of your hands going numb.\n In your increasing panic, you...\n";} std::cout << "\n What would you like to do?\n"; std::cout << "\n[A] Examine the b

Programming Boards C++ Programming 'Duplicate case value' error with chars. Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes http://cboard.cprogramming.com/cplusplus-programming/65991-duplicate-case-value-error-chars.html for common problems Thread: 'Duplicate case value' error with chars. Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 05-28-2005 #1 Mr Newbie View Profile View Forum Posts Perma-Newbie Join Date Feb 2005 Posts 7 'Duplicate case value' error with chars. I want to give a variable a value according to the value of a char within a string. For example, duplicate case if (in[12] == z) y = 8; So what I've done is assign some const chars, and I'm using a switch... case to assign the values. I keep getting 'duplicate case value' errors from the line with "case (V): y = 5; break;" onwards, and my compiler tells me that the case value was previously used in the previous line. What am I doing wrong? Code: //... const char I = ('i'||'I'); const char duplicate case value V = ('v'||'V'); const char X = ('x'||'X'); const char L = ('l'||'L'); const char C = ('c'||'C'); const char M = ('m'||'M'); const char operators = ('/'||'*'||'+'||'-'); //... for (i = 0, x = 0; i < 256, in[i] != '\0'; i++) { if (in[i] != operators) { switch (in[i]) { case (I): y = 1; break; case (V): y = 5; break; case (X): y = 10; break; case (L): y = 50; break; case (C): y = 100; break; case (M): y = 1000; break; default: cout<<"Oh ......... Something's gone wrong."; break;} /* code to do something with y before the cycle starts again and it's changed */ } Yes, it's a roman numeral calculator . Last edited by Mr Newbie; 05-28-2005 at 10:36 AM. 05-28-2005 #2 Salem View Profile View Forum Posts and the hat of int overfl Join Date Aug 2001 Location The edge of the known universe Posts 34,467 > const char I = ('i'||'I'); This isn't what you think it is. In particular, it isn't a value which specifically matches two cases of the same letter. By the time you've done the same trick to several letters, you have duplicate values. Scrap all the const chars, and do this Code: switch ( toupper(in[i]) ) { case 'I': y = 1; break; case 'V': y