Errno 150 Mysql Error 1005
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Mysql Error 1005 Hy000 Can T Create Table Errno 150
hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss sql error 1005 errno 150 Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQL Foreign Key Error mysql error 1005 can't create table 1005 errno 150 up vote 31 down vote favorite 8 I'm doing a small DataBase with MySQL Workbench. I have a main table, called "Immobili", which has a Primary Key composed by four columns: (Comune, Via, Civico, Immobile). Now, I also have three other tables, wich have the same primary key (Comune, Via, Civico, Immobile), but these fields are also referenced to the table Immobili.
Mysql Error 1005 Errno 121
First question: Can I make a Primary Key that is also a Foreign Key? Second Question: When I try to export the changes it says: Executing SQL script in server # ERROR: Error 1005: Can't create table 'dbimmobili.condoni' (errno: 150) CREATE TABLE IF NOT EXISTS `dbimmobili`.`Condoni` ( `ComuneImmobile` VARCHAR(50) NOT NULL , `ViaImmobile` VARCHAR(50) NOT NULL , `CivicoImmobile` VARCHAR(5) NOT NULL , `InternoImmobile` VARCHAR(3) NOT NULL , `ProtocolloNumero` VARCHAR(15) NULL , `DataRichiestaSanatoria` DATE NULL , `DataSanatoria` DATE NULL , `SullePartiEsclusive` TINYINT(1) NULL , `SullePartiComuni` TINYINT(1) NULL , `OblazioneInEuro` DOUBLE NULL , `TecnicoOblazione` VARCHAR(45) NULL , `TelefonoTecnico` VARCHAR(15) NULL , INDEX `ComuneImmobile` (`ComuneImmobile` ASC) , INDEX `ViaImmobile` (`ViaImmobile` ASC) , INDEX `CivicoImmobile` (`CivicoImmobile` ASC) , INDEX `InternoImmobile` (`InternoImmobile` ASC) , PRIMARY KEY (`ComuneImmobile`, `ViaImmobile`, `CivicoImmobile`, `InternoImmobile`) , CONSTRAINT `ComuneImmobile` FOREIGN KEY (`ComuneImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ComuneImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `ViaImmobile` FOREIGN KEY (`ViaImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ViaImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `CivicoImmobile` FOREIGN KEY (`CivicoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`CivicoImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `InternoImmobile` FOREIGN KEY (`InternoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`InternoImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE =
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Error 1005 Access Denied
Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: http://stackoverflow.com/questions/4063141/mysql-foreign-key-error-1005-errno-150 Sign up MySQL error 1005 errno 150 Foreign key constraint is incorrectly formed up vote 0 down vote favorite I have created the following tables: Stops: CREATE TABLE Stop ( routeNo DECIMAL (4,0) UNSIGNED, stopNo DECIMAL(3,0) UNSIGNED, latitude DECIMAL(19,16), longitude DECIMAL(19,16), CONSTRAINT PK_Location PRIMARY KEY (routeNo, stopNo), CONSTRAINT FK_stop_location FOREIGN KEY (latitude,longitude) REFERENCES Location(latitude,longitude), CONSTRAINT FK_stop_route FOREIGN KEY (routeNo) REFERENCES Route(routeNo) ); http://stackoverflow.com/questions/34074739/mysql-error-1005-errno-150-foreign-key-constraint-is-incorrectly-formed And the table WorkDay: CREATE TABLE Workday ( theDate DATE PRIMARY KEY, notes VARCHAR(30) ); I then try to create the table Order Delivery with the following code: CREATE TABLE OrderDelivery ( routeNo DECIMAL(4,0) UNSIGNED, stopNO DECIMAL(3,0) UNSIGNED, orderNo INT(9), CONSTRAINT pk_Orders PRIMARY KEY (routeNo, stopNo, orderNo), deliveryDateExpected DATE, deliveryTime TIME, customerName VARCHAR(40), creditCardNo CHAR(16) NOT NULL, customerRanking ENUM('platinum','gold','occasional','one-off'), CONSTRAINT fk_Routes FOREIGN KEY (routeNo) REFERENCES Stop(routeNo), CONSTRAINT fk_Stops FOREIGN KEY (stopNo) REFERENCES Stop(stopNo), CONSTRAINT fk_Dates FOREIGN KEY (deliveryDateExpected) REFERENCES Workday(theDate) ); However every time i try to create the OrderDelivery table it gives the error that the foreign key is incorrectly formed "SQL Error (1005): Can't create table 'harry.OrderDelivery' (errno:150)Foreign key constraint is incorrectly formed" How can i rectify this? mysql share|improve this question asked Dec 3 '15 at 19:40 HarAdams 92 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote You can't create a foreign key to a table with a multiple primary key referencing only one field of that primary key. So your problem lies here: CONSTRAINT fk_Routes FOREIGN KEY (routeNo) REFERENCES Stop(routeNo), CONSTRAINT fk_Stops FOREIGN
log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow http://dba.stackexchange.com/questions/62114/create-table-shows-error-1005hy000-errno-150 the company Business Learn more about hiring developers or posting ads with us Database Administrators https://mariadb.org/mariadb-innodb-foreign-key-constraint-errors/ Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best error 1005 answers are voted up and rise to the top Create table shows ERROR 1005(HY000) errno 150 up vote 0 down vote favorite i tried to create tables as per given in my textbook in MySQL server as follows: create table department (dept_name varchar(20), building varchar(15), budget numeric(12,2), primary key (dept_name) ); create table course (course_id varchar(8), title varchar(50), dept_name varchar(20), credits numeric(2,0), primary key (course_id), foreign key (dept_name) references department ); the department table sql error 1005 gets created, but an error ERROR 1005 (HY000): Can't create table 'test.course' (errno: 150) is displayed. The queries seem very simple. And i am unable to find any mistake. What can be the possible error that is preventing me to create the table? mysql foreign-key share|improve this question asked Mar 31 '14 at 5:29 Amita 312 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote accepted You are missing column name of parent table to which your child refer, while creating child table, do like below create table department (dept_name varchar(20), building varchar(15), budget numeric(12,2), primary key (dept_name) ); create table course (course_id varchar(8), title varchar(50), dept_name varchar(20), credits numeric(2,0), primary key (course_id), foreign key (dept_name) references department(dept_name) ); share|improve this answer answered Mar 31 '14 at 5:32 Abdul Manaf 4,73563864 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged mysql foreign-key or ask your own question. asked 2 years ago viewed 3686 times active 11
for Developers MariaDB Contributor Agreement MariaDB Contributor Agreement FAQs Community Ambassadors Events Past Events and Conferences Sponsor Sponsors List of Donors Blog About MariaDB Sponsors Governance Logos and Badges MariaDB Trademark Usage Statistics Service Providers Maintenance Policy Security Policy Download Learn Get Involved Social Media Getting Started for Developers MariaDB Contributor Agreement MariaDB Contributor Agreement FAQs Community Ambassadors Events Past Events and Conferences Sponsor Sponsors List of Donors Blog HomeGeneralMariaDB: InnoDB foreign key constraint errors MariaDB: InnoDB foreign key constraint errors 2015-08-07 4 Comments Written by Jan Lindstrom Introduction A foreign key is a field (or collection of fields) in one table that uniquely identifies a row of another table. The table containing the foreign key is called the child table, and the table containing the candidate key is called the referenced or parent table. The purpose of the foreign key is to identify a particular row of the referenced table. Therefore, it is required that the foreign key is equal to the candidate key in some row of the primary table, or else have no value (the NULL value). This is called a referential integrity constraint between the two tables. Because violations of these constraints can be the source of many database problems, most database management systems provide mechanisms to ensure that every non-null foreign key corresponds to a row of the referenced table. Consider following simple example: create table parent ( id int not null primary key, name char(80) ) engine=innodb; create table child ( id int not null, name char(80), parent_id int, foreign key(parent_id) references parent(id) ) engine=innodb; As far as I know, the following storage engines for MariaDB and/or MySQL support foreign keys: