Error 1005 Mysql Errno 150
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Error 1005 (hy000) Errno 150
MySQL Foreign Key Error 1005 errno 150 up vote 31 down vote favorite 8 I'm doing a small DataBase with MySQL Workbench. I have a main table, called "Immobili", which has a Primary Key composed by four columns: (Comune, Via, Civico, Immobile). Now, I also have three other tables, wich have the same primary key (Comune, Via, Civico, Immobile), but these fields are also mysql error 1005 can't create table referenced to the table Immobili. First question: Can I make a Primary Key that is also a Foreign Key? Second Question: When I try to export the changes it says: Executing SQL script in server # ERROR: Error 1005: Can't create table 'dbimmobili.condoni' (errno: 150) CREATE TABLE IF NOT EXISTS `dbimmobili`.`Condoni` ( `ComuneImmobile` VARCHAR(50) NOT NULL , `ViaImmobile` VARCHAR(50) NOT NULL , `CivicoImmobile` VARCHAR(5) NOT NULL , `InternoImmobile` VARCHAR(3) NOT NULL , `ProtocolloNumero` VARCHAR(15) NULL , `DataRichiestaSanatoria` DATE NULL , `DataSanatoria` DATE NULL , `SullePartiEsclusive` TINYINT(1) NULL , `SullePartiComuni` TINYINT(1) NULL , `OblazioneInEuro` DOUBLE NULL , `TecnicoOblazione` VARCHAR(45) NULL , `TelefonoTecnico` VARCHAR(15) NULL , INDEX `ComuneImmobile` (`ComuneImmobile` ASC) , INDEX `ViaImmobile` (`ViaImmobile` ASC) , INDEX `CivicoImmobile` (`CivicoImmobile` ASC) , INDEX `InternoImmobile` (`InternoImmobile` ASC) , PRIMARY KEY (`ComuneImmobile`, `ViaImmobile`, `CivicoImmobile`, `InternoImmobile`) , CONSTRAINT `ComuneImmobile` FOREIGN KEY (`ComuneImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ComuneImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `ViaImmobile` FOREIGN KEY (`ViaImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ViaImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `CivicoImmobile` FOREIGN KEY (`CivicoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`CivicoImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `InternoImmobile` FOREIGN KEY (`InternoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`InternoImmobi
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posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of http://stackoverflow.com/questions/4063141/mysql-foreign-key-error-1005-errno-150 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQL ERROR 1005: Can't create table (errno: 150) up vote 6 down vote favorite I am trying to create the following table create table messaInScena ( data date, ora time, spazio varchar(20), spettacolo varchar(40), postiDisponibili smallint, prezzoIntero http://stackoverflow.com/questions/17812616/mysql-error-1005-cant-create-table-errno-150 decimal(5,2), prezzoRidotto decimal(5,2), prezzoStudenti decimal(5,2), primary key (data, ora, spazio), foreign key (spazio) references spazio(nome) on update cascade on delete set null, foreign key (spettacolo) references spettacolo(titolo) on update cascade on delete set null, constraint RA3_1 check (postiDisponibili >= 0) ) ; but I get the following error: Error Code: 1005 Can not create table 'teatrosql.messainscena' (errno: 150) The tables that are referenced by foreign keys are: create table spazio ( nome varchar(20) primary key, indirizzo varchar(40) not null, pianta varchar(20), capienza smallint ); create table spettacolo ( titolo varchar(40) primary key, descrizione LONGBLOB, annoProduzione char(4) ); I have already verified that the fk are unique and that there are no typos (but given a control also you that you never know :D). As you can see the reference fields are primary keys. between fields and fk reference types and dimensions coincide .. where am I wrong?? the the other tables of DB create table teatro ( nome varchar(20) primary ke
Communication Skills Training Interpersonal Skills Training Blog About Blog Troy Fawkes / Archives / Solved: MySQL ERROR 1005: Can't create table (errno: 150) (Foreign Key) Nov 27 Solved: MySQL ERROR 1005: Can't create table (errno: 150) https://www.troyfawkes.com/solved-mysql-error-1005-cant-create-table-errno-150/ (Foreign Key) November 27, 2011 Troy Fawkes 8 Comments Archives Share on Facebook Share 0 Share on TwitterTweet 0 Share on Google Plus Share 0 Share on Pinterest Share 0 Share on LinkedIn Share 0 This is another stupid error. It has to do with trying to successfully set foreign keys in MySQL. ERROR 1005: Can't create table (errno: 150) Great, that's fantastic. Here's an example of where this error 1005 error will occur. CREATE TABLE main(
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id)
);
CREATE TABLE other(
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
main_id INT NOT NULL,
PRIMARY KEY(id),
FOREIGN KEY(main_id) REFERENCES main(id)
); So I'm trying to make the table "other" reference the table "main" through the foreign key "main_id" and, if you try it, it'll throw an Error 150. Want the solution? The foreign key "main_id" sql error 1005 has to have the exact same type as the primary key that it references. In the example, "main_id" in the table "other" has the type INT NOT NULL while "id" in the table "main" has the type "INT UNSIGNED NOT NULL" and also AUTO_INCREMENT, but that isn't something we have to worry about. To make things incredibly clear, here's the working example. CREATE TABLE main( id INT UNSIGNED NOT NULL AUTO_INCREMENT, PRIMARY KEY(id) ); CREATE TABLE other( id INT UNSIGNED NOT NULL AUTO_INCREMENT, main_id INT UNSIGNED NOT NULL, PRIMARY KEY(id), FOREIGN KEY(main_id) REFERENCES main(id) ); To solve ‘MySQL ERROR 1005: Can't create table (errno: 150)‘ you likely just have to ensure that your foreign key has the exact same type as the primary key. Hope it helps. Share on Facebook Share 0 Share on TwitterTweet 0 Share on Google Plus Share 0 Share on Pinterest Share 0 Share on LinkedIn Share 0 Facebook Twitter Tumblr Pinterest Google+ LinkedIn E-Mail About The Author My name is Troy Boileau but I go by Troy Fawkes. I'm a digital marketer working in Toronto. On top of that, my passions include social skills, networking and dating; subjects that I've been semi-professionally involved with for almost five years. Top