Error 1064 In Mysql Syntax
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x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error http://www.inmotionhosting.com/support/website/database-troubleshooting/error-1064 Code: 1064 in mysql up vote 4 down vote favorite I created a procedure that is supposed to do some operation but every time I call it, mysql comes out with an error, which I have not clue what it means. I have tried to understand it in vain, here 's the table structure which the stored procedure where made to do an http://stackoverflow.com/questions/7926082/error-code-1064-in-mysql operation on it: CREATE TABLE `recruitment`.`job_seeker` ( `user_id` INT Null , `fname` VARCHAR(45) Null , `lname` VARCHAR(45) Null , `mname` VARCHAR(45) Null , `gender` VARCHAR(10) Null , `dob` DATE Null , `marital_status` VARCHAR(45) Null , `address` VARCHAR(45) Null , `city` VARCHAR(45) Null , `nationality` VARCHAR(45) Null , `phone` VARCHAR(45) Null , `mobile` VARCHAR(45) Null , `degree_id` INT Null , `education` VARCHAR(100) Null , `experience` VARCHAR(250) Null , `other` VARCHAR(250) Null , `job_target` VARCHAR(250) Null , PRIMARY KEY (`user_id`) , INDEX `user_id` (`user_id` ASC) , INDEX `degree_id` (`degree_id` ASC) , CONSTRAINT `user_id` FOREIGN KEY (`user_id` ) REFERENCES `recruitment`.`user_authentication` (`user_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `degree_id` FOREIGN KEY (`degree_id` ) REFERENCES `recruitment`.`degree` (`degree_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION ); Here's the stored procedure: DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `createSeekerProfile`(in userName varchar(45), in fn varchar(45),in mn varchar(45), in ln varchar(45), in gender varchar(6),in nationality varchar(45), in ad varchar(45),in city varchar(45),in phone varchar(15),in mob varchar(15), in maritalStatus varchar(45), in degId int, in educ varchar(100), in exper varchar(250), in other varchar(250), in dob date,in jtarg varchar(250)) begin declare returned_ID int; set @dyn_que = CONCAT('select user_id
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/30068603/mysql-error-1064-sql-syntax-error-in-select-statement Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the http://w3schools.invisionzone.com/index.php?showtopic=41524 Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQL error 1064: SQL syntax error error 1064 in SELECT statement up vote -1 down vote favorite I am relatively new to somewhat advanced MySQL querying. I had been trying to query the most recent order in an order table of a particular user using MySQL SELECT statement using the following MySQL query. SELECT o1.* FROM order AS o1 WHERE o1.orderDateTime = ( SELECT MAX(o2.orderDateTime) FROM order AS o2 WHERE o2.userId = '1' ) But error 1064 mysql I had been constantly getting the following MySQL error #1064 related to MySQL syntax. #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order AS o1 WHERE o1.orderDateTime = (SELECT MAX(o2.orderDateTime)FROM order AS ' at line 1 I got similar errors in relation with INSERT statements but I managed to fix it up using the methods specified in MySQL 1064: You have an error in your SQL syntax I made every effort to fix the query in the current case but I was still unsuccessful. I would be grateful to you if someone can help me out with fixing this MySQL syntax error for SELECT clause specified above. It would be great if someone could specify me the exact reason for the occurrence of this issue, as well. php mysql share|improve this question edited May 6 '15 at 5:55 Hanky Panky 36.9k83264 asked May 6 '15 at 5:53 Chiranga Alwis 171113 2 order is reserved word use bacticks to escape –M Khalid Junaid May 6 '15 at 5:54 add a comment| 3 Answers 3 active oldest votes up
Detected You currently have javascript disabled. Several functions may not work. Please re-enable javascript to access full functionality. SQL error #1064 Started by Stromgren, Jan 19 2012 04:52 PM Please log in to reply 4 replies to this topic #1 Stromgren Stromgren Newbie Members 21 posts Posted 19 January 2012 - 04:52 PM Hello I have a problem with a query i just created. When i run it, it returns this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"INSERT INTO user (username, password, join_date, virksomhed, email, vej, postnu' at line 1 "INSERT INTO user (username, password, join_date, virksomhed, email, vej, postnummer, by, telefon) VALUES ('$username', SHA('$password1'), NOW(), '$virksomhed', '$email', '$vej', '$postnummer', '$by', '$telefon')" Can anyone please help me? Thanks in advance Back to top #2 justsomeguy justsomeguy More Human Than Human Moderator 29,451 posts Gender:Male Location:Phoenix Languages:Focusing on PHP and JavaScript Posted 19 January 2012 - 06:41 PM The double quote should not be part of the SQL query. SQL also does not understand PHP variables. Know your history: Babbage | Lovelace | Turing | Hopper | RitchieConTEXT Sublime Text Opera PHP MySQL phpMyAdminUse a debugger: Firefox, IE, Chrome, Safari, or OperaKnow the foundations of computer science: algorithms, machine architectures, data structures, etc. Don't just blindly copy techniques from application to application. Know what you are doing, that it works, and why it works. Don't think you know what the industry will be in five years time or what you'll be doing then, so gather a portfolio of general and useful skills. Try to write better, more principled code. Work to make "programming" more of a professional activity and less of a low-level "hacking" activity (programming is also a craft, but not just a craft). Learn from the classics in the field and the better advanced textbooks; don't be satisfied with the easily digested "how to" guides and online documentation - it's shallow.-- Bjarne StroustrupHe that te