Error Code 1075
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Vmware Authorization Service Error 1075
identify any member (WHERE memberid='abcde'). My question is: how to keep auto_increment, but make memberid as a primary key? Is that possible? When I try to create this table with PRIMARY KEY (memberid), I get an error: 1075 - Incorrect table definition; there can be only one auto column and it must be defined as a key What is the best choice (Hopefully, there is a way to keep id column so performance is good and queries identify any user by memberid, not by id), if the performance is very important (although the disk space is not)? mysql primary-key auto-increment mysql-error-1075 share|improve this question edited Nov 13 '11 at 20:45 OMG Ponies 198k36356415 asked Nov 13 '11 at 20:35 Haradzieniec 3,1921257134 add a comment| 3 Answers 3 active oldest votes up vote 26 down vote accepted You can have an auto-Incrementing column that is not the PRIMARY KEY, as long as there is an index (key) on it: CREATE TABLE members ( id int(11) UNSIGNED NOT NULL AUTO_INCREMENT, memberid VARCHAR( 30 ) NOT NULL , `time` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP , firstname VARCHAR( 50 ) NULL , lastname VARCHAR( 50 ) NULL , PRIMARY KEY (memberid) , KEY (id) --- or: UNIQUE KEY (id) ) ENGINE = MYISAM; share|improve this answer answered Nov 13 '11 at 21:44 ypercubeᵀᴹ 77.9k790159 +1 and thanks for the comment, learned something today
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Updates: Status: Closed Impact on me: None Category:MySQL Server: Documentation Severity:S3 (Non-critical) Version:5.1.36-community OS:Microsoft Windows (XP Pro) Assigned to: Paul Dubois Tags: 1075, 42000, auto_increment, error, reference Triage: Needs Triage: D4 (Minor) View Add Comment Files Developer Edit Submission View Progress Log Contributions [7 Jul 2009 4:15] Ender Li Description: In http://dev.mysql.com/doc/refman/5.1/en/example-auto-increment.html, there is a sample code : CREATE TABLE animals ( grp ENUM('fish','mammal','bird') NOT NULL, id MEDIUMINT NOT NULL AUTO_INCREMENT, name CHAR(30) NOT NULL, PRIMARY KEY (grp,id) ); INSERT INTO animals (grp,name) VALUES ('mammal','dog'),('mammal','cat'), ('bird','penguin'),('fish','lax'),('mammal','whale'), ('bird','ostrich'); SELECT * FROM animals ORDER BY grp,id; When I try to "CREATE TABLE animals", I get "ERROR 1075 (42000): Incorrect table definition; there can be only one auto column and it must be def ined as a key". How to repeat: mysql> use test Database changed mysql> show tables; +----------------+ | Tables_in_test | +----------------+ | 321321 | | person | | shirt | | shop | | t1 | +----------------+ 5 rows in set (0.13 sec) mysql> CREATE TABLE animals ( -> grp ENUM('fish','mammal','bird') NOT NULL, -> id MEDIUMINT NOT NULL AUTO_INCREMENT, -> name CHAR(30) NOT NULL, -> PRIMARY KEY (grp,id) -> ); ERROR 1075 (42000): Incorrect table definition; there can be only one auto column and it must be def ined as a key mysql> Suggested fix: Maybe Server error, maybe docs error... Please just fix or modify one of them. [7 Jul 2009 5:48] Valerii Kravchuk Thank you for the problem report. Actually, this is not a server bug, just a difference between MyISAM (assumed as default by that manual page) and InnoDB storage engine documented elsewhere (http://dev.mysql.com/doc/refman/5.1/en/innodb-auto-increment-handling.html). You (and me) have InnoDB as a default storage engine instead. Look: mysql> CREATE TABLE animals ( -> grp ENUM('fish','mammal','bird') NOT NULL, -> id MEDIUMINT NOT NULL AUT