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Error 2015 Visual Basic

Join them; it only takes a minute: Sign up Excel VBA find string : Error 2015 up vote 1 down vote favorite I have to following code snippet ... Public Sub FindText(path As String, file As String) Dim

Excel Vba Error 2015 Evaluate

Found As Range myText = "test(" MacroBook = ActiveWorkbook.Name ' Open the File Workbooks.Open path & file, ReadOnly:=True, UpdateLinks:=False For Each ws In Workbooks(file).Worksheets With ws Set Found = .UsedRange.Find(What:=myText, LookIn:=xlFormulas, _ LookAt:=xlPart, MatchCase:=False) If Not Found Is Nothing Then ' do stuff ' ... I see in the debugger that Found contains Error 2015! The sheet contains the text I want in the formula. Any ideas why I'm getting the error? Thanks excel vba excel-vba find share|improve quicktime error 2015 this question edited Feb 25 '14 at 13:15 asked Feb 25 '14 at 12:22 Rueful Rabbit 3127 1 it's because your formula in the sheet returns #VALUE! error. You can handle it using IsError: If Not IsError(Found) Then –simoco Feb 25 '14 at 12:36 is this a sub or function? please, show complete code. –KazimierzJawor Feb 25 '14 at 12:43 1 Bravo Simoco, nice catch! –Rueful Rabbit Feb 25 '14 at 13:21 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted As follow up from comments to the Q, Error 2015 occurs because your formula in the sheet returns #VALUE! error. You can handle it using IsError: If Not Found Is Nothing Then If Not IsError(Found) Then ' do sth End If End If share|improve this answer edited Feb 25 '14 at 16:41 answered Feb 25 '14 at 13:41 simoco 27.5k93552 is there a way of finding which formula is giving the error? –user3540466 Dec 30 '15 at 16:30 add a comment| up vote 0 down vote You don't need to use 'Set' in your code. You only use this to assign a reference to an object. Try:- For Each ws In Workbooks(file).Worksheets With ws Found = .UsedRange.Find(What:=myText, LookIn:=xlFormulas, _ LookAt:=xlPart, MatchCase:=False) If Not Found Is Nothing Then ' do stuff ' ... Hopefully this should work. share|improve this a

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hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask error 2020 Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. error 2010 Join them; it only takes a minute: Sign up Excel VBA - Array Formula returns #VALUE! (Error 2015) in case a cell contains more than 255 characters up vote 2 down vote favorite 1 Dear all I am using http://stackoverflow.com/questions/22014093/excel-vba-find-string-error-2015 an array formula and pass the result to a VBA macro, which means the result of the formula is passed as array to my macro. In some cases I get in the array a #VALUE (error 2015) and I have no clue why. When I play arround with the affected cell where it gets the data from then it is happening when the cell has quite an amount of characters (~3000 chars). Has anyone a clue what I can http://stackoverflow.com/questions/35436777/excel-vba-array-formula-returns-value-error-2015-in-case-a-cell-contains-m try to solve the isuse? formula: {=arrayToCSV(removeElementsFrom2DimArray(IF('sheet'!$G$1:$G$2000=A1;'sheet'!$F$1:$F$2000)))} the IF('sheet'!$G$1:$G$2000=A1;'sheet'!$F$1:$F$2000) part returns an array like {FALSE, FALSE, FALSE... Value, Value, FALSE , ...}. This one I pass to my mVBA function removeElementsFrom2DimArray to remove the FALSE elements Now it seems that the IF('sheet'!$G$1:$G$2000=A1;'sheet'!$F$1:$F$2000) return in some cases #VALUE(Error 2015) for some of the elements i.e. {FALSE, FALSE, FALSE... #VALUE!, Value, FALSE , ...} Function removeElementsFrom2DimArray(ByRef arr() As Variant, Optional value As Variant = False) As String() On Error GoTo ErrorHandler Dim coll As New Collection Dim i As Integer If (IsArray(arr)) Then For i = 1 To UBound(arr, 1) If (arr(i, 1) <> value) Then --> Here happens the error that arr(i, 1) return #VALUE! Error 2015. Why? coll.Add (arr(i, 1)) End If Next i End If removeElementsFrom2DimArray = collectionToArray(coll) Exit Function ErrorHandler: MsgBox Err.Description Resume End Function UPDATES: I tried to modify to pass over arr as Variant or ByVal. It did not made any difference. I tried to modify to pass over arr as array arr() with and without the (). It did not made any difference. If I reduce the number of chars in the affected cell 'sheet'!$F$1:$F$2000 to below 256 chars then it works! If I use just the formula {=IF(sheet!$G$1:$G$2000=A1;sheet!$F$1:$F$2000)} (array formula) then it works too! so I assume there is a limitation in passing arrays from native formulas to own functions? So that values in the array wit

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