Error 2023 Excel

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Runtime Error 2023

Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges excel error codes Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: error 2023 rift Sign up Type Mismatch Error Excel VBA - Looping through each column of Used Range up vote 1 down vote favorite I have an excel spreadsheet with a title row at the top. I am trying to log the column number of each cell in the top row of my excel spreadsheet (title row) that matches a certain string such as "Recommended

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Action 1" For Each c In Worksheets("Cost Estimates").Range(Cells(1, 1), Cells(totalRows, totalCols)) If c.Value = "Recommended Action 1" Then recAct1 = c.Column Debug.Print CStr(recAct1) ElseIf c.Value = "Recommended Action 2" Then recAct2 = c.Column ElseIf c.Value = "Recommended Action 3" Then recAct3 = c.Column End If Next Where recAct holds the column number and totalRows and totalCols are the total number of rows and columns (respectively on the spreadsheet). I keep receiving a 'Type Mismatch' error for: If c.Value = "Recommended Action 1" Then I put my cursor over the c value during this error and I get an 'Error 2023' message. I suspected that it was because c was a column number and not an actual range address. I think this error is caused by the fact that I do not know what type of variable 'c' is actually returning -- I thought it was a range object. excel vba excel-vba share|improve this question edited Feb 24 '15 at 19:21 pnuts 33.7k63569 asked Oct 15 '13 at 18:02 H3lue 37641021 Are you trying to find out which column in row 1

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of error 2023 archeage this site About Us Learn more about Stack Overflow the company Business Learn error 2023 fnis more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question

Error 2023 Glyph

x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up http://stackoverflow.com/questions/19387985/type-mismatch-error-excel-vba-looping-through-each-column-of-used-range Evaluate() Function Returning Error 2023, however there is no error up vote 0 down vote favorite I am using the Evaluate() function to test a value for errors prior to placing into a cell. In my example below, this is returning Error 2023, However when I paste the string into a cell, it reads correctly with no error (will return exactly the value referenced http://stackoverflow.com/questions/28081972/evaluate-function-returning-error-2023-however-there-is-no-error in the external spreadsheet). The example is as follows: Evaluate("='H:\@Projects\@Dev[BudgetTracking_ProjectName_MSTR_FK_2.xlsm]Budget Estimate (2)'!F44") excel vba function evaluate share|improve this question edited Jan 22 '15 at 5:49 L42 12.4k52143 asked Jan 22 '15 at 5:42 Y2kShea 104 If this is a followup question to Determine if formula will return #Ref! error then use of Evaluate where the formula you want to test refers to a closed workbook will not work. An alternative might be to use Application.DisplayAlerts = False and just write the formula to the cell then test for #Ref!. This will suppress to File Open dialog. (Remember to Application.DisplayAlerts = True after) –chris neilsen Jan 22 '15 at 6:53 That is a great approach, Chris. The function does work, but there is another handling tier of this thing that I need to work the logic out for and this suggestion I think will be really useful. Thank you –Y2kShea Jan 26 '15 at 2:09 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote accepted The Error 2023 is the xlErrRef #REF!. The Evaluate function can't directly evaluate from c

Forums Excel Questions error 2023 Results 1 to 3 of 3 error 2023This is a discussion on error 2023 within the Excel Questions forums, part of the Question Forums http://www.mrexcel.com/forum/excel-questions/217130-error-2023-a.html category; when i'm running the following macro i get error 2023 what does that mean and more importantly how do i ... LinkBack LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Aug 2nd, 2006,05:17 PM #1 meave New Member error 2023 Join Date Aug 2006 Posts 4 error 2023 when i'm running the following macro i get error 2023 what does that mean and more importantly how do i fix it. macro: Code: Sub OneColumnRemoveBlanks() Dim MyColumn As Long, c As Range, i As Integer MyColumn = Selection.Column i = 0 For Each c In Selection If Len(c) > 0 Then Cells(c.Row - i, c.Column + error 2023 excel 1) = c.Value Else i = i + 1 End If Next c End Sub the line If Len(c) > 0 Then gives the error according to visual basics. if someone could help me with this and explain it in simple language (i can just only read macro and understand them, even this one i haven't made myself) i would be very gratefull.[/quote] Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Aug 3rd, 2006,01:28 PM #2 meave New Member Join Date Aug 2006 Posts 4 if have been trying various things today and i noticed that the same macro still works in an older version of my spreadsheet could anyone help me on how this could be solved i'll put. the following macro is excecuting the previous macro. the first is done correctly but somewhere between the first and the fourth it goes wrong. Code: Sub CreateItemValidation() ' ' CreateItemValidation Macro ' Macro recorded 5-8-2005 by Danny Batenburg ' ' Sheets("Equiped Items").Select Union(Range( _ "FL:FL,FN:FN,FP:FP,FR:FR,FT:FT,FV:FV,FX:FX,FZ:FZ,GB:GB,GD:GD,GF:GF,GH:GH,GJ:GJ,GL:GL,GN:GN,GP:GP,DN:DN,DB:DB,DD:DD,DF:DF,DH:DH,DJ:DJ,DL:DL,DN:DN,DP:DP,DR:DR,DT:DT,DV:DV,DX:DX,DZ:DZ,EB:EB,ED:ED" _ ), Range( _ "EF:EF,EH:EH,EJ:EJ,EL:EL,EN:EN,EP:EP,ER:ER,ET:ET,EV:EV,EX:EX,EZ:EZ,FB:FB,FD:FD,FF:FF,FH:FH,FJ:FJ" _ )).Select Selection.ClearContents Range("'Equiped Items'!DA2:DA2000").Select Application.Run _ "'Kopie van Kopie van Kansloos Sheet.xls'!OneColumnRemoveBlanks" Range("'Equiped Items'!DC2:DC2000").Select Application.Run _ "'Kopie va