Error Number 2627 Sql
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Error 2627 Sql Server
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Error 2627 Sql Server 2008
a minute: Sign up Unique Key Violation in SQL Server - Is it safe to assume Error 2627? up vote 37 down vote favorite 3 I need to catch violation of UNIQUE constraints in a special way by a C# application sql error code 2627 I am developing. Is it safe to assume that Error 2627 will always correspond to a violation of this kind, so that I can use if (ThisSqlException.Number == 2627) { // Handle unique constraint violation. } else { // Handle the remaing errors. } ? sql-server-2005 unique-constraint share|improve this question edited May 3 '12 at 20:37 Mark Sowul 5,9392335 asked Jun 26 '11 at 11:47 User 1,25211932 add a comment| 3 Answers 3 active oldest votes up vote 73 down vote accepted sql server error code 2627 2627 is unique constraint (includes primary key), 2601 is unique index SELECT * FROM sys.messages WHERE text like '%duplicate%' and text like '%key%' and language_id = 1033 share|improve this answer answered Jun 26 '11 at 12:19 gbn 268k40376480 1 +1 for including the SQL –Peter H. Jul 3 '13 at 11:46 @gbn What is the difference between unique constraint and unique index? Don't both enforce indices? –student Feb 18 at 15:36 add a comment| up vote 4 down vote Here is a handy extension method I wrote to find these: public static bool IsUniqueKeyViolation(this SqlException ex) { return ex.Errors.Cast
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Error 2627 Violation Of Primary Key
Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it http://stackoverflow.com/questions/6483699/unique-key-violation-in-sql-server-is-it-safe-to-assume-error-2627 only takes a minute: Sign up Violation of PRIMARY KEY constraint Msg 2627 Cannot insert duplicate key up vote 0 down vote favorite I am getting a primary key violation and I don't know how to resolve it. The actual error message is; Msg 2627, Level 14, State 1, Line 1 Violation of PRIMARY KEY constraint 'PK_infmtx_dat_Transactions'. Cannot insert duplicate key http://stackoverflow.com/questions/17619603/violation-of-primary-key-constraint-msg-2627-cannot-insert-duplicate-key in object 'dbo.infmtx_dat_Transactions'. My code is as follows: INSERT INTO infmtx_dat_Transactions (tranid,chgid,chgidagnst,incnumagnst,rptpd,aid,claimid ,chgsvcpd,trantype,doschg,doscalpd,postdtchg,postdtchgcalpd,postdttran ,postdttrancalpd,depositdt,depositcalpd,cptid,cptcode,cptcomp,billprov ,rendprov,facid,posid,dptid,priminsmne,priminscatid,transcode,crcat ,refprovid,modalid,units,adjunits,patcnt,enccnt,cptcnt,amt,chgallow ,totworkrvu,totfacrvu,denial,curresponsible,curbal,curinsmne ,curopenbalflag,curcreditbalflag,denyflag,denycode,denydate,feetypeid ) SELECT trn.tran_id ,trn.chg_id ,chg.chgidagnst ,chg.incnumagnst ,trn.rptpd ,trn.acctid ,chg.claimid ,chg.rptpd ,tcd.trantype ,chg.doschg ,chg.doscalpd ,chg.postdtchg ,chg.postdtchgcalpd ,trn.tranpostdt ,trn.tranpostpd ,trn.pmtdate ,trn.pmtpd ,chg.cptid ,chg.cptcode ,chg.cptcomp ,chg.billprov ,chg.rendprov ,chg.facid ,chg.posid ,chg.dptid ,chg.priminsmne ,chg.priminscatid ,trn.payermne ,tcd.crcat ,chg.refprovid ,chg.modalid ,0 ,0 ,0 ,0 ,0 ,trn.trnamt ,chg.chgallow ,0 ,0 ,0 ,'' ,0 ,'' ,'N' ,'N' ,'N' ,'' ,Null ,chg.feetypeid FROM tmp_dat_OtherTrans trn LEFT JOIN infmtx_dat_Transactions chg on trn.chg_id = chg.tranid AND trn.chg_id = chg.chgid AND trn.chg_id = chg.chgidagnst LEFT JOIN infmtx_dic_TransCode tcd on trn.payermne = tcd.trancodemne ORDER BY trn.tran_id; How would I set a query to find the duplicate records. The primary keys on the infmtx_dat_Transactions table are:tranid,chgid,chgidagnst,rptpd and trantype sql-server share|improve this question edited Jul 12 '13 at 17:11 alroc 17.1k22240 asked Jul 12 '13 at 16:28 user2576682 1625 3 What's your primary key on that table? –Joe Jul 12 '13 at 16:29 add a comment| 2 Answers 2 active oldest votes up vote 1 down vote The primary key (and other candidate keys) prevent inser
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Messages 2001-3000 Messages 3001-4000 Messages 4001-5000 Messages 5001-6000 Messages 6001-7000 Messages 7001-7500 Messages 7501-8000 Messages 8001-8500 Messages 8501-9000 Messages 9001-9500 Messages 9501-10000 Messages 10001-10500 Messages 10501-11000 Messages 11001-11500 Messages 11501-12000 Messages 12001-13000 Messages 13001-13500 Messages 14001-14500 Home>SQL Server Error Messages> Msg 2627 - Violation of PRIMARY KEY constraint Constraint Name. Cannot insert duplicate key in object Table Name. SQL Server Error Messages - Msg 2627 - Violation of PRIMARY KEY constraint Constraint Name. Cannot insert duplicate key in object Table Name. SQL Server Error Messages - Msg 2627 Error Message Server: Msg 2627, Level 14, State 1, Line 1 Violation of PRIMARY KEY constraint Constraint Name. Cannot insert duplicate key in object Table Name. Causes: This error occurs when you are trying to insert a new record into a table that contains a PRIMARY KEY constraint and the key of the record being inserted already exists in the table. As an example, suppose you have a table containing the different loan types that your application are accepting: CREATE TABLE [dbo].[Loan Type] ( [Loan Type ID] VARCHAR(20) NOT NULL PRIMARY KEY, [Name] VARCHAR(50) NOT NULL ) GO And your table already contains the following loan types: Loan Type ID Name ------------- ------------------ CAR Car Loan HOME Home Loan HOME EQUITY Home Equity Loan PERSONAL Personal Loan STUDENT Student Loan If you try to add another loan type where the Loan Type ID already exists without knowing that it is already in the table, you will get the error. INSERT INTO [dbo].[Loan Type] ( [Loan Type ID], [Name] ) VALUES ('HOME EQUITY', 'Home Equity Loan') Server: Msg 2627, Level 14, State 1, Line 1 Violation of PRIMARY KEY constraint 'PK_Loan_Type'. Cannot insert duplicate key in object 'Loan Type'. The statement has been terminated. Solution / Work Around: To avoid this error, check first if a record with a given key already exists in the table and if it doesn’t exist yet, then perform the INSERT: IF NOT EXISTS (SELECT 'X' FROM [dbo].[Loan Type] WHERE [Loan Type ID] = 'HOM