Error 3464 In Vba
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Access Vba 3464
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Error 3464 Data Type Mismatch
in criteria expression up vote 0 down vote favorite I have a continuous form in ms access 2010 which is filtered by a textbox in which the user inputs a number. The filtered field in the underlying data table is of data type number, which also reads Long Integer in table design view. I assume the textbox delivers a string, so my after update method error 3464 access 2010 for the textbox converts the textbox.Value to a numeric format before setting the filter parameter code. The problem is that every way I try to cast the filterval variable results in a different error. Casting filterval as Long results in error 3464 data type mismatch in criteria expression at the line: .Filter = "[ClientNumber]='" & filterval & "'" How do I change my code so that the after update method can filter the form without error, given that the ClientNumber field in the data table is Long Integer? Here is my current code for the after update method of the txtFilter textbox: Dim filterVal As Long filterval = CLng(txtFilter.Value) With Forms!Main!NavigationSubform.Form!NavigationSubform.Form .Filter = "[ClientNumber]='" & filterval & "'" .FilterOn = True vba ms-access access-vba ms-access-2010 share|improve this question asked Nov 25 '13 at 22:01 CodeMed 1,0161895168 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote Since [ClientNumber] is Long Integer, don't enclose filterval with quotes when you build the .Filter string. .Filter = "[ClientNumber]=" & filterval And actually, you shouldn't need that filterval variable. Try it this way instead ... .Filter = "[ClientNumber]=" & Me.txtFilter.Value share|improve this answer answered No
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Run Time Error 3464 Data Type Mismatch
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Discuss using VBA for Access programming. Search Forums Show Threads Show Posts Advanced Search Find All Thanked Posts Go to run time error 3464 data type mismatch in criteria expression vba Page... Welcome to the p2p.wrox.com Forums. You are currently viewing the Access VBA section of the Wrox Programmer to Programmer discussions. This is a community of tens of thousands of software programmers and website http://stackoverflow.com/questions/20204290/error-3464-data-type-mismatch-in-criteria-expression developers including Wrox book authors and readers. As a guest, you can read any forum posting. By joining today you can post your own programming questions, respond to other developers’ questions, and eliminate the ads that are displayed to guests. Registration is fast, simple and absolutely free . Thread Tools Display Modes #1 (permalink) May 2nd, 2007, 05:46 AM Vince_421 Friend of Wrox Join http://p2p.wrox.com/access-vba/57349-error-3464-data-type-mismatch-criteria-express.html Date: Apr 2006 Location: Ternat, , Belgium. Posts: 159 Thanks: 0 Thanked 0 Times in 0 Posts error 3464 'data type mismatch in criteria express Hi, I have a from that tells me the next error when I try to run the code of the only action button on the form: Data type mismatch in criteria expression (error number 3464) The code that the button runs on to is: Private Sub cmdCheckOut_Click() On Error GoTo Err_cmdCheckOut_Click Dim db As DAO.Database Dim rst As DAO.Recordset Dim sSQL As String Dim intNumber As Long Dim varItem As Variant If Me.lstCheckOut.ItemsSelected.Count = 0 Then MsgBox "Er werd geen keuze gemaakt uit de lijst." & vbCrLf & _ "Er werd dus niemand uitgeschreven." & vbCrLf & vbCrLf & _ "Aucun choix n'a été effectué." & vbCrLf & _ "Personne n'a donc été désinscrit.", vbExclamation, "CobelAdmin" Exit Sub Else For Each varItem In Me.lstCheckOut.ItemsSelected intNumber = Me.lstCheckOut.Column(0) sSQL = "SELECT tblOpvolgingBezoekers.Autonumber, tblOpvolgingBezoekers.DateTimeOut, tblOpvolgingBezoekers.CheckOutDoor " & _ "FROM tblOpvolgingBezoekers " & _ "WHERE (((tblOpvolgingBezoekers.Autonumber)= " & Chr(34) & intNumber & Chr(34) & "));" Set db = Application.CurrentDb() Set rst = db.OpenRecordset(sSQL, dbOpenDynaset) While Not rst.EOF rst.Edit rst("DateTimeOut") = Now() rst("CheckOutDoor") = sAanlog rst.Update rst.MoveNext Wend rst.Close Set rst = No
Today's Posts Search Community Links Social Groups Pictures & Albums Members List Calendar Search Forums Show Threads Show Posts Tag Search http://www.access-programmers.co.uk/forums/showthread.php?t=149458 Advanced Search Find All Thanked Posts Go to Page... Thread Tools Rate Thread Display Modes 05-16-2008, 01:26 AM #1 Kita Registered User Join Date: May 2008 Posts: 3 Thanks: 0 Thanked 0 Times in 0 Posts Run-time error '3464': Data type mismatch in criteria expression! hello guys We're making a database in error 3464 access 2002 and we keep getting this error... here's the code: Code: Dim Base As Database Dim str, strTest0 As String Dim strTest1, strTest2, strTest3 As Double Dim rcd, rcd1, rcd2 As Recordset Set Base = CurrentDb Set rcd = Base.OpenRecordset("SLProd_Out", dbOpenDynaset) Set rcd1 = Base.OpenRecordset("SLProd_In", dbOpenDynaset) strTest0 = [Forms]![Shelflife]![Lb_Armazem].Column(0) strTest1 = [Forms]![Shelflife]![Lb_Armazem].Column(1) strTest2 = [Forms]![Shelflife]![Lb_Armazem].Column(2) strTest3 error 3464 data = [Forms]![Shelflife]![Lb_UtiOfi].Column(4) str = "SELECT SLProd_In.PN, SLProd_In.TR, SLProd_In.Dt_L, SLProd_Out.TAP_Num" _ & " FROM SLProd_Out,SLProd_In WHERE (((SLProd_In.PN)='" & strTest0 & "') AND ((SLProd_In.TR)=" & strTest1 & ") AND ((SLProd_In.Dt_L)=" & strTest2 & ") AND ((SLProd_Out.TAP_Num)=" & strTest3 & "))" Set rcd2 = Base.OpenRecordset(str) when we click Debug it goes directly to the line "Set rcd2 = Base.OpenRecordset(str)" hope u guys can help me Thanks in advance Kita View Public Profile Find More Posts by Kita 05-16-2008, 01:57 AM #2 KenHigg Registered User Join Date: Jun 2004 Posts: 13,295 Thanks: 7 Thanked 155 Times in 129 Posts I would suggest you examine str in the imediate window at the point that it errors. I'm guessing something is wrong with the sql statement __________________ To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts. ken “You don’t learn to walk by following rules. You learn by doing, and by falling over.” KenHigg View Publi