Error 5 Access Is Denied Python
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million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How to avoid “WindowsError: [Error 5] Access is denied” up vote 2 down vote favorite There's the script to re-create folder: # Remove folder (if exists) with all files if os.path.isdir(str(os.path.realpath('..') + "\\my_folder")): shutil.rmtree(os.path.realpath('..') + "\\my_folder", ignore_errors=True) error 5 access denied vista # Create new folder os.mkdir(os.path.realpath('..') + "\\my_folder") This works nearly always, but in some cases (on creation step) I get WindowsError: [Error 5] Access is denied: 'C:\\Path\\To\\my_folder' What could cause this error and how can I avoid it? python python-2.7 windowserror share|improve this question edited Jun 15 at 8:55 asked Jun 15 at 8:41 Andersson 2,4282524 check this: stackoverflow.com/questions/12990112/… –Daniel Sanchez Jun 15 at 8:58 add a comment| 2 Answers 2 active oldest votes up vote 1 down vote It happens because you are not checking if you have permissions to open that path. You need to change the permissions on those folders. share|improve this answer answered Jun 15 at 8:53 wind85 15129 add a comment| up vote 1 down vote What could cause this error? You simply do not have access to the folder you are writing in for the process that is currently running (python.exe), or maybe even for the user. Unless your user is an admin ther
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Error 5 Access Denied Starting Service Windows Server 2003
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Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up WindowsError [error 5] Access is denied up vote http://stackoverflow.com/questions/37830326/how-to-avoid-windowserror-error-5-access-is-denied 18 down vote favorite 4 I'm using the killableprocess package (built on top of subprocess) for running processes Whenever I run the "killableprocess.Popen(command)" piece of code in my script I get the following error: File "killableprocess.py", line 157, in _execute_child winprocess.AssignProcessToJobObject(self._job, hp) File "winprocess.py", line 37, in ErrCheckBool raise WinError() WindowsError [error 5] Access is denied Exception TypeError: "'NoneType' object is not callable" in
Sign in Pricing Blog Support Search GitHub This repository Watch https://github.com/conda/conda/issues/2687 99 Star 905 Fork 307 conda/conda Code Issues 1,117 Pull requests 35 Projects 0 Wiki Pulse Graphs New issue windows 10 windowserror error https://bugs.python.org/issue19643 5 access denied #2687 Closed maien85 opened this Issue Jun 15, 2016 · 20 comments Projects None yet Labels bug Milestone error 5 4.1 Assignees mingwandroid 6 participants maien85 commented Jun 15, 2016 I've installed Anaconda on Windows 10, and now I'm trying to create an environment for python 3.5 using the follwoing comand: conda create -n py35 python=3.5 anaconda Also tried: conda create -n py35 python=3.5 error 5 access And I tried running as admin. Also tried rebooting. In all cases I get: An unexpected error has occurred, please consider sending the following traceback to the conda GitHub issue tracker at: https://github.com/conda/conda/issues Include the output of the command 'conda info' in your report. Current conda install: platform : win-64 conda version : 4.1.0 conda-build version : 1.20.0 python version : 2.7.11.final.0 requests version : 2.9.1 root environment : C:\Users\mbinj\Anaconda2 (writable) default environment : C:\Users\mbinj\Anaconda2 envs directories : C:\Users\mbinj\Anaconda2\envs package cache : C:\Users\mbinj\Anaconda2\pkgs channel URLs : https://repo.continuum.io/pkgs/free/win-64/ https://repo.continuum.io/pkgs/free/noarch/ https://repo.continuum.io/pkgs/pro/win-64/ https://repo.continuum.io/pkgs/pro/noarch/ config file : None is foreign system : False Traceback (most recent call last): File "C:\Users\mbinj\Anaconda2\Scripts\conda-script.py", line 5, in sys.exit(main()) File "C:\Users\mbinj\Anaconda2\lib\site-packages\conda\cli\main.py", line 120, in main args_func(args, p) File "C:\Users\mbinj\Anaconda2\lib\site-packages\conda\cli\main.py", line 127, in args_func args.func(args, p) File "C:\Users\mbinj\Anaconda2\lib\site-packages\conda\cli\main_create.py", line 57, in execute install(args, parser, 'create') File "C:\Users\mbinj\Anaconda2\lib\site-packages\conda\cli\inst
User List Committer List Help Tracker Documentation Tracker Development Report Tracker Problem Issue19643 classification Title: shutil rmtree fails on readonly files in Windows Type: enhancement Stage: resolved Components: Library (Lib), Windows Versions: Python 3.5 process Status: closed Resolution: fixed Dependencies: Superseder: Assigned To: tim.golden Nosy List: Jovik, ivan.radic, paul.moore, python-dev, r.david.murray, sushisource, tim.golden, zach.ware Priority: normal Keywords: patch Created on 2013-11-18 12:11 by ivan.radic, last changed 2014-10-16 17:37 by paul.moore. This issue is now closed. Files File name Uploaded Description Edit issue19643-doc.patch tim.golden, 2014-05-07 10:17 review issue19643-doc.2.patch tim.golden, 2014-05-07 13:59 review Messages (27) msg203285 - (view) Author: Ivan Radic (ivan.radic) Date: 2013-11-18 12:11 shutil.rmtree works nice on Windows until it hits file with read only attribute set. Workaround is to provide a onerror parameter as a function that checks and removes file attribute before attempting to delete it. Can option to delete read_only files be integrated in shutil.rmtree? Example output in In Python 2.7: shutil.rmtree("C:\\2") Traceback (most recent call last): File "