Error 6 Overflow In Excel
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Forums Excel Questions Runtime Error '6' Overflow error at row 32767 Results 1 to 6 of 6 1Likes Top All This Page 1 Post By Mark O'Brien Runtime Error '6' overflow error vba excel Overflow error at row 32767This is a discussion on Runtime Error '6' Overflow
Runtime Error 6 Overflow Windows 7
error at row 32767 within the Excel Questions forums, part of the Question Forums category; Hello, I am running a runtime error 6 overflow vba access macro that retrieves data from a DB. The entire table is only 35,045 rows. I ... LinkBack LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in http://answers.microsoft.com/en-us/msoffice/forum/msoffice_excel-mso_other/run-time-error-6-overflow-during-macro-run/6a176497-c2b4-44e9-81c1-c921a71a5947 TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Oct 13th, 2003,05:51 PM #1 leeloo0505 Board Regular Join Date Mar 2003 Posts 130 Runtime Error '6' Overflow error at row 32767 Hello, I am running a macro that retrieves data from a DB. The entire table is only 35,045 rows. I am trying to retrieve all http://www.mrexcel.com/forum/excel-questions/63516-runtime-error-6-overflow-error-row-32767-a.html the rows from the table but for some reason when it hits row 32,768 rows it says 'Runtime Error 6: Overflow. All previous 32,767 rows are brought into the sheet fine. The sheet I am writing too is 'cleared' before the import.. anyone have any suggestions? leeloo Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Oct 13th, 2003,05:54 PM #2 Mark O'Brien MrExcel MVP Join Date Feb 2002 Location Columbus, OH, USA Posts 3,530 Re: Runtime Error '6' Overflow error at row 32767 Change your "Integer" declaration to "Long". Is that a good guess without seeing any code? Share Share this post on Digg Del.icio.us Technorati Twitter mikerickson likes this. Mark O'Brien Columbus Ohio Celtic Supporters Club Reply With Quote Oct 13th, 2003,06:02 PM #3 leeloo0505 Board Regular Join Date Mar 2003 Posts 130 Re: Runtime Error '6' Overflow error at row 32767 Awesome! Yep that was it, had my irow2 defined as a integer... thank you so much! leeloo Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Oct 13th, 2003,06:15 PM #4 Mark O'Brien MrExcel MVP Join Date Feb 2002 Location Columbus, OH, USA Posts 3,530
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn http://stackoverflow.com/questions/12588485/vba-macro-run-time-error-6-overflow-coding-inside-a-loop more about Stack Overflow the company Business Learn more about hiring developers or posting http://stackoverflow.com/questions/12469849/run-time-error-6-overflow-excel-vba ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA Macro Run time error 6: overflow- coding inside a error 6 loop up vote 2 down vote favorite Having a problem with this Error. I am creating a GA and the loop is to assign my fitness value to an array. some of the variables Dim Chromolength as integer Chromolength = varchromolength * aVariables Dim i as integer, j as integer, counter as integer Dim Poparr() As Integer Dim FitValarr() As Integer the code: ReDim Poparr(1 To PopSize, 1 error 6 overflow To Chromolength) For i = 1 To PopSize For j = 1 To Chromolength If Rnd < 0.5 Then Poparr(i, j) = 0 Else Poparr(i, j) = 1 End If Next j Next i For i = 1 To PopSize j = 1 counter = Chromolength Do While counter > 0 FitValarr(i) = FitValarr(i) + Poparr(i, counter) * 2 ^ (j - 1) j = j + 1 counter = counter - 1 Loop Next i I am having problems with: FitValarr(i) = FitValarr(i) + Poparr(i, counter) * 2 ^ (j - 1) I apologize, I am fairly new to VBA. vba excel-vba share|improve this question asked Sep 25 '12 at 17:54 John Hopley 1361211 1 Are you dimensioning FitValarr to be FitValarr(1 to PopSize) anywhere? –Jon Egerton Sep 25 '12 at 17:57 uhm no... should i add ReDim FitValarr(1 to PopSize) –John Hopley Sep 25 '12 at 18:00 add a comment| 1 Answer 1 active oldest votes up vote 10 down vote accepted An overflow condition arises when you create an integer expression that evaluates to a value larger than can be expressed in a 16-bit signed integer. Given the expression, either the contents of FitValarr(i), or the
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Run-time error 6: Overflow: Excel VBA up vote 3 down vote favorite I have been trying to resolve this but could not. I have the following VBA code. While running it gives "run time error 6: Overflow". I guess I have assigned a right type to each variable. Please help!! Sub UseCoeff() Dim a, b As Long Dim Value1 As Double ThisWorkbook.Sheets("UseTableBEA").Activate For b = 2 To 427 For a = 2 To 431 Value1 = ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value / ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value ThisWorkbook.Sheets("UseCoeff").Cells(a, b).Value = Value1 Next a Next b End Sub Each cell will have a result that may be between 0 and 1 up to eight decimal places. Thanks in advance!! excel-vba runtime-error share|improve this question edited Sep 18 '12 at 4:04 Passerby 7,72021331 asked Sep 18 '12 at 3:05 user1671860 25125 Which version of Excel are you using? In Excel 2003 you can't have 427 columns... –Passerby Sep 18 '12 at 4:05 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote If ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value is ever 0, then ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value / ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value will cause the Overflow error if ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value is also 0. To avoid this, use an if statement to filter out the 0s, just update the comment with the actual logic you want: If ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value = 0 Then Value1 = 'Whatever you want but probably 0. Else Value1 = ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value / ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value End If share|impro