Error Overflow In Excel
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Vba Overflow Integer
Overflow the company Business Learn more about hiring developers or posting ads with us run time error 6 overflow Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community runtime error 6 overflow excel vba of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Excel VBA: Overflow error up vote 1 down vote favorite Just started programming in VBA, I http://answers.microsoft.com/en-us/msoffice/forum/msoffice_excel-mso_other/run-time-error-6-overflow-during-macro-run/6a176497-c2b4-44e9-81c1-c921a71a5947 have a problem, and i don't know how to solve this. I think everything is ok. There shows Run-Time Error '6' Overflow when i want to run this macro. Sub Działaj() Dim Tablica(1 To 5000) As String Dim Dni() Dim kolumna As Integer Dim wiersz As Integer Dim licznik As Integer Dim PF As Boolean Dim tmp As Integer Dim i As Integer Dim tmp2 As String licznik = 2 tmp = http://stackoverflow.com/questions/20339067/excel-vba-overflow-error 0 PF = False kolumna = 22 wiersz = 2 Do If Worksheets("Początkowe").Cells(wiersz, kolumna).Value <> vbNullString Then For i = 1 To licznik If Worksheets("Początkowe").Cells(wiersz, kolumna).Value = Tablica(i) Then 'debugger shows problem here i guess PF = True tmp = i End If Next i End If If Worksheets("Początkowe").Cells(wiersz, kolumna).Value = "koniec" Then Exit Do End If wiersz = wiersz + 1 Loop End Sub Can anyone tell me where i made a mistake? I would be very grateful. excel vba overflow share|improve this question asked Dec 2 '13 at 22:19 Domin1992 35118 1 One, you haven't set any value in Tablica(i). Second, if you don't find the value koniec, then the loop keep on until you grow out of your integer variable wiersz, around 32k. –nutsch Dec 2 '13 at 22:27 What do you mean saying "you haven't set any value in Tablica(i)", can you give me an example? Don't worry about "koniec" it will be at the end of all data in all columns. –Domin1992 Dec 2 '13 at 22:30 Sorry, you were right about "koniec" too :) Thanks. –Domin1992 Dec 2 '13 at 22:35 you're referencing If Worksheets("Początkowe").Cells(wiersz, kolumna).Value = Tablica(i), but at no point in your code prior to that l
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more http://stackoverflow.com/questions/12588485/vba-macro-run-time-error-6-overflow-coding-inside-a-loop about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users http://www.vbforums.com/showthread.php?518655-Overflow-error-in-Excel-macro Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA Macro Run time error 6: overflow- coding inside a loop up vote 2 down vote favorite Having a problem with this Error. I am creating a GA error 6 and the loop is to assign my fitness value to an array. some of the variables Dim Chromolength as integer Chromolength = varchromolength * aVariables Dim i as integer, j as integer, counter as integer Dim Poparr() As Integer Dim FitValarr() As Integer the code: ReDim Poparr(1 To PopSize, 1 To Chromolength) For i = 1 To PopSize For j = 1 To Chromolength If Rnd < 0.5 Then Poparr(i, j) = 0 Else Poparr(i, j) = error 6 overflow 1 End If Next j Next i For i = 1 To PopSize j = 1 counter = Chromolength Do While counter > 0 FitValarr(i) = FitValarr(i) + Poparr(i, counter) * 2 ^ (j - 1) j = j + 1 counter = counter - 1 Loop Next i I am having problems with: FitValarr(i) = FitValarr(i) + Poparr(i, counter) * 2 ^ (j - 1) I apologize, I am fairly new to VBA. vba excel-vba share|improve this question asked Sep 25 '12 at 17:54 John Hopley 1361211 1 Are you dimensioning FitValarr to be FitValarr(1 to PopSize) anywhere? –Jon Egerton Sep 25 '12 at 17:57 uhm no... should i add ReDim FitValarr(1 to PopSize) –John Hopley Sep 25 '12 at 18:00 add a comment| 1 Answer 1 active oldest votes up vote 11 down vote accepted An overflow condition arises when you create an integer expression that evaluates to a value larger than can be expressed in a 16-bit signed integer. Given the expression, either the contents of FitValarr(i), or the expression 2^(j-1) could be overflowing. Suggest all the the variables presently declared as Int be changed to Long. Long integers are 32-bit signed values and provide a correspondingly larger range of possible values. share|improve this answer answered Sep 25 '12 at 18:15 David W 7,4451741 add a comment| Your Answer draft saved draft discar
is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 4 of 4 Thread: Overflow error in Excel macro Tweet Thread Tools Show Printable Version Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Apr 16th, 2008,05:51 AM #1 303factory View Profile View Forum Posts Thread Starter New Member Join Date Apr 2008 Posts 11 Overflow error in Excel macro Hi I've written code to go through each row of a spreadsheet, and delete any rows where the date does not fall within a specific range. Unfortunatly on my spreadsheet I occasionally get large numbers in the date column due to corruption. I was hoping the 'isdate' function would allow me to remove these but I keep getting an