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Excel Vba Overflow Runtime Error 6
Error within the Excel Questions forums, part of the Question Forums category; Hi, vba overflow error 6 I am really new to writing code in VBA and the code below is meant to convert information on ... LinkBack excel vba overflow error 6 LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode
Vba Overflow Integer
Nov 29th, 2011,08:43 AM #1 berwicks New Member Join Date Nov 2011 Location West Lothian, Scotland Posts 6 VBA - Overflow Error Hi, I am really new to writing code in VBA and the code below is meant to convert information on Goods Received Notes into XML for posting into a legacy system. Each line in Excel contains details of the individual GRN for up to three order lines.
Runtime Error 6 Overflow Fix
The macro should then take this data and create an appropriate XML file. I was getting a loop error, but after some digging on this site I resolved that, but now I am getting an overflow error. Can someone please have a look at my code and let me know where I am going wrong? Code: Sub GenerateXML() ' Dim intRowS As Integer, intRowC As Integer, intRowC2 As Integer, intRowD As Integer Dim strTab As String, strTab2 As String, tempco As String intRowS = 10 'row count on DataEntry Sheet intRowC = 3 'row count on GenCode Sheet intRowC2 = 3 intRowS2 = 6 intRowS3 = 5 intRowS4 = 4 intRowS5 = 3 strTab = "GenCode" strTab2 = "DataEntry" tempco = "" 'codes to check for special characters Worksheets(strTab2).Range("A10", "Y1100").Replace What:="&", Replacement:="&", SearchOrder:=xlByColumns, MatchCase:=True Worksheets(strTab2).Range("A10", "Y1100").Replace What:="'", Replacement:="'", SearchOrder:=xlByColumns, MatchCase:=True Worksheets(strTab2).Range("A10", "Y1100").Replace What:="""", Replacement:=""", SearchOrder:=xlByColumns, MatchCase:=True Worksheets(strTab2).Range("A10", "Y1100").Replace What:="<", Replacement:="<", SearchOrder:=xlByColumns, MatchCase:=True Worksheets(strTab2).Range("A10", "Y1100").Replace What:=">", Replacement:=">", SearchOrder:=xlByColumns, MatchCase:=True Sheets(strTab).Select Cells.Select Selection.ClearContents Worksheets(strTab).Cells(1, 1) = "" Worksheets(strTab).Cells(2, 1) = "" Worksheets(strTab).Cells(intRowC, 2) = "" intRowC = intRowC + 1 Worksheets(strTab).Cells(intRowC, 2) = "" intRowC = intRowC + 1 Worksheets(strTab).Cells(intRowC, 2) = "" & Worksheets(strTab2).Cells(intRowS5, 2) & "" intRowC = intRowC + 1 Wo
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Vba Integer Max Value
Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, runtime error 6 overflow excel just like you, helping each other. Join them; it only takes a minute: Sign up Excel VBA: Overflow error up vote 1 down vote favorite Just started programming in VBA, I have a problem, and i don't http://www.mrexcel.com/forum/excel-questions/595352-visual-basic-applications-overflow-error.html know how to solve this. I think everything is ok. There shows Run-Time Error '6' Overflow when i want to run this macro. Sub Działaj() Dim Tablica(1 To 5000) As String Dim Dni() Dim kolumna As Integer Dim wiersz As Integer Dim licznik As Integer Dim PF As Boolean Dim tmp As Integer Dim i As Integer Dim tmp2 As String licznik = 2 tmp = 0 PF = False kolumna = 22 wiersz = http://stackoverflow.com/questions/20339067/excel-vba-overflow-error 2 Do If Worksheets("Początkowe").Cells(wiersz, kolumna).Value <> vbNullString Then For i = 1 To licznik If Worksheets("Początkowe").Cells(wiersz, kolumna).Value = Tablica(i) Then 'debugger shows problem here i guess PF = True tmp = i End If Next i End If If Worksheets("Początkowe").Cells(wiersz, kolumna).Value = "koniec" Then Exit Do End If wiersz = wiersz + 1 Loop End Sub Can anyone tell me where i made a mistake? I would be very grateful. excel vba overflow share|improve this question asked Dec 2 '13 at 22:19 Domin1992 35118 1 One, you haven't set any value in Tablica(i). Second, if you don't find the value koniec, then the loop keep on until you grow out of your integer variable wiersz, around 32k. –nutsch Dec 2 '13 at 22:27 What do you mean saying "you haven't set any value in Tablica(i)", can you give me an example? Don't worry about "koniec" it will be at the end of all data in all columns. –Domin1992 Dec 2 '13 at 22:30 Sorry, you were right about "koniec" too :) Thanks. –Domin1992 Dec 2 '13 at 22:35 you're referencing If Worksheets("Początkowe").Cells(wiersz, kolumna).Value = Tablica(i), but at no point in your code prior to that line do you assign a value to the array, so Tablica(i) at that stage is an empty string. &ndash
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more http://stackoverflow.com/questions/12469849/run-time-error-6-overflow-excel-vba about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Run-time error 6: Overflow: Excel VBA up vote 3 down vote favorite I error 6 have been trying to resolve this but could not. I have the following VBA code. While running it gives "run time error 6: Overflow". I guess I have assigned a right type to each variable. Please help!! Sub UseCoeff() Dim a, b As Long Dim Value1 As Double ThisWorkbook.Sheets("UseTableBEA").Activate For b = 2 To 427 For a = 2 To 431 Value1 = ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value / ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value ThisWorkbook.Sheets("UseCoeff").Cells(a, runtime error 6 b).Value = Value1 Next a Next b End Sub Each cell will have a result that may be between 0 and 1 up to eight decimal places. Thanks in advance!! excel-vba runtime-error share|improve this question edited Sep 18 '12 at 4:04 Passerby 7,75021331 asked Sep 18 '12 at 3:05 user1671860 25125 Which version of Excel are you using? In Excel 2003 you can't have 427 columns... –Passerby Sep 18 '12 at 4:05 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote If ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value is ever 0, then ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value / ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value will cause the Overflow error if ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value is also 0. To avoid this, use an if statement to filter out the 0s, just update the comment with the actual logic you want: If ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value = 0 Then Value1 = 'Whatever you want but probably 0. Else Value1 = ThisWorkbook.Sheets("UseTableBEA").Cells(a, b).Value / ThisWorkbook.Sheets("UseTableBEA").Cells(432, b).Value End If share|improve this answer edited Sep 18 '12 at 14:20 answered Sep 18 '12 at 4:18 Daniel 10.4k11637 Just did some testing and if I use a zero I get a divide by zero error opposed to overflow error. –Alistair Weir Sep 18 '12 at 14:16 1 @AlistairW