Error C2662 Cannot Convert This

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Error C2662 Conversion Loses Qualifiers

posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community c++ error c2662 Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up c++ error C2662 cannot convert 'this' pointer from 'const cannot convert this pointer from const to & Type' to 'Type &' up vote 17 down vote favorite 6 I am trying to overload the c++ operator== but im getting some errors... error C2662: 'CombatEvent::getType' : cannot convert 'this' pointer from 'const CombatEvent' to 'CombatEvent &' this error is at this line if (lhs.getType() == rhs.getType()) see the code bellow: class CombatEvent { public: CombatEvent(void); ~CombatEvent(void); enum CombatEventType { AttackingType, ... LowResourcesType }; CombatEventType getType(); BaseAgent*

Error C2662 Cannot Convert This Pointer From Const To Conversion Loses Qualifiers

getAgent(); friend bool operator<(const CombatEvent& lhs, const CombatEvent& rhs) { if (lhs.getType() == rhs.getType()) return true; return false; } friend bool operator==(const CombatEvent& lhs, const CombatEvent& rhs) { if (lhs.getType() == rhs.getType()) return true; return false; } private: UnitType unitType; } can anybody help? c++ operator-overloading syntax-error friend-function share|improve this question asked Aug 22 '12 at 7:33 thiagoh 1,74262143 add a comment| 3 Answers 3 active oldest votes up vote 36 down vote accepted CombatEventType getType(); needs to be CombatEventType getType() const; Your compiler is complaining because the function is being given a const object that you're trying to call a non-const function on. When a function gets a const object, all calls to it have to be const throughout the function (otherwise the compiler can't be sure that it hasn't been modified). share|improve this answer edited Dec 24 '14 at 3:09 hichris123 6,536113257 answered Aug 22 '12 at 7:36 Hbcdev 4,33522353 add a comment| up vote 5 down vote change the declaration to : CombatEventType getType() const; you can only call 'const' members trough references to const. share|improve this answer answered Aug 22 '12 at 7:36 Andrzej 2,7671225 add a comment| up vote 3 down vote It's a const issue, yo

Forum Visual C++ & C++ Programming Visual C++ Programming [RESOLVED] error C2662: cannot convert 'this' pointer from 'const Item' to 'Item &' If const method this is your first visit, be sure to check out the FAQ const_cast example by clicking the link above. You may have to register or Login before you can post: click the register

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link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 11 of 11 Thread: [RESOLVED] error C2662: cannot http://stackoverflow.com/questions/12068301/c-error-c2662-cannot-convert-this-pointer-from-const-type-to-type convert 'this' pointer from 'const Item' to 'Item &' Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode March 6th, 2007,07:07 AM #1 Mybowlcut View Profile View Forum Posts Visit Homepage Senior Member Join Date Nov 2006 Location Australia Posts 1,569 [RESOLVED] error C2662: cannot convert 'this' pointer http://forums.codeguru.com/showthread.php?416873-RESOLVED-error-C2662-cannot-convert-this-pointer-from-const-Item-to-Item-amp from 'const Item' to 'Item &' Hi guys! The error: Code: error C2662: 'Item::GetName' : cannot convert 'this' pointer from 'const Item' to 'Item &' My class definition: Code: class Inventory { public: Inventory(vector ITEMLIST): itemList(ITEMLIST) {} inline void ListItems(); private: vector itemList; }; The class member function that the error is occurring in (error line in red): Code: inline void Inventory::ListItems() { if(itemList.empty()) cout << "\n\nYou have no items."; else { vector::const_iterator iter = itemList.begin(); for(iter; iter != itemList.end(); ++iter) { cout << "\n\n"; cout << iter->GetName(); } } } And the class (Item) member function that the iter is trying to access: Code: string GetName() { return name; } I can't get around this error.. it's beyond my knowledge I think. I've tried and I'm seeking helppppppp. If I'm missing anything out let me know! Good judgment is gained from experience. Experience is gained from bad judgment. Cosy Little Game | SDL | GM script | VLD | Syntax Hlt | Can you help me with my homework assignment? Reply With Quote March 6th, 2007,07:18 AM #2 0xC0000005 View Profile View Forum Posts

download a browser that supports JavaScript, or enable it if it's disabled (i.e. NoScript). Home Qt Development General and Desktop C2662: 'function' : cannot convert 'this' pointer from 'type1' to https://forum.qt.io/topic/7774/solved-c2662-function-cannot-convert-this-pointer-from-type1-to-type2 'type2' C2662: 'function' : cannot convert 'this' pointer from 'type1' to 'type2' This topic has been deleted. Only users with topic management privileges can see it. huckfinn last edited by Hello people, I http://cboard.cprogramming.com/cplusplus-programming/99520-compile-error-cannot-convert-pointer.html have a QHash dynamicData which is not const! @ #pragma once #include #include #include #include "DataItem.h" class DataController { public: DataController(void); ~DataController(void); int removeDataItem(qint32 key) const; protected: QHash dynamicData; error c2662 }; @ And my source @ #include #include "DataController.h" DataController::DataController(void) { // } int DataController::removeDataItem(qint32 key) const { return this->dynamicData.remove( key ) ; } @ I get error C2662: 'QHash::remove' : cannot convert 'this' pointer from 'const QHash' to 'QHash &' My dynamicData is not constant, so remove should be callable. Whats the matter? I dont see the error.. Cheers Huck Reply Quote 0 thisisbhaskar last edited error c2662 cannot by Your removeDataItem() is const function, and its trying to remove/modify your class member variable. That may be the problem?? Reply Quote 0 JohanSolo last edited by [quote author="Vijay Bhaska Reddy" date="1311172988"]Your removeDataItem() is const function, and its trying to remove/modify your class member variable. That may be the problem??[/quote] It definitely is! A const method cannot modify the current instance (pointed by "this"). You have a conception problem in here : how could a method that removes an item from a container not modify the instance which "owns" the container... Of course there are workaround if you REALLY want the method to be const. You can either declare your QHash mutable or use const_cast to remove the "const" in front of the ‘const QHash’. I would'nt recommend this though. `They did not know it was impossible, so they did it.' -- Mark Twain Reply Quote 0 huckfinn last edited by Yes, thats it. No the method might be non const as well. I havent recognized that. Thankk you both! Reply Quote 0 thisisbhaskar last edited by My suggestion is .. I don't see a good reason why your removeDataItem() should be const. Remove const. Reply Quote 0 huckfinn last edi

Programming Boards C++ Programming compile error cannot convert 'this' pointer Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes for common problems Thread: compile error cannot convert 'this' pointer Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 02-24-2008 #1 George2 View Profile View Forum Posts Registered User Join Date May 2006 Posts 1,579 compile error cannot convert 'this' pointer Hello everyone, Which C++ rule do I break in the following code? Why there is compile error? Code: class Foo{ public: Foo() { } int foo1() { return 100; } const Foo getCurrent1() { return *this; } const Foo& getCurrent2() { return *this; } }; int main() { Foo f; f.getCurrent1().foo1(); // error C2662: 'Foo::foo1' : cannot convert 'this' pointer from 'const Foo' to 'Foo &' f.getCurrent2().foo1(); // error C2662: 'Foo::foo1' : cannot convert 'this' pointer from 'const Foo' to 'Foo &' return 0; } thanks in advance, George 02-24-2008 #2 tabstop View Profile View Forum Posts and the Hat of Guessing Join Date Nov 2007 Posts 14,185 I got a slightly more helpful warning message from gcc: error: no matching function for call to `Foo::foo1() const' foo1 is not labeled as a const function, therefore it cannot take a const "argument". 02-24-2008 #3 George2 View Profile View Forum Posts Registered User Join Date May 2006 Posts 1,579 Thanks tabstop, Your fix works, cool! I am confused about what the compile outputs, cannot convert 'this' pointer from 'const Foo' to 'Foo &' I think it should change "this" to "*this", right? This pointer is a pointer to class (Foo*) and not class type itself (Foo)? Should be the following? Any comments? cannot convert '*this' from 'const Foo' to 'Foo &' Originally Posted by tabstop I got a slightly more helpful warning message from gcc: error: no matching function for call to `Foo: