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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the error c2664 cannot convert parameter company Business Learn more about hiring developers or posting ads with us Stack Overflow error c2664 cannot convert parameter 1 from Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 error c2664 cannot convert parameter from const char to lpcwstr million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error C2664: cannot convert parameter 1 from 'int' to 'int []' up vote 0 down vote favorite #include using error c2664 cannot convert argument namespace std; class amin { private: const int length = 10; int newArray[length]; int i; public: int deleteEvenNumber(int getArray[length]) { for (i = 0 ; i < length ; i++) { if (getArray[i] % 2 == 0) newArray[i] = getArray[i]; i++; }; return newArray[length]; }; }; main: int main() { amin manipulateArrays; int input , i = 0; const int length = 10; int mainArray[length]; cout<<"Please enter ten numbers :"<

Error C2664 In C++

0 ; i < length ; i++) { cin>>input; mainArray[i] = input; i++; }; manipulateArrays.deleteEvenNumber(mainArray[length]); }; i got these two errors: error C2664: 'amin::deleteEvenNumber' : cannot convert parameter 1 from 'int' to 'int []' IntelliSense: argument of type "int" is incompatible with parameter of type "int *" please help and explain about my mistake to me. and please introduce a good tutorial for this problem or this title to me. c++ casting share|improve this question edited Mar 3 '14 at 15:23 herohuyongtao 25.4k96691 asked Mar 3 '14 at 15:13 Amin Khormaei 492312 I would use a std::vector rather than arrays. –Nick Mar 3 '14 at 15:17 add a comment| 2 Answers 2 active oldest votes up vote 4 down vote accepted Your function deleteEvenNumber() requires an int [] (i.e. int array), however you passed it an int to it. manipulateArrays.deleteEvenNumber(mainArray[length]); ^^^^^^^^^^^^^^^^^ | this is an 'int', not an 'int []' To also pass the length to the function, you may want to change your function to int deleteEvenNumber(int getArray[], int length) And then call it like: manipulateArrays.deleteEvenNumber(mainArray, length); Alternatively, you can use vector mainArray instead, and then you can easily get its length by mainArray.size(). share|improve this answer edited Mar 3 '14 at 15:21 answered Mar 3 '14 at 15:15 herohuyongtao 25.4k96691 And

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this site About Us Learn more about Stack Overflow the company Business Learn error c2664 cannot convert argument 1 from more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question error c2664 in visual c++ x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error http://stackoverflow.com/questions/22150353/error-c2664-cannot-convert-parameter-1-from-int-to-int C2664: cannot convert parameter 1 from 'X' to 'X' up vote 1 down vote favorite I have a C++/Win32/MFC project in Visual Studio 2008, and I'm getting a strange error message when I compile it. I've created a small project to demonstrate the problem, and the main code is #ifndef _MyObject_h #define _MyObject_h class MyObject { public: MyObject() { } }; #endif // http://stackoverflow.com/questions/14713648/error-c2664-cannot-convert-parameter-1-from-x-to-x _MyObject_h // --- END MyObject.h // --- BEGIN ObjectData.h #ifndef _ObjectData_h #define _ObjectData_h template class ObjectData { public: DataPolicy *data; ObjectData() : data(NULL) { } ObjectData(const ObjectData ©) : data(copy.data) { } ObjectData & operator=(const ObjectData ©) { this->data = copy.data; return *this; } }; #endif // _ObjectData_h // --- END ObjectData.h // --- BEGIN Tool.h #ifndef _Tool_h #define _Tool_h #include "ObjectData.h" template class Tool { private: ObjectData _object; public: Tool(ObjectData obj); }; #endif // _Tool_h // --- END Tool.h // --- BEGIN Tool.cpp #include "stdafx.h" #include "Tool.h" template Tool::Tool(ObjectData obj) : _object(obj) { } // --- END Tool.cpp // --- BEGIN Engine.h #ifndef _Engine_h #define _Engine_h #include "Tool.h" #include "MyObject.h" class Engine { private: MyObject *_obj; public: Engine(); ~Engine(); void DoSomething(); }; #endif // _Engine_h // --- END Engine.h // --- BEGIN Engine.cpp #include "stdafx.h" #include "Engine.h" Engine::Engine() { this->_obj = new MyObject(); } Engine::~Engine() { delete this->_obj; } void Engine::DoSomething() { ObjectData objData; objData.data = this->_obj; // NEXT LINE IS WHERE THE ERROR OCCURS Tool< ObjectData > *tool = new Tool< ObjectData >(objData); } // --- END Eng

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow http://stackoverflow.com/questions/21797959/c2664-cannot-convert-parameter the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community https://www.daniweb.com/programming/software-development/threads/210365/error-c2664-createfilew-cannot-convert-parameter-1-from-const-char-5-to-lpcwstr of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up C2664 Cannot Convert Parameter up vote 0 down vote favorite I am implementing this code but i error c2664 am receiving an error. http://curl.haxx.se/libcurl/c/ftpupload.html The error is in this bit of code. static size_t read_callback(void *ptr, size_t size, size_t nmemb, void *stream) { curl_off_t nread; /* in real-world cases, this would probably get this data differently as this fread() stuff is exactly what the library already would do by default internally */ size_t retcode = fread(ptr, size, nmemb, stream); nread = (curl_off_t)retcode; fprintf(stderr, "*** We read %" CURL_FORMAT_CURL_OFF_T " bytes from error c2664 cannot file\n", nread); return retcode; } Errors are... IntelliSense: argument of type "void *" is incompatible with parameter of type "FILE *" and Error C2664: 'fread' : cannot convert parameter 4 from 'void *' to 'FILE *' Any tips would be useful. I don't understand why we'd pass a void *stream to the function. What does that even mean? A pointer to a void? It is called here. /* we want to use our own read function */ curl_easy_setopt(curl, CURLOPT_READFUNCTION, read_callback); CURL API CURLOPT_READFUNCTION Pass a pointer to a function that matches the following prototype: size_t function( void *ptr, size_t size, size_t nmemb, void *userdata); This function gets called by libcurl as soon as it needs to read data in order to send it to the peer. The data area pointed at by the pointer ptr may be filled with at most size multiplied with nmemb number of bytes. Your function must return the actual number of bytes that you stored in that memory area. Returning 0 will signal end-of-file to the library and cause it to stop the current transfer. If you stop the current transfer by returning 0 "pre-maturely" (i.e before the server expected it, like when you've said you will upload N bytes and you upload less than N bytes),

7 Years Ago Hello, I am doing simple read/write program for serial port. I am faceing a error that i donĀ“t understand. Error is: "error C2664: 'CreateFileW' : cannot convert parameter 1 from 'const char [5]' to 'LPCWSTR' " My whole program: #include #include #include using namespace std; void set_com_pin(bool value); int main(int argc, char* argv[]) { if(argc != 2) { cerr<<"bad usage !"<

 

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