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Error Redefinition Of Main

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Error Redefinition Of ‘class

Sign up Redefinition of main up vote 4 down vote favorite I started writing code in C, and I needed the toupper function in my code, so I added to ctype.h header file to include it. All of a sudden I can't run my program because I keep getting a redefinition of main error from my compiler. Before I added the header error redefinition of c++ ctype.h, and even if I get rid of the header file ctype.h, the program runs. What do I do to fix this? #include #include #define NAMESPACE 20 int main (void) { char first_name[NAMESPACE], middle_name[NAMESPACE], last_name[NAMESPACE]; printf ("Please enter your first, middle and last name.\n"); scanf ("%s", first_name); scanf("%s", middle_name); scanf ("%s", last_name); printf ("%s %0.1s %s", first_name, middle_name, last_name); return 0; } [error] redefinition of "int main()": Here is the code saved as a header file called ctype.h in my DEV c++ , #include #include int main (void) { char ch[]="I AM AN IDIOT."; char c='A'; int i=0; while(c) { c=getch(); printf("%c\a",ch[i]); i++; if(i==14) { printf(" "); i=0; } } } c main share|improve this question edited Jun 5 '15 at 21:00 asked Jun 5 '15 at 16:31 nicholas cupello 265 2 The code looks OK to me. What's your platform? –R Sahu Jun 5 '15 at 16:39 1 can you post a screenshot of your project in dev+c++? –pfannkuchen_gesicht Jun 5 '15 at 18:00 1 Is that the entire error message? Does it refer to a line number?

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Error Redefinition Of 'struct Iovec'

fallacies Newbie Posts: 15 Karma: 0[add] Arduino rocks error: redefinition of 'int main()' Feb 03, 2010, 07:53

Error Redefinition Of Default Argument

pm i keep getting this error in my code during verify/compile:Quote" In function 'int main()':error: redefinition of 'int main()' "am supposed to doing an alarmclock/stopwatch type of http://stackoverflow.com/questions/30671479/redefinition-of-main deal...and i was trying to get the code to compile and run so that i can test if it's adding and subtracting correctly, and make sure i coded my interrupts to work correctly, and figure out how i can control lines on a serial lcd i am about to connect.***PLUS*** i apologize for all of the http://forum.arduino.cc/index.php?topic=43125.0 volatile declarations, but the compiler would not let me NOT declare it again within the voids.Code: [Select]#include
#include
#include
#include

volatile int trigger1;
volatile int trigger2;
volatile int mode;
volatile int second;
volatile int second1;
volatile int second2;
volatile int second3;
volatile int minute;
volatile int minute1;
volatile int minute2;
volatile int minute3;
volatile int hour;
volatile int hour1;
volatile int hour2;
volatile int hour3;
int test_t;

void setup()
{
 pinMode(2, INPUT);          //Make digital 2 an input
   digitalWrite(2, HIGH);   // Enable pull up resistor
 pinMode(3, INPUT);        //  Make digital 3 an input
   digitalWrite(3, HIGH); //   Enable pull up resistor
 // Setup Interrupt 0, pin 2
 attachInterrupt(0, i_Zero, RISING);
 // Setup Interrupt 1, pin 3
 attachInterrupt(1, i_One, RISING);  
 interrupts();
 volatile int trigger1;
 volatile int trigger2;
 trigger1=0;
 trigger2=0;
}

void i_Zero()
{
 volatile int trigger

browser that supports JavaScript, or enable it if it's disabled (i.e. NoScript). Home OJ Reverse Words in a String Submit with C code, got error https://leetcode.com/discuss/11131/submit-with-c-code-got-error-redefine-main-function redefine main function" Submit with C code, got error redefine main function" browsing This topic has been deleted. Only users with topic management privileges can see it. 0 Y yunhua Reputation: https://www.quora.com/The-following-code-is-not-giving-an-error-of-redefinition-of-a-instead-it-is-only-giving-%E2%80%98a%E2%80%99-undeclared-as-an-error-Why-It-should-also-give-redefinition-of-a-as-an-error-Edit-Please-look-at-second-code 4 #include #include char input[] = "the sky is blue "; char output[128]; int main() { char *pe = input + strlen(input)-1; char *p = NULL, *t; int idx error redefinition = 0; while (pe != input) { if (*pe == ' ' || *pe == '\t') { pe--; continue; } p = pe; while (*(p-1) != ' ' && *(p-1) != '\t' && p != input) { p--; } t = p; while (t <= pe) { output[idx++] = *t++; } output[idx++] = ' '; if (p != input) pe = error redefinition of p-1; else break; } output[idx] = '\0'; printf("%s\n", output); return 0; } last edited by Reply Quote 0 M mike3 Reputation: 851 C is not a valid language for solutions on this site. Only Java, C++, and Python are currently available. This exclusion is necessary because the tester uses objects to take the solution and run it through all of its tests. C is not an object oriented language, so it is unlikely to be added anytime soon. Another issue here is that the main() method is the entry point for a compiler to run the program. By adding one of your own, the compiler doesn't know which main method to use. However, this shouldn't be an issue at all. The tester requires that you start your program with the method provided, in this case, void reverseWords(string &s). Without that, there is no way to the tester to enter your program, and so would always fail it. last edited by Reply Quote Loading More Posts 2 Posts 751 Views Reply Reply as topic Log in to reply Back To Leetcode 1 / 1

an error of" redefinition of a" instead it is only giving "‘a’ undeclared" as an error. Why? It should also give redefinition of 'a' as an error. Edit: Please look at second code.#include int main() { int i; for (i = 0;i < 5; i++) int a = i; printf("%d", a); return 0; }@http://ideone.com/x0OWae#include int main() { int i; for (i = 0;i < 5; i++) int a = i;//Why not here, as this loop is also defining a multiple times int a=3; int a=4;//Gives redefinition error return 0; }@http://ideone.com/Uy5R9KUpdateCancelAnswer Wiki5 Answers Niroj Pokhrel, Love it.Written 157w agoFirst: for(i =0; i<5;i++) int a=i; printf("%d",a); Here, a is defined in the scope of for loop only so you cannot access it outside the for loop. So, undeclared error comes in this case.Second: for(i =0; i<5;i++) int a=i; Here, a is declared once and it is not declared every execution of the for loop. So, you won't get a redefinition error.int a=3; int a=4; Here you are declaring it twice so redefinition error.If you write,for(i =0; i<5;i++) int a=i; int a; then it will be perfectly fine.448 Views · View UpvotesRelated QuestionsMore Answers BelowIn the following two code examples why is the first example giving an error, but not the second?Why doesn't the following Java code give any compilation error?Why is the following code giving a form error?Why does the following code give a runtime error?Why is the following code giving a run time error? Arshad Feeroz, Programmer , Student , techieWritten 132w agoThe scope of a loop is confined only till the next line if there are no blocks { } used with the loop. Here, the scope of for loop lies only till line number 2.for (i = 0;i < 5; i++) int a = i; printf("%d", a);In this case, 'a' is declared inside the for loop scope , and cannot be used outside the scope of for loop . printf("%d",a) lies outside the for loop scope , that is why the compiler does not recognise 'a' here and gives a declaration error. for (i = 0;i < 5; i++) int a = i;//Why not here, as this loop is also defining a multiple times int a=3; int a=4;//Gives redefinition errorHere, int a=i; lies in the for loop scope -- NO ERRORint a=3; it lies outside the for loop scope and can be declared without any error. Coz the first 'a' was inside for loop and this 'a' is declared outside the for loop(in the scope of main(). therefore , NO ERROR.int a=4; Here 'a' cant be declar

 

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