Mysql Error Code 1022
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Error: Error 1215: Cannot Add Foreign Key Constraint
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Can't write; duplicate key in table up vote 77 down vote favorite 7 I'm getting a 1022 error regarding duplicate keys on create table command. Having looked at the query, I can't understand where the duplication is taking place. Can anyone else see it? SQL query: -- ----------------------------------------------------- -- Table `apptwo`.`usercircle` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `apptwo`.`usercircle` ( `idUserCircle` MEDIUMINT NOT NULL ,
Mysql Add Constraint Foreign Key
`userId` MEDIUMINT NULL , `circleId` MEDIUMINT NULL , `authUser` BINARY NULL , `authOwner` BINARY NULL , `startDate` DATETIME NULL , `endDate` DATETIME NULL , PRIMARY KEY ( `idUserCircle` ) , INDEX `iduser_idx` ( `userId` ASC ) , INDEX `idcategory_idx` ( `circleId` ASC ) , CONSTRAINT `iduser` FOREIGN KEY ( `userId` ) REFERENCES `apptwo`.`user` ( `idUser` ) ON DELETE NO ACTION ON UPDATE NO ACTION , CONSTRAINT `idcategory` FOREIGN KEY ( `circleId` ) REFERENCES `apptwo`.`circle` ( `idCircle` ) ON DELETE NO ACTION ON UPDATE NO ACTION ) ENGINE = INNODB; MySQL said: Documentation #1022 - Can't write; duplicate key in table 'usercircle' mysql share|improve this question edited Aug 5 '13 at 11:48 Prix 14.1k939100 asked Aug 5 '13 at 11:13 Git-able 4221410 4 If I remember correctly, the primary key is always also a UNIQUE INDEX, so you would have to drop the unique index statement? –Mr47 Aug 5 '13 at 11:15 Thanks for the tip! –Git-able Aug 5 '13 at 11:42 1 ON DELETE NO ACTION would just drop the entire use of the foreign key. Unless you have very specific reasons to do that. –AmazingDreams Aug 5
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Mysql Constraint
Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads mysql drop foreign key with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million http://stackoverflow.com/questions/18056786/error-1022-cant-write-duplicate-key-in-table programmers, just like you, helping each other. Join them; it only takes a minute: Sign up mysql error code 1022 duplicate key in table up vote 1 down vote favorite I searched through the prior posts but didn't quite find the answer, so here it goes ... I have this table CREATE TABLE `leags` ( http://stackoverflow.com/questions/18985789/mysql-error-code-1022-duplicate-key-in-table `lid` int(10) NOT NULL AUTO_INCREMENT, `lName` varchar(255) NOT NULL, `description` varchar(255) DEFAULT NULL, `links` varchar(255) DEFAULT NULL, `cid` int(10) NOT NULL, PRIMARY KEY (`lid`), KEY `index2` (`lid`,`lName`), KEY `index3` (`lid`,`lName`,`cid`), KEY `cid_idx` (`cid`), CONSTRAINT `cid` FOREIGN KEY (`cid`) REFERENCES `cats` (`cid`) ) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8 COMMENT='Leagues'$$ I have another table that has the above PK as a foreign key. CREATE TABLE `tams` ( `tId` INT(10) NOT NULL , `tName` VARCHAR(255) NOT NULL , `lid` INT(10) NULL , `url` TEXT NULL , PRIMARY KEY (`tId`) , INDEX `index2` (`tId` ASC, `tName` ASC) , INDEX `index3` (`tId` ASC, `tName` ASC, `lid` ASC) , INDEX `lid_idx` (`lid` ASC) , CONSTRAINT `lid` FOREIGN KEY (`lid` ) REFERENCES leags` (`lid` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB The creation of this table works fine, but I run into a problem creating the below table. CREATE TABLE IF NOT EXISTS spSched ( `spscId` INT(10) NOT NULL AUTO_INCREMENT , `startDate` DATE NOT NULL , `endD
Jenkins Liferay Maven MySQL Outlook Ruby on Rails SQL Server sqlite3 Uncategorized slf4j Websphere Blogroll Development Blog Documentation Plugins Suggest http://techmajik.com/2014/01/03/how-to-resolve-mysql-error-code-1022/ Ideas Support Forum Themes WordPress Planet Meta Log in RSS Comments RSS ← Sidebar Jan/143 How to resolve mysql error code 1022? No comments · Posted by admin in MySQL MySQL CREATE TABLE statement throws error code 1022 with following message: "Error Code: 1022 Can't write; duplicate key in table [ Your table name ]". To foreign key solve this please ensure you have unique key name assigned across indexes and foreign key names. So if you have Person, Address and PersonAddress tables with foreign keys associated with Address table. Then define unique values for index keys and foreign keys. Person table -> AddressId [ FK ] -> Address Table [ PK ] so foreign key constraint name address id to "fk_addressid_address" PersonAddress table -> AddressId [ FK ], PersonID [ FK] so name address id to "fk_addressid_person" and name person id to "fk_personid_person". As you can see now FK addressid named uniquely across your tables. This will resolve mysql error code 1022 issue. No tags No comments yet. Leave a Reply Click here to cancel reply. Name* Mail* (will not be published) Website Your Comment − 6 = three << How to put django-admin.py in system path? How to use an existing database with Django >> Find it! Theme Design by devolux.nh2.me Tag Cloud ArrayList Builds Collection common io D-link 868L Django Eclipse Excel Installation JAVA Jenkins Liferay logging MACRO Merge PDFs Out of Memory PDFMerger Rails Router Ruby Ruby on Rails SBG6580 Scanner Set SQL sqlite3 SQL Server SQL Server Import Export subList Wordpress Archives March 2015 February 2015 January 2015 December 2014 November 2014 August 2014 July 2014 April 2014 January 2014 December 2013 May 2013 February 2013 To top