Error Ambiguous Overloading Causes Type Ambiguity
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Ambiguity In Function Overloading In C++
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Ambiguity Error In C++
each other. Join them; it only takes a minute: Sign up c++ function overload ambiguous up vote 0 down vote favorite in c++ void foo(int i) { std::cout<<"int"< error. in visual-studio 2008, the error is C2668:'function' : ambiguous call to overloaded function i know why this problem occur and i know a solution that using-time typecast. but i think this is not a good solution because using this way is kill the lexicality of function overloading. in my project, i making a lexical-object that change auto type to int,float,std::basic_string and function pointer. overload all typecast operator and creator. but when i input a 'NULL', the error C2668 occurs. in fact it is almost no problem . the only serious problem is when using FALSE. my project is core library and so i can't guide every end-client programmer. who knows the trick or tip of solve this problem more smart way? c++ operator-overloading method-overloading lexical share|improve this question edited May 6 '12 at 17:14 Mat 135k21234273 asked May 6 '12 at 13:59 user1101221 60111 This compiles fine on gcc 4.5. –mfontanini May 6 '12 at 14:03 If this is your real code then report a compiler called. Possible causes and solutions are discussed here. Contents 1 Ambiguous Overloaded Functions 1.1 Example: 2 Ambiguous Constructors or Conversion Operators 2.1 Example: 3 Ambiguous Namespace overloaded function be ambiguous or Unit Scope Names 3.1 Example: 3.2 Example: 3.3 Example: 4 See Also Ambiguous Overloaded Functions If the functions are overloaded, and more than one function definition can be used difference between function and method with the supplied parameters, this error is emitted. To resolve the ambiguity, modify the type of the parameters so that the compiler can identify what function is called. Example: void http://stackoverflow.com/questions/10471085/c-function-overload-ambiguous foo(short); // #1 void foo(char); // #2 int I; foo(i); // error: ambiguous foo((char)i); // picks #2 Ambiguous Constructors or Conversion Operators One possible solution is to make the constructor and/or operator explicit using the keyword explicit. Example: struct A { A(const A&); A(const wchar_t*); }; struct B { operator A(); explicit operator wchar_t*(); }; int main() { B http://docwiki.embarcadero.com/RADStudio/Berlin/en/E2015_Ambiguity_between_'function1'_and_'function2'_(C%2B%2B) v; A s(v); // ok (since operator wchar is explicit) } Ambiguous Namespace or Unit Scope Names Ambiguity results if the functions are declared in different namespaces that are used simultaneously. To resolve the ambiguity, specify the namespace of the function to be called. (See the scope resolution operator and Unit Scope Names.) Example: struct A { void foo(); }; // #1 struct B { void foo(); }; // #2 struct C: A, B { void callfoo() { foo(); //error: ambiguous B::foo(); // picks #2 } }; Example: [BCC32 Error] Unit4.cpp(19): E2015 Ambiguity between '_fastcall Fmx::Printer::Printer()' and 'Fmx::Printer' This is "As Designed" because there is both a namespace and a function named Printer in scope. To fix the source, you should write: void __fastcall TForm4::FormCreate(TObject *Sender) { Fmx::Printer::Printer()->BeginDoc(); } Example: namespace Ns { namespace Foo { void Foo() {} } } Using namespace Ns::Foo; Using namespace Ns; void Bar { Foo(); // error! Which Foo? // should instead be Ns::Foo::Foo(); } See Also namespace (keyword) Explicit Access Qualification C++ Applications Use STRICT Type Checking Resolving Ambiguities: 'Byte' and 'S called as an ambiguity in function overloading. When the program contains ambiguity, the compiler will not compile the program. The main cause of ambiguity in the program · Type conversion · Functions with default arguments · Functions with http://ramperi.org/ambiguity.htm pass by reference Type conversion #include a) a different number of arguments or, b) different types of arguments or, c) both - Overloaded functions can be... a) Standard functions (not as members of a class) b) Class member functions (methods and constructors) c) Operator functions (as we'll see later) - Overloading allows function calls to the same name to respond differently depending on the parameter types - Overloading, as we'll see later, plays a key role in OO features such as inheritance and polymorphism - Consider the following example with overloaded standard functions #include Ambiguity Error In Function Overloading In C++
How Can A Call To An Overloaded Function Be Ambiguous