Python Cv Error
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Error (-215) Scn == 3 Scn == 4 In Function Cvtcolor Python
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Error: (-215) Scn == 3 || Scn == 4 In Function Cvtcolor C++
takes a minute: Sign up How to catch “OpenCV Error” in Python up vote 5 down vote favorite 1 If I get OpenCV Error: ... what's the syntax to catch it since OpenCV Error uses two words? I'm able to catch the following cv.error but how would I catch this? EDIT: I don't get it... is the answer obvious? Am I error: (-215) !empty() in function cv::cascadeclassifier::detectmultiscale being unclear? EDIT 2 I can't reproduce it b/c I'm on a different computer but it looked similar to: OpenCV Error: Bad argument. Something something array cv.error: This is another error I'm able to catch cv.error but not OpenCV Error with the following: try: # do a thing except (cv.error, OpenCV Error): print "Can't do the thing" sys.exit(1) python opencv share|improve this question edited Jan 16 '12 at 0:46 asked Jan 15 '12 at 21:49 user1136342 92341527 What is the exception raised when you run into this OpenCV Error? –Makoto Jan 15 '12 at 22:44 Yes, you're being very unclear. Please explain your problem more clearly. Unfortunately I can't tell you specifically what you should improve in your question, because I don't understand it at all. –Petr Viktorin Jan 15 '12 at 22:47 Post the traceback, and if possible the exceptional code –wim Jan 15 '12 at 22:53 2 Some OpenCV functions don't throw errors, they print out a message and exit the program (either with exit or abort, I can't remember). In ot
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Cv2 Cvtcolor Error
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Error: (-215) Scn == 3 || Scn == 4 In Function Ipp_cvtcolor
company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users error: (-215) !empty() in function detectmultiscale Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes http://stackoverflow.com/questions/8873657/how-to-catch-opencv-error-in-python a minute: Sign up value error in python cv up vote 1 down vote favorite I am trying to change black pattern in a monochrome 3 channel QR to any another color but I am getting this error all the time if k.any()==[0,0,0]: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() http://stackoverflow.com/questions/36421916/value-error-in-python-cv code I am trying is given below: import cv2 import numpy as np img = cv2.imread('C:/New folder (2)/new1.png') rows,cols,bands = img.shape print rows,cols,bands for i in xrange (rows): for j in xrange (cols): k = img[i,j] if k.any()==[0,0,0]: img[i,j]==[255,255,255] cv2.imshow('r',r) cv2.waitKey(0) The image which I am using is attached below. Please help me to get out of this. QR Image python opencv qr-code share|improve this question edited Apr 5 at 19:15 tfv 2,1051634 asked Apr 5 at 9:11 Priya 235 add a comment| 2 Answers 2 active oldest votes up vote 0 down vote accepted While I have corrected your indentation errors in your post, you had two minor errors: 1.) Wrong syntax for np.any() 2.) Assigning the new pixel value, you did a comparison instead, which had no effect on the value. Corrected code with comments is attached: import cv2 import numpy as np img = cv2.imread('image.png') rows,cols,bands = img.shape print rows,cols,bands for i in xrange (rows): for j in xrange (cols): k = img[i,j] #corrected syntax for comparison of multiple components if np.all(k==[0,0,0]): # Use = instead of == i
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