Cakephp Ajax Internal Server Error
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just like you, helping each other. Join them; it only takes a minute: Sign up CakePHP Ajax Request not going Internal Server Error up vote 0 down vote favorite I am just trying to test ajax form submit in CakePhp. I have below written code. But ajax is not working. Error in chrome : POST http://localhost/john/Frontends/AjaxFormSubmit joomla internal server error 500 (Internal Server Error) View File echo $this->Form->input('appendedInputButton', array('id'=>'url','name' => 'AjaxFormSubmit', 'type' => 'text')); echo $this->Form->button('Convert', array('id' => 'Convert', 'type' => 'button')); jQuery $(document).ready(function () { $('#Convert').on({ 'click': function () { var urlVal = $("#url").val(); if (urlVal == '' || urlVal == 0) { $("#url").focus(); return false; } $.ajax({ url: 'http://localhost/john/Frontends/AjaxFormSubmit', cache: false, type: 'POST', success: function (data) { alert(data); } }); } }); }); Controller App::uses('AppController', 'Controller'); class FrontendsController extends AppController { public $name = 'Frontends'; public $uses = array(); public $components = array('RequestHandler'); public $helpers = array('Html', 'Form'); public function index() { $this - > layout = 'frontend_index_layout'; } public function AjaxFormSubmit() { echo "Receiving Via Ajax"; } } Error Log File 2013-08-13 13:41:43 Error: [MissingControllerException] Controller class JsController could not be found. Exception Attributes: array ( 'class' => 'JsController', 'plugin' => NULL, ) Request URL: /john/js/jquery-1.10.1.min.map Stack Trace: #0 G:\wamp\www\john\app\webroot\index.php(111): Dispatcher->dispatch(Object(CakeRequest), Object(CakeResponse)) #1 {main} 2013-08-13 13:42:01 Error: [MissingViewException] View file "G:\wamp\www\john\app\View\Frontends\Ajax_Form_Submit.ctp" is missing. Exception Attributes: array ( 'file' => 'G:\\wamp\\www\\john\\app\\View\\Frontends\\Ajax_Form_Submit.ctp', ) Requ
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up 500 Internal server error http://stackoverflow.com/questions/18210679/cakephp-ajax-request-not-going-internal-server-error in cakePHP 2 while trying to request using ajax up vote 0 down vote favorite I get 500 internal server error if try get data from another Model(Product) in Cart model. using ajax. But if I only comment out the $this->Product->findBy(id) is working fine. $('form#add_form').on('submit', function(e){ var thisForm = $(this); $.ajax({ url: thisForm.attr('action'), type: 'POST', //dataType: 'json', data: thisForm.serialize(), success: function(count) { var total_items = $('p#total-items'); http://stackoverflow.com/questions/33931156/500-internal-server-error-in-cakephp-2-while-trying-to-request-using-ajax total_items.html('Total items: ' + count); console.log(count); } }); e.preventDefault(); }); this is my CartsController class CartsController extends AppController { public $uses = array('Product', 'Cart'); public function add() { $this->autoRender = false; $itemsInCart = $this->Session->read(); if ($this->request->is('POST')) { $item = $this->Product->findBy($this->request->data['Cart']['product_id']); } echo $this->request->data['Cart']['product_id']; } } ajax cakephp cakephp-2.0 share|improve this question asked Nov 26 '15 at 5:26 PHP.Newbie 6010 1 There is no findby method, you have to specify what are you finding by :) –skywalker Nov 26 '15 at 7:15 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote there is no findBy method You must change your controller code like this: class CartsController extends AppController { public $uses = array('Product', 'Cart'); public function add() { $this->autoRender = false; $itemsInCart = $this->Session->read(); if ($this->request->is('POST')) { $productID = $this->request->data['Cart']['product_id']; $item = $this->Product->findById($productID); } echo json_encode($this->request->data['Cart']['product_id']); } } share|improve this answer edited Nov 27 '15 at 8:44 answered Nov 26 '15 at 15:17 Malik Perang 171110 still getting same error sir. –PHP.Newbie Nov 27 '15 at 8:26 Code updated,please try. –Malik Perang Nov 27 '15 at 8:45 error still occurs. Sir but
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more http://stackoverflow.com/questions/11585620/ajax-error-handling-in-cakephp about Stack Overflow the company Business Learn more about hiring developers or posting https://github.com/cakephp/cakephp/issues/8174 ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Ajax error handling in CakePHP up vote 7 down vote favorite internal server 4 I want to do something very similar to this but in the CakePHP world for AJAX requests. At the moment I am doing this: $this->autoRender = false; $this->response->statusCode(500); It is based off of this. However this solution does not allow me to include a custom message like in the Rails example, so that way, in my clients side error handler, I can display the message included in the internal server error 500 error response. How would I implement the same functionality in CakePHP like the Ruby on Rails example? php ajax cakephp error-handling share|improve this question edited Aug 9 at 14:32 lorem monkey 2,06622137 asked Jul 20 '12 at 19:14 paul smith 57211120 add a comment| 3 Answers 3 active oldest votes up vote 0 down vote accepted You can use CakeExceptions as explained in the Cookbook: http://book.cakephp.org/2.0/en/development/exceptions.html BUT if you want to use your custom messages I found no other way than using debug = 1 in your production mode :( Here's my approach with built in methods: In your controller: if($this->request->is('ajax')){ Configure::write('debug', 1); } if(!$allowed) { throw new InternalErrorException('Keep your fingers away from me!'); // 500 error } Change the error template to output nothing but the error when used in AJAX calls in /app/View/Errors/error500.ctp: request->is('ajax')): // Output for AJAX calls echo $name; else: //Standard CakePHP output ?>
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0 ): echo $this->element('exception_stack_trace'); endif; endif; ?> You can then parse the returned text in your AJAX. Here's the jQuery parts I use: //... error: function (request) { yourErrorShowingFuncSupport Search GitHub This repository Watch 658 Star 6,736 Fork 3,047 cakephp/cakephp Code Issues 159 Pull requests 23 Projects 0 Wiki Pulse Graphs New issue 500 internal server error when sending email with cakephp 3 ajax #8174 Closed Bahhous opened this Issue Feb 3, 2016 · 1 comment Projects None yet Labels Invalid Milestone 3.2.2 Assignees No one assigned 2 participants Bahhous commented Feb 3, 2016 No description provided. Bahhous changed the title from 500 internal server error when sending email with cakephp ajax to 500 internal server error when sending email with cakephp 3 ajax Feb 3, 2016 CakePHP member ADmad commented Feb 3, 2016 Please no info on how to reproduce issue nothing can be done. ADmad closed this Feb 3, 2016 ADmad added this to the 3.2.2 milestone Feb 3, 2016 ADmad added the Invalid label Feb 3, 2016 Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment Contact GitHub API Training Shop Blog About © 2016 GitHub, Inc. Terms Privacy Security Status Help You can't perform that action at this time. You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Reload to refresh your session.