Error 10022 Python
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Socket.error Errno 10022 An Invalid Argument Was Supplied
Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs python winerror 10022 Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join socket error invalid argument them; it only takes a minute: Sign up socket.error errno=10022 when using socket.send(packet, (ip, port)) up vote 0 down vote favorite I learned to send packet using socket by Python, but there is an error (socket.error errno=10022) when running the code below on the Windows machine, and everything works fine on the Linux. How can I fix it? try: s
Python Socket.accept Errno 22
= socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP) except socket.error , msg: print 'Socket could not be created. Error Code : ' + str(msg[0]) + ' Message ' + msg[1] sys.exit() s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1) source_ip = self.source dest_ip = self.destination packet = ''; ip_header = self.construct_ip_header() tcp_header = self.construct_tcp_header() packet = ip_header + tcp_header s.sendto(packet, (dest_ip , 0 )) python sockets share|improve this question asked Sep 15 '15 at 15:30 lixiaoyu 230416 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote Error 10022 from Winsock means "Invalid argument" possibly because you're trying to mix SOCK_RAW with IPPROTO_TCP which are incompatible. The third argument is probably being ignored on linux, but windows is complaining about it. Something is also very wrong with your code sample - you've tried to open a raw socket, but are manually writing tcp and ip headers, but not handling the TCP state machine yourself? This seems highly overcomplicated unless you have some very specialist requirements. If you're just trying to open a TCP socket between this code and a server I
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta [winerror 10022] an invalid argument was supplied Discuss the workings and policies of this site About Us Learn python socket connect invalid argument more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us
Setsockopt Python
Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like http://stackoverflow.com/questions/32590031/socket-error-errno-10022-when-using-socket-sendpacket-ip-port you, helping each other. Join them; it only takes a minute: Sign up Python select.select() error 10022 on windows up vote 3 down vote favorite 1 I got class (subclassed from QThread), that recieve data from server at many sockets by select.select(): # -*- coding: utf-8 -*- from PyQt4.QtCore import QThread, pyqtSignal import json import select class http://stackoverflow.com/questions/7103182/python-select-select-error-10022-on-windows MainSocketThread(QThread) : disconnected_by_admin = pyqtSignal() disconnected_by_network = pyqtSignal(bool) def __init__(self, connects_dict=None) : QThread.__init__(self) self.connects = connects_dict if not self.connects: self.connects={} def run(self) : try: while 1 : inputready, outputready, exceptready = select.select(self.connects.keys(), [], []) for s in inputready : try : data = self.s_[s].recv(4096) if not data : s.close() self.connects.pop(s) else : cmd = json.loads(data) print s, cmd, 'asd' # ProcessCommand(s, cmd) except Exception as e: s.close() self.connects.pop(s) except Exception as e: print e self.disconnected_by_network.emit(False) self.exec_() And that's how i create socket(in other class) : self.connections_dict = {} self.main_socket_thread = MainSocketThread(self.connections_dict) if not self.s : try: self.s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) self.s.connect((host, port)) except Exception as e: print e, e.__class__() self.display_connection_status(False) else: self.connections_dict[self.s] = self self.main_socket_thread.start() self.s.send(json.dumps({'command': 'operator_insite', 'login': self.settings_dict['login'], 'password': hashlib.md5(self.settings_dict['password']).hexdigest()})) self.display_connection_status(True) But i got select.error 10022 every time trying to select from sockets. What is wrong with my code? python sockets pyqt share|improve this question asked Aug 18 '11 at 6:19 Andrewshkovskii 3111417 add a comment| 3 Answers 3 active oldest votes up vote 0 down vote are
SQL Server 2014 Express resources Windows Server 2012 resources Programs MSDN subscriptions Overview Benefits Administrators Students Microsoft Imagine Microsoft Student Partners ISV Startups TechRewards Events Community Magazine Forums Blogs Channel 9 Documentation APIs and reference https://social.msdn.microsoft.com/Forums/en-US/3076a9cd-57a0-418d-8de1-07adc3b486bb/socket-fails-with-error-10022-when-application-is-run-from-certain-network-shares-on-vista-and?forum=wsk Dev centers Retired content Samples We’re sorry. The content you requested has been http://www.dreamincode.net/forums/topic/351094-problems-with-client-in-a-simple-serverclient-set-up/ removed. You’ll be auto redirected in 1 second. Ask a question Quick access Forums home Browse forums users FAQ Search related threads Remove From My Forums Answered by: socket() fails with error 10022 when application is run from certain network shares on Vista and Windows 7 (works on XP) Windows Desktop invalid argument Development > Windows Desktop Winsock Kernel (WSK) Question 0 Sign in to vote Hi, We've run into a strange problem where our network application runs fine from most network shares, but fails on a particular one. The socket() function returns an 10022 (WSAEINVAL) error when this occurs. It runs fine locally and on most network shares. Here's a sample program that causes the an invalid argument error: #include "stdafx.h" #include
(2 Pages) 1 2 → New Topic/Question Reply 18 Replies - 2953 Views - Last Post: 30 July 2014 - 04:33 AM Rate Topic: #1 DK3250 D.I.C Addict Reputation: 176 Posts: 611 Joined: 27-December 13 Problems with client in a simple server/client set-up Posted 27 July 2014 - 09:17 AM Based on litterature I've made two small programs, a server and a client. The server seems to run fine, but when running the client I get an error massage. The code was written for Python 2.7 and has been modified (by me) to run Python 3.3 I use IDLE as editor and console. The server code: ' import socket, sys host = socket.gethostname() data_payload = 2048 backlog = 5 def echo_server(port): sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) server_address = (host, port) print("Starting up echo server on ", server_address, " port %s" %sock.bind(server_address)) sock.listen(backlog) while True: print("Waiting to receive message from client") client, address = sock.accept() data = client.recv(data_payload) if data: print("Data : %s" %data) client.send(data) print("Send ", data, " bytes back to %s" %address) client.close() echo_server(9900) The client code: import socket, sys host = '127.0.0.1' def echo_client(port): sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) server_address = (host, port) print("Connecting to %s port %s" %server_address) sock.connect(server_address) try: message = "Test message. This will be echoed" print("Sennding %s" % message) sock.sendall(message) amount_received = 0 amount_expected = len(message) while amount_received < amount_expected: data = sock.recv(16) amount_received += len(data) print("Received : %s" % data) except (socket.errno, e): print("Sockert error: %s" %str(e)) except (Exception, e): print("Other exception: %s" %str(e)) finally: print("Closing connection to server") sock.close() echo_client(9900) .. and the error message upon running the client: Traceback (most recent call last): File "C:\Python33\Client.py", line 29, in