Error Invalid Type Of Argument Of Unary

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Error Invalid Type Argument Of Unary ‘*’ (have ‘double’)

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Error Invalid Type Argument Of Unary ‘*’ (have ‘int’)

programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error: invalid type argument of ‘unary *’ (have ‘int’) up vote 20 down vote favorite 7 I have a C

Error Invalid Type Argument Of Unary '*' (have 'int')

Program: #include int main(){ int b = 10; //assign the integer 10 to variable 'b' int *a; //declare a pointer to an integer 'a' a=(int *)&b; //Get the memory location of variable 'b' cast it //to an int pointer and assign it to pointer 'a' int *c; //declare a pointer to an integer 'c' c=(int *)&a; //Get the memory location of variable 'a' which is //a pointer to 'b'. Cast that to an error invalid type argument of unary '*' (have 'char') int pointer //and assign it to pointer 'c'. printf("%d",(**c)); //ERROR HAPPENS HERE. return 0; } Compiler produces an error: error: invalid type argument of ‘unary *’ (have ‘int’) Can someone explain what this error means? c pointers share|improve this question edited Sep 30 '13 at 19:23 Eric Leschinski 46.4k23221190 asked Mar 28 '11 at 7:30 picstand 112127 add a comment| 4 Answers 4 active oldest votes up vote 14 down vote accepted Since c is holding the address of an integer pointer, its type should be int**: int **c; c = &a; The entire program becomes: #include int main(){ int b=10; int *a; a=&b; int **c; c=&a; printf("%d",(**c)); //successfully prints 10 return 0; } share|improve this answer edited Sep 30 '13 at 19:24 Eric Leschinski 46.4k23221190 answered Mar 28 '11 at 7:41 codaddict 251k50362442 3 Also note the lack of casts in the answer. The casts in the question hide the problems on the line that is assigning an int ** to a int *. (c=(int *)&a;) –Thanatos Sep 30 '13 at 22:54 add a comment| up vote 8 down vote Barebones C program to produce the above error: #include using namespace std; int main(){ char *p; *p = 'c'; cout << *p[0]; //error: invalid type argument of `unary *' //peeking too deeply into p

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about invalid type argument of unary ‘*’ (have ‘float’) Stack Overflow the company Business Learn more about hiring developers or posting ads invalid type argument of unary '*' (have 'float') with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow invalid type argument of unary '*' (have 'double') is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Pointers ABC. error: invalid type argument of unary ‘*’ (have ‘struct config’) up http://stackoverflow.com/questions/5455866/error-invalid-type-argument-of-unary-have-int vote 2 down vote favorite I have a basic problem. I should know enough about pointers by now. The way I see it configData is the first link in a linked list (of the type struct config) while procNames is a pointer to the first link in a linked list of the type struct config. So if I want to say that procNames is equal to configData then I need http://stackoverflow.com/questions/9559957/pointers-abc-error-invalid-type-argument-of-unary-have-struct-config to access the pointer that points to configData which is *configData. Anyhow I think I am missing something. Anyone sees the problem? Also, I get the next error: error: invalid type argument of unary ‘*’ (have ‘struct config’) struct config_line { char name[MAX_WORD]; int time; }; struct config { struct config_line *lines; int count; }; //global variable struct config configData; //local variable struct config *procNames; //the problem (done locally) procNames = *configData; c pointers struct linked-list share|improve this question edited Mar 4 '12 at 23:50 caf 155k14192324 asked Mar 4 '12 at 23:39 Paul Kar. 5102923 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted I think you want procNames = &configData; This sets the pointer procNames to the address of the structure configData. You can access the elements using either procNames->count procNames->lines[i].name // Pointer to the 1st char of the name in the i'th config_line structure or configData.count configData.lines[i].name Remember that, since lines is itself a pointer, you'll need to allocate memory for each config_line structure: struct config_line thisLine; // Declare a structure procNames->lines = &thisLine; // Point to it or // Declare a pointer to an array of structures, allocate memory for the structures struct config_line *linePtr = mal

Programming Boards C Programming Invalid type of unary '*' Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get http://cboard.cprogramming.com/c-programming/123366-invalid-type-unary-*.html a compiler | Fixes for common problems Thread: Invalid type of unary '*' Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded https://bytes.com/topic/c/answers/950228-invalid-type-argument-unary Mode 01-23-2010 #1 trishaxxcore View Profile View Forum Posts Registered User Join Date Jan 2010 Posts 3 Invalid type of unary '*' Good day! I'm having problems with my lab activity(which I can't find the invalid type solution), it's already graded but I have to finish it and to make it function. Is there something wrong with the way I reallocated space? Please help me find the solution for this. I have problems during compile time, it says: invalid type argument of unary '*' Code: int getInputs(int **ptr) { int x, w; int i=0; int y=0; int *pTemp; *ptr = malloc(sizeof(int)*10); do { print("enter number here:"); argument of unary scanf("%d", &x); if (i<10) { if(x>0) { *(*ptr + i) = x; i++; y++; } else if(x==0) { *(*ptr + i) = x; i++; } } else { w=i++; if(x>0) { pTemp = realloc(ptr, sizeof (int) * 10); *(*pTemp + w ) = x; // invalid type argument of unary '*' y++; w++; } else if(x==0) { *(*pTemp + w ) = x; // invalid type argument of unary '*' w++; } } }while(x>=0); return y; } PS. 01-23-2010 #2 Memloop View Profile View Forum Posts Registered User Join Date Mar 2009 Posts 399 Change it to: Code: *(pTemp + w ) 01-23-2010 #3 trishaxxcore View Profile View Forum Posts Registered User Join Date Jan 2010 Posts 3 Originally Posted by Memloop Change it to: Code: *(pTemp + w ) I already changed it that way. It now says [Linker Error]:Undefined reference to print. 1d returned 1 exit status. 01-23-2010 #4 Memloop View Profile View Forum Posts Registered User Join Date Mar 2009 Posts 399 There's no "print" function in standard C. Use puts or printf. 01-23-2010 #5 trishaxxcore View Profile View Forum Posts Registered User Join Date Jan 2010 Posts 3 Originally Posted by Memloop There's no "print" function in standard C. Use puts or p

question and get tips & solutions from a community of 418,513 IT Pros & Developers. It's quick & easy. invalid type argument of `unary *' P: 1 nsbcnjsbc What's wrong?here's the code Expand|Select|Wrap|Line Numbers #include #include #definepi3.141592; intmain(void) { floatradium,diameter,perimeter,area; printf("pleaseinputradium："); scanf("%f",&radium); diameter=2.0*radium; perimeter=2.0*radium*pi; area=radium*pi*radium; printf("thediameter：%f\ntheperimeter：%f\nthearea%f\n",diameter,perimeter,area); system("PAUSE"); return0; } Jun 28 '13 #1 Post Reply Share this Question 1 Reply Expert Mod 5K+ P: 8,916 Banfa The problem is not with the * operator, it can be chained as it is at line 13 if all the operands are variables or constants. The problem all the operands are not variables or constants because at line 3 you have put a semi-colon at the end of your definition of pi which means that after preprocessing line 13 looks like this Expand|Select|Wrap|Line Numbers area=radium*3.141592;*radium; With the extra ; the second * forms part of a second expression and it only has 1 operand so it is treated as the unary dereference operator, this operator operates on pointers and radium is a float so you get the error [i]error: invalid type argument of unary '*' (have 'float')/I] Remove the ; from line 3 Jun 28 '13 #2 reply Message Cancel Changes Post your reply Join Now >> Sign in to post your reply or Sign up for a free account. Similar topics invalid type argument of 'unary*' invalid type argument of ‘unary *’ (have ‘int’) type argument in OpenRecordset method SFINAE -- basis: array of void is invalid type invalid operands to binary == or wrong type argument to unary exclamation mark invalid lvalue in unary `&' invalid lvalue in unary '&' .... why LKM invalid type argument of '->' pointer-to-pointer (invalid lvalue in unary `&) Local class instances invalid template argument Browse more C / C++ Questions on Bytes Question stats viewed: 6383 replies: 1 date asked: Jun 28 '13 Follow this discussion BYTES.COM © 2016 Formerly "TheScripts.com" from 2005-2008 About Bytes | Advertise on Bytes | Contact Us Sitemap | C / C++ Answers Sitemap | C / C++ Insights Sitemap Follow us to get the Latest Bytes Updates