Constructor Undefined Error Java
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Java Enum Constructor Undefined
Code: public class WeightIn{ private double weight; private double height; public WeightIn (double weightIn, double heightIn){ weight = weightIn; height = heightIn; } public void setWeight(double weightIn){ weight = weightIn; } public void setHeight(double heightIn){ height = heightIn; } } public class WeightInApp{ public static void main (String [] args){ WeightIn weight1 = new WeightIn(); //Error happens here. weight1.setWeight(3.65); weight2.setHeight(1.7); } } I have a constructor defined. java constructor share|improve this question edited Aug 17 '13 at implicit super constructor object is undefined 1:24 Eric Leschinski 46k23219189 asked Aug 10 '13 at 5:56 user2669883 26112 6 The compiler is right. The constructor WeightIn() is not defined. –A--C Aug 10 '13 at 5:58 can you correct the code and then past a copy so i can understand it please –user2669883 Aug 10 '13 at 6:24 Scrit still doesnt work –user2669883 Aug 10 '13 at 6:34 add a comment| 6 Answers 6 active oldest votes up vote 10 down vote add this to your class. public WeightIn(){ } Please understand that default no-argument constructor is provided only if no other constructor is written If you write any constructor, then compiler does not provided default no-arg constructor. You have to specify one. share|improve this answer edited Aug 24 '13 at 3:40 answered Aug 10 '13 at 5:59 Prasad Kharkar 9,84811846 1 what do you mean –user2669883 Aug 10 '13 at 6:14 add a comment| up vote 4 down vote In this you can't do WeightIn weight1 = new WeightIn(); since default constructor is not defined. So you can add public WeightIn(){ } Or you can do this WeightIn weight1 = new WeightIn(3.65,1.7) // constructor accept two double values share|improve this answer edited Aug 17 '13 at 1:25 Eric Leschinski 46k23219189 answered Aug 10 '13 at 6:03 Ruchira Gayan Ranaweera 20.6k114278 add a comment| up vote 1 down vot
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The Constructor Is Undefined Processing
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The Constructor String Is Undefined
Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Java constructor undefined up vote 2 down vote favorite Basically, http://stackoverflow.com/questions/18159104/java-error-the-constructor-is-undefined I was doing a Java exercise in a book and this source code is its answer to the exercise. However, eclipse says there is an error at the third line up from the bottom, saying "- The constructor PhoneNumber() is undefined". But as I understand, that specific constructor is defined correctly so what is the problem? public class PhoneNumber { // Only the relevant source codes are posted http://stackoverflow.com/questions/16071149/java-constructor-undefined here. // I removed other bits cause I'm sure they are not responsible for the // error private char[] country; private char[] area; private char[] subscriber; public PhoneNumber(final String country, final String area, final String subscriber) { this.country = new char[country.length()]; country.getChars(0, country.length(), this.country, 0); this.area = new char[area.length()]; area.getChars(0, area.length(), this.area, 0); this.subscriber = new char[subscriber.length()]; subscriber.getChars(0, subscriber.length(), this.subscriber, 0); checkCorrectness(); } private void runTest() { // method body } public static void main(final String[] args) { (new PhoneNumber()).runTest(); // error here saying : // "The constructor PhoneNumber() is undefined" } } java share|improve this question edited Apr 18 '13 at 12:12 asked Apr 17 '13 at 22:12 Kyle 1315 add a comment| 3 Answers 3 active oldest votes up vote 6 down vote accepted Eclipse is correct. Your code does not define a constructor with no arguments, which is what you are calling with new PhoneNumber() inside the main method. You have only one constructor, which is: public PhoneNumber (final String country, final String area, final String subscriber) The so called default constructor, the one with no arguments, is automatically created for you if you don't specify any other constructor. Since you specify one with 3 parameters, you have no d
here for a quick overview of the site Help Center Detailed http://stackoverflow.com/questions/6262116/the-constructor-is-undefined-error answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join is undefined the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up “ The constructor is undefined ” error up vote 2 down vote favorite My Code: public class ViewsActivity extends Activity implements OnClickListener the constructor is { // private Integer[] ImgIds = { R.drawable.pic1, R.drawable.pic2, R.drawable.pic3, R.drawable.pic4 }; private LinearLayout mLinearLayout; private Gallery g; private MediaPlayer mp; private ImageView i; private Thread th; private Runnable viewUpdate; private int m_index = 0; private OnClickListener mImageListener = new OnClickListener() { @Override public void onClick(View v) { setContentView(R.layout.main); g = (Gallery) findViewById(R.id.gallery1); g.setAdapter(new ImageAdapter(v.getContext())); g.setOnItemClickListener(mGalleryClickListener); g.setOnItemSelectedListener(mGallerySelectedListener); } }; private OnItemSelectedListener mGallerySelectedListener = new OnItemSelectedListener() { @Override public void onItemSelected(AdapterView adapter, View v, int i, long lng) { String descr = ""; switch(i) { case 0: descr = "scena1"; break; case 1: descr = "scena2"; break; case 2: descr = "scena3"; break; case 3: descr = "scena4"; break; case 4: descr = "scena5"; break; case 5: descr = "scena6"; break; case 6: descr = "scena7"; break; case 7: descr = "scena8"; break; case 8: descr = "scena9"; break; case 9: descr = "scena10"; break; } To