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Parse Error In Template Argument List

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Template Class Member Function Definition

to spam. Bug44906 - g++ is giving error: parse error c++ template member function of non-template class in template argument list Summary: g++ is giving error: parse error in template argument c++ member template list Status: REOPENED Alias: None Product: gcc Classification: Unclassified Component: c++ (show other bugs) Version: 4.4.3 Importance: P3 enhancement Target Milestone: --- Assignee: Not

C++ Template Member Function Specialization

yet assigned to anyone URL: Keywords: diagnostic Depends on: Blocks: Reported: 2010-07-10 15:43 UTC by Amitava Ray Chaudhuri Modified: 2011-10-19 22:24 UTC (History) CC List: 1 user (show) manu See Also: Host: Target: Build: Known to work: Known to fail: Last reconfirmed: 2011-09-23 00:00:00 Attachments Code which is

Define Template Function In Cpp

failing. (515 bytes, text/plain) 2010-07-10 15:44 UTC, Amitava Ray Chaudhuri Details .s file generated by -save-temps (30 bytes, text/plain) 2010-07-10 15:44 UTC, Amitava Ray Chaudhuri Details .ii file generated by -save-temps (73.98 KB, text/plain) 2010-07-10 15:45 UTC, Amitava Ray Chaudhuri Details View All Add an attachment (proposed patch, testcase, etc.) Note You need to log in before you can comment on or make changes to this bug. Description Amitava Ray Chaudhuri 2010-07-10 15:43:04 UTC amitavac@whileliesent-lm:~/data/prog/c++/template_ptr$g++ -v -o template template.cpp Using built-in specs. Target: i486-linux-gnu Configured with: ../src/configure -v --with-pkgversion='Ubuntu 4.4.3-4ubuntu5' --with-bugurl=file:///usr/share/doc/gcc-4.4/README.Bugs --enable-languages=c,c++,fortran,objc,obj-c++ --prefix=/usr --enable-shared --enable-multiarch --enable-linker-build-id --with-system-zlib --libexecdir=/usr/lib --without-included-gettext --enable-threads=posix --with-gxx-include-dir=/usr/include/c++/4.4 --program-suffix=-4.4 --enable-nls --enable-clocale=gnu --enable-libstdcxx-debug --enable-plugin --enable-objc-gc --enable-targets=all --disable-werror --with-arch-32=i486 --with-tune=generic --enable-checking=release --build=i486-linux-gnu --host=i486-linux-gnu --target=i486-linux-gnu Thread model: posix gcc version 4.4.3 (Ubuntu 4.4.3-4ubuntu5) COLLECT_GCC_OPTIONS='-v' '-o' 'template' '-shared-libgcc' '-mtune=generic' '-march=i486' /usr/lib/gcc/i486-linux-gnu/4.4.3/cc1plus -quiet -v -D_GNU_SOURCE template.cpp -D_FORTIFY_SOURCE=2 -quiet -dumpbase template.cpp -mtune=generic -march=i486 -auxbase template -v

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C++ Template Function

Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up https://gcc.gnu.org/bugzilla/show_bug.cgi?id=44906 C++ confusing attribute name for member template up vote 18 down vote favorite 1 I've found that when accessing a non-template attribute (v.foo) from a variable of a template type (T& v), C++ can be tricked into thinking that it is a member template if there is a template function of the same name (template class void foo()). How can this be http://stackoverflow.com/questions/10671406/c-confusing-attribute-name-for-member-template explained from the C++ spec? Consider this simple program: #include /** Determine whether the 'foo' attribute of an object is negative. */ template bool foo_negative(T& v) { return v.foo < 0; } struct X { int foo; }; int main() { X x; x.foo = 5; assert(!foo_negative(x)); return 0; } We have a template function foo_negative that takes an object of any type and determines whether its foo attribute is negative. The main function instantiates foo_negative with [T = X]. This program compiles and runs without any output. Now, add this function to the top of the program: template void foo() { } Compiling it with G++ 4.6.3 results in this compiler error: funcs.cpp: In function ‘bool foo_negative(T&)’: funcs.cpp:13:14: error: parse error in template argument list funcs.cpp: In function ‘bool foo_negative(T&) [with T = X]’: funcs.cpp:25:5: instantiated from here funcs.cpp:13:14: error: ‘foo’ is not a member template function (Where Line 13 is return v.foo < 0 and Line 25 is assert(!foo_negative(x)).) Clang produces similar errors. Wat? How did adding an unrelated function that is never called manage to introduce a syntax err

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more http://stackoverflow.com/questions/33423702/how-to-use-greater-than-inside-a-template-parameter-and-not-get-a-parsing-er about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping https://bytes.com/topic/c/answers/520238-template-trouble each other. Join them; it only takes a minute: Sign up How to use > (greater-than) inside a template parameter and not get a parsing error? up vote 11 down vote favorite I want to only define a function member function based on the size of the template parameter: template typename std::enable_if 1, void>::type foobify(T v) { // ... } int main() { //foobify((unsigned char)30); // should not compile foobify((long)30); } However, I get: main.cpp:8:41: error: expected unqualified-id before numeric constant typename std::enable_if 1, void>::type It works if I instead do 1 < sizeof(T). Thus I believe GCC is thinking I am ending the template parameter, instead of continuing the boolean expression. Is there c++ template member any way to use > itself without having to work around it? c++ parsing templates share|improve this question asked Oct 29 '15 at 20:11 Claudiu 94.7k92307493 2 Also see Operators and template-ids –Shafik Yaghmour Oct 29 '15 at 20:17 2 You could also use is_greater typename std::enable_if::type :PPPPP –101010 Oct 29 '15 at 20:20 add a comment| 2 Answers 2 active oldest votes up vote 17 down vote accepted Yes, expressions using that operator must be parenthesized. See [temp.names]/3: When parsing a template-argument-list, the first non-nested >138 is taken as the ending delimiter rather than a greater-than operator. [..] [ Example: template class X { /* ...*/ }; X< 1>2 > x1; // syntax error X<(1>2)> x2; // OK — end example ] 138) A > that encloses the type-id of a dynamic_cast, static_cast, reinterpret_cast or const_cast, or which encloses the template-arguments of a subsequent template-id, is considered nested for the purpose of this description. Clearly that doesn't apply if you use the symmetric counterpart of that comparison, i.e. employing <, instead - parsing is unambiguous in that case. share|improve this answer edited Oct 29 '15 at 20:17 answered Oct 29 '15 at 20:13 Columbo 42.1k576126 add a comment| up vote 12 down vote Yes, you should use parentheses: template typename std::enable_if<(sizeof(T) > 1), void>::type foobify(T v) { // ... } share|impro

tips & solutions from a community of 418,616 IT Pros & Developers. It's quick & easy. Template trouble P: n/a idar.douglas.hillgaar Hi - the following code compiled easily in VS.Net however using g++'s there are several errors relating to template (I'm using a list()) - using the latest ver. of g++ Code: list ::iterator i; if (my_list2.empty()) cout << "List is empty " << endl; else { /* Adds integers to an array I need for 3rd lib. */ for( i = my_list2.begin(), count = 0; i != my_list2.end() && count < size; i++, count ++) { seq[count] = *i; } } /* printing out the values */ for (int i = 0; i < size; i++) { cout << " test: " << seq[i] << endl; } Errors in g++: readSequence.c: In function 'int main()': readSequence.c:561: error: expected primary-expression before 'template' readSequence.c:561: error: expected `;' before 'template' readSequence.c:567: error: expected initializer before '*' token readSequence.c:570: error: 'my_list2' was not declared in this scope readSequence.c:584: error: overloaded function with no contextual type information readSequence.c:584: error: parse error in template argument list readSequence.c:584: error: expected `;' before ')' token readSequence.c:586: error: 'seq' was not declared in this scope readSequence.c:592: error: 'seq' was not declared in this scope make: *** [readSequence.o] Error 1 Aug 5 '06 #1 Post Reply Share this Question 6 Replies P: n/a Alf P. Steinbach * id*******************@gmail.com: Hi - the following code Is not your actual code. Post a complete, minimal, actual example, and indicate where in that code the compiler reports an error. -- A: Because it messes up the order in which people normally read text. Q: Why is it such a bad thing? A: Top-posting. Q: What is the most annoying thing on usenet and i

 

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