Access 2007 Datediff Error
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Datediff In Access 2007 Queries
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Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up DateDiff Access Query returning #Error ms access datediff up vote 2 down vote favorite I am trying to get the number of days between two dates. Here is the Expression I am using in Access Query Designer. (Access 2007) Expr1: DateDiff('d',[Accept Date],[Sent Date]) The query is returning #Error. The [Accept Date] and [Sent Date] format is yyyymmdd and the Data Type is TEXT. I changed it to Date/Time but Access purged the data. Here ms access datediff hours and minutes is the SQL behind the Query if that helps: SELECT RTG.[PRO NO], RTG.[Service], RTG.[Sent Date], RTG.[Accept Date], DateDiff('d',[Accept Date],[Sent Date]) AS Expr1 FROM RTG WHERE (((RTG.[PRO NO Prefix])<>"215") AND ((RTG.[Invoice Number])="8548")); This has got to be something simple, right? sql ms-access ms-access-2007 share|improve this question edited Oct 9 '14 at 14:41 HansUp 79.1k114371 asked Oct 9 '14 at 14:14 Derek 1361615 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted DatePart can accept dates which are actually text instead of Date/Time datatype. However, the text must be something which Access recognizes as a valid date representation. A text date in "yyyymmdd" format doesn't satisfy that requirement. For example, in the Immediate window ... ? IsDate("20141009") False However, if you insert dashes between the year, month, and day segments, Access can recognize the text string as a date. ? Format("20141009", "0000-00-00") 2014-10-09 ? IsDate(Format("20141009", "0000-00-00")) True Test that technique in a simple query to make sure it avoids the error. SELECT RTG.[Sent Date], RTG.[Accept Date], DateDiff( 'd', Format([Accept Date],'0000-00-00'), Format([Sent Date],'0000-00-00') ) AS Expr1 FROM RTG If Access still throws an error, use CDate to cast the text date to Date/Time
Applies To: Access 2016, Access 2013, Access 2010, Access 2007, Access 2010 Developer, Access 2007 Developer, Access 2013 Developer, Less Applies To: Access 2016
Ms Access Datediff Working Days
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Ms Access Datediff Weekdays Only
have? More... Returns a Variant (Long) specifying the number of time intervals between two specified dates. See some examples Syntax DateDiff ( interval, date1, date2 [, firstdayofweek] http://stackoverflow.com/questions/26280722/datediff-access-query-returning-error [, firstweekofyear] ) The DateDiff function syntax has these arguments: Tip: In Access 2010, the Expression Builder has IntelliSense, so you can see what arguments your expression requires. Argument Description interval Required. String expression that is the interval of time you use to calculate the difference between date1 and date2. date1, date2 Required. Variant (Date). Two https://support.office.com/en-us/article/DateDiff-Function-e6dd7ee6-3d01-4531-905c-e24fc238f85f dates you want to use in the calculation. firstdayofweek Optional. A constant that specifies the first day of the week. If not specified, Sunday is assumed. firstweekofyear Optional. A constant that specifies the first week of the year. If not specified, the first week is assumed to be the week in which January 1 occurs. Settings The intervalargument has these settings: Setting Description yyyy Year q Quarter m Month y Day of year d Day w Weekday ww Week h Hour n Minute s Second Top of Page The firstdayofweek argument has these settings: Constant Value Description vbUseSystem 0 Use the NLS API setting. vbSunday 1 Sunday (default) vbMonday 2 Monday vbTuesday 3 Tuesday vbWednesday 4 Wednesday vbThursday 5 Thursday vbFriday 6 Friday vbSaturday 7 Saturday Constant Value Description vbUseSystem 0 Use the NLS API setting. vbFirstJan1 1 Start with week in which January 1 occurs (default). vbFirstFourDays 2 Start with the first week that has at least four days
Groups Pictures & Albums Members List Calendar Search Forums Show Threads Show Posts Tag Search Advanced Search Find All Thanked Posts Go to Page... Thread Tools Rate http://www.access-programmers.co.uk/forums/showthread.php?t=203129 Thread Display Modes 12-27-2010, 03:28 AM #1 Fede Newly Registered User Join Date: Dec 2010 Posts: 16 Thanks: 0 Thanked 0 Times in 0 Posts DateDiff Error Why? Hi, I http://webcheatsheet.com/sql/access_functions/datediff.php have two dates, Shipping Date and Delivery date... I wrote this on a query Select ID CoDe --> from Table1 --> where (DateDiff("d",[table1].[shipping Date],[table1].[Delivery date],2)>2) What's Wrong ? The Query doesn't work... ms access Thank You Fede View Public Profile Find More Posts by Fede 12-27-2010, 05:58 AM #2 Rabbie Super Moderator Join Date: Jul 2007 Location: In Exile in Wiltshire Posts: 5,891 Thanks: 106 Thanked 72 Times in 64 Posts Re: DateDiff Error Why? Just try Select ID CoDe --> from Table1 --> where (DateDiff("d",[table1].[shipping Date],[table1].[Delivery date])>2) You don't need the ms access datediff the firstdayofweek parameter when you are working in days. __________________ The best solution is the simplest one that meets all requirements. To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts. Rabbie View Public Profile Visit Rabbie's homepage! Find More Posts by Rabbie 12-27-2010, 05:59 AM #3 Fede Newly Registered User Join Date: Dec 2010 Posts: 16 Thanks: 0 Thanked 0 Times in 0 Posts Re: DateDiff Error Why? Ok Thank You very much now is all right!!!! Fede View Public Profile Find More Posts by Fede 12-27-2010, 06:04 AM #4 Rabbie Super Moderator Join Date: Jul 2007 Location: In Exile in Wiltshire Posts: 5,891 Thanks: 106 Thanked 72 Times in 64 Posts Re: DateDiff Error Why? Glad to be of help __________________ The best solution is the simplest one that meets all requirements. To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts. Rabbie View Public Profile Visit Rabbie's homepage! Find More Posts by Rabbie
Date function DateAdd function DateDiff function DatePart function DateSerial function DateValue function Day function Exp function FileDateTime function First function Fix function Format function Hour function IIf function IsDate function IsNull function IsNumeric function Int function Last function LCase function Left function Len function Log function LTrim function Max function Mid function Min function Minute function Month function MonthName function Now function Replace function Right function Rnd function Round function RTrim function Second function Sgn function Sin function Space function Sqr function Str function StrConv function Sum function Switch function Tan function Time function TimeSerial function TimeValue function Trim function Ucase function Val function Weekday function WeekdayName function Year function Subscription Sign up for the free email newsletter for new tips, tutorials and more. Enter your email address below, and then click the button. Privacy Policy Access: DateDiff Function In Access, the DateDiff function returns the number of time intervals between two dates. The syntax for theDateDiff function is: DateDiff( interval, date1, date2[, firstdayofweek[, firstweekofyear]] ) You can use the DateDiff function to determine how many time intervals exist between two dates. For example, you can use DateDiff to calculate the number of days between an order date and its shipdate or the number of weeks between today and the end of the year. interval is the interval of time to use to calculate the difference between date1 and date2. The following is a list of valid interval values. Interval Description yyyy Year q Quarter m Month y Day of year w Weekday ww Week h Hour n Minute s Second date1, date 2 are the two dates to calculate you want to use in the calculation. firstdayofweekis optional argument that specifies the first day of the week. If not specified, Sunday is assumed. If not specified, the first week is assumed to be the week in which Jan 1 occurs. The following is a list of valid parameters for firstweekofyear. Constant Value Description vbUseSystem 0 Use the NLS API settings vbSunday 1 Sunday (default used) vbMonday 2 Monday vbTuesday 3 Tuesday vbWednesday 4 Wednesday vbThursday 5 Thursday vbFriday 6 Friday vbSaturday 7 Saturday firstweekofyearis optional argument that specifies the first week of th