Error Msg 8152 In Sql Server

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Sql Server Msg 8152 String Or Binary Data Would Be Truncated

Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users sql server msg 8152 level 16 state 14 Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a error code 8152 sql server minute: Sign up Msg 8152, String or binary data would be truncated up vote 7 down vote favorite 2 I have this table: CREATE TABLE Vendors ( VendorID NUMERIC(10) NOT NULL, VendorName CHAR(50) NOT NULL, VendorAddress VARCHAR(30) NULL, VendorCityName VARCHAR(20) NOT NULL, VendorStateName CHAR(2) NOT NULL, VendorZip VARCHAR(10) NULL, VendorContactName CHAR(50) NOT NULL, VendorContactPhone VARCHAR(12) NOT NULL, VendorContactEmail VARCHAR(20) NOT NULL, VendorSpecialty

Sql Error 8152 Sqlstate 22001

CHAR(20) NOT NULL CONSTRAINT VendorsPK PRIMARY KEY (VendorID) ); And this insert: INSERT INTO Vendors(VendorID, VendorName, VendorAddress, VendorCityName, VendorStateName, VendorZip, VendorContactName, VendorContactPhone, VendorContactEmail, VendorSpecialty) VALUES(151330, 'Hyperion', '77 West 66th Street', 'New York', 'NY', 10023, 'John Hinks', '212-337-6564', 'jhinks@hyperionbooks.com', 'Popular fiction') Why does this statement yield the 8152 error? sql-server error-handling share|improve this question edited Apr 23 '13 at 14:55 Aaron Bertrand 165k18265320 asked Apr 23 '13 at 14:40 Stephen Fians 46114 @zhrist I see what you did there... did there... did there... –Tjorriemorrie Sep 26 at 0:00 add a comment| 1 Answer 1 active oldest votes up vote 15 down vote VendorContactEmail is only 20 bytes. Your e-mail address on the first line (jhinks@hyperionbooks.com) is longer than that - 24 bytes. And many e-mail addresses will be longer. Who decided to only allow 20 characters in the e-mail address column? According to the standard, this should be VARCHAR(320) - 64 characters for localpart + 1 for @ + 255 for domain. share|improve this answer answered Apr 23 '13 at 14:45 Aaron Bertrand 165k18265320 add a comment| Your Answer draft save

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String Or Binary Data Would Be Truncated. The Statement Has Been Terminated In Sql Server

terminated. SQL Server Error Messages - Msg 8152 - String or binary data would be truncated. The statement has been terminated. SQL Server Error Messages - Msg 8152 Error Message http://stackoverflow.com/questions/16172259/msg-8152-string-or-binary-data-would-be-truncated Server: Msg 8152, Level 16, State 9, Line 1 String or binary data would be truncated. The statement has been terminated. Causes: This error is usually encountered when inserting a record in a table where one of the columns is a VARCHAR or CHAR data type and the length of the value being inserted is longer than the length of the http://www.sql-server-helper.com/error-messages/msg-8152.aspx column. To illustrate, let’s say you have the following table: CREATE TABLE [dbo].[Students] ( [StudentID] INT, [FirstName] VARCHAR(10), [LastName] VARCHAR(10) ) Issuing the following INSERT statement will generate this error message: INSERT INTO [dbo].[Students] ( [StudentID], [FirstName], [LastName] ) VALUES ( 12345, 'Rumpelstiltskin', '' ) Msg 8152, Level 16, State 9, Line 1 String or binary data would be truncated. The statement has been terminated. Since the [FirstName] column will only accept 10 characters, the INSERT statement will fail because the length of the value being inserted is more than 10 characters. The error can also be encountered when decreasing the length of a VARCHAR or CHAR column in a table that already contains data and the new length of the column is not long enough to accommodate the longest value in the column. CREATE TABLE [dbo].[Students] ( [StudentID] INT, [FirstName] VARCHAR(20), [LastName] VARCHAR(20) ) INSERT INTO [dbo].[Students] ( [StudentID], [FirstName], [LastName] ) VALUES ( 12345, 'Rumpelstiltskin', '' ) ALTER TABLE [dbo].[Students] ALTER COLUMN [FirstName] VARCHAR(10) Msg 8152, Level 16, State 9, Line 1 String or binary data would be trunca

(Русский)ישראל (עברית)المملكة العربية السعودية (العربية)ไทย (ไทย)대한민국 (한국어)中华人民共和国 (中文)台灣 (中文)日本 (日本語)  HomeLibraryLearnDownloadsTroubleshootingCommunityForums Ask a question Quick access Forums home Browse forums users FAQ Search related threads Remove From My Forums Answered by: Error https://social.msdn.microsoft.com/Forums/sqlserver/en-US/8b7326bd-5ada-4815-88b6-577d7bbd8476/error-8152-string-or-binary-data-would-be-truncated?forum=sqldataaccess 8152: "String or binary data would be truncated" SQL Server > https://raresql.com/2014/01/03/sql-server-a-quick-solution-to-string-or-binary-data-would-be-truncated-using-stored-procedure/ SQL Server Data Access Question 0 Sign in to vote I've been working with a sample database that the company is using for testing purposes. I (we) did not create the database - it was sent over to us by another company. msg 8152 I'm still a rank newbie at working with MS SQL Server, though I've worked with Access and MySQL in the past. There is one table that contains bank information. At the moment, it is filled with information on imaginary (fake) banks. I need to change one record so that it contains the in sql server information of a real bank the company is using. The problem is, I am unable to touch anything within this table. Any attempt to make changes gives me an error prompt that reads "String or binary data would be truncated". I ran the profiler, and it shows an Exception - Error: 8152 Severity 16 State 2. Furthermore, I also get an error prompt stating: "The value you entered is not consistent with the data type or length of this column". I've checked and checked again, and as far as I can tell, the value I entered _is_ consistent with the data type/length of the column. I can make changes perfectly fine on the other tables in the database. Only this one table gives me trouble. Could anyone shed some light on why exactly this is occurring, and why only on this one table? Thank you :) Monday, October 17, 2005 9:22 PM Reply | Quote

triggers using sp_MSforeachtable » SQL SERVER - A quick solution to ‘String or binary data would be truncated' using Storedprocedure January 3, 2014 by Muhammad Imran String or binary data would be truncated (Error number 8152) is a very common error. It usually happens when we try to insert any data in string (varchar,nvarchar,char,nchar) data type column which is more than size of the column. So you need to check the data size with respect to the column width and identify which column is creating problem and fix it. It is very simple if you are dealing with less columns in a table. But it becomes nightmare if you are dealing with inert into query with huge number of columns and you need to check one by one column. I received this query from one of my Blog readers Mr Ram Kumar asking if there is a shortcut to resolve this issue and give the column name along with the data creating problems. I started searching for the solution but could not get proper one. So I started developing this solution. Before proceeding with the solution, I would like to create a sample to demonstrate the problem. SAMPLE : --This script is compatible with SQL Server 2005 and above. --DROP TABLE tbl_sample --GO CREATE TABLE tbl_sample ( [ID] INT, [NAME] VARCHAR(10), ) GO INSERT INTO tbl_sample VALUES (1,'Bob Jack Creasey') GO INSERT INTO tbl_sample ([ID],[NAME]) VALUES (2,'Frank Richard Wedge') GO --OUTPUT Msg 8152, Level 16, State 14, Line 1 String or binary data would be truncated. The statement has been terminated. Msg 8152, Level 16, State 14, Line 2 String or binary data would be truncated. The statement has been terminated. SOLTUION : Given below is the stored procedure that can find the exact column name and its data which is exceeding the limit of column width. --DROP PROCEDURE usp_String_or_binary_data_truncated --GO CREATE PROCEDURE usp_String_or_binary_data_truncated @String VARCHAR(MAX) AS DECLARE @VARCHAR AS VARCHAR(MAX) DECLARE @Xml AS XML DECLARE @TCount AS INT SET @String= REPLACE(REPLACE(REPLACE(REPLACE(@String,'''','') ,'[',''),']',''),CHAR(13) + CHAR(10),'') SET @Xml = CAST((''+REPLACE(@String,'(','') +'') AS XML) SELECT @TCount=COUNT(*) FROM @Xml.nodes('A') AS FN(A)