C Error C2106
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Error C2106 '=' Left Operand Must Be L-value C++
ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the error c2106 visual c++ Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: left operand must be l-value in c Sign up error C2106: '=' : left operand must be l-value up vote 2 down vote favorite Looking at the other questions regarding error C2106, I am still lost as to what the issue is with my code. While compiling I
Left Operand Must Be L Value Struct
get the following errors: c:\driver.cpp(99): error C2106: '=' : left operand must be l-value c:\driver.cpp(169): error C2106: '=' : left operand must be l-value The line of code is as follows: payroll.at(i) = NULL; //Line 99 payroll.at(count++) = ePtr; //Line 169 I am failing to understand why this error is being thrown. In this project I have changed my driver.cpp from an array of employee object pointers to a custom Vector template that I made. I declare the Vector as follows... //Declare
C++ Must Be A Modifiable Lvalue
an Vector to hold employee object pointers MyVector here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack must be lvalue javascript Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a expression must be a modifiable lvalue community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up C - Can't figure out this error : “C2106: '=' : left operand must be l-value” http://stackoverflow.com/questions/17930948/error-c2106-left-operand-must-be-l-value up vote -2 down vote favorite I am using Visual Studio 2013 to try and learn C language. I'm using the famous K&R book and after literally copying and pasting the following piece of code from the book to Visual Studio 2013 i got the error : 1 error C2106: '=' : left operand must be l-value 2 IntelliSense: expression must be a modifiable lvalue #include here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more http://stackoverflow.com/questions/15282003/left-operand-must-be-l-value-c-programing about Stack Overflow the company Business Learn more about hiring developers or posting ads http://stackoverflow.com/questions/28642982/error-c2106-left-operand-must-be-l-value-with-c with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up left operand must be l-value , C programing up vote 1 down must be vote favorite am trying to understand how link lists work ; and on changing example code from tutor I get the 'left operand must be l-value' error ...here is my code. Any help appreciated :) struct node { char name[20]; struct node *next; }; /*Function to allocate memory and initialize node - returns pointer to node*/ struct node*mknode(char *str) { struct node *np; np = (struct node*)malloc(sizeof(struct node)); if(np) { must be l np->name = *str; np->next = NULL; /*sets the 'next' pointer to last list item to NULL*/ } return np; } int main(void) { int i,menu,k=1,number; char name[20]; char *str = name; struct node* n; struct node *head=NULL; printf("Link Lists\n 1-Enter Data into lists\n 2-Display All List Items\n 3-Quit Program :(\n"); do { printf("\nPlease choose an option: "); scanf("%d",&menu); switch (menu) { case 1: printf("\nPlease Enter A Number:"); scanf("%d",&name); n=mknode(str); /*create new node with i as data*/ append_node(&head,n); /*add new node to end of list*/ break; this is where i get the error np->name = *str; after changing the structures data type from integer to char thanks c share|improve this question asked Mar 7 '13 at 21:22 Dex Dave 651211 You're treating np->name as a pointer, when it's an array. You can't assign something to an array. –teppic Mar 7 '13 at 21:25 You can't assign directly to a character array, you need to use strcpy or strncpy –Hunter McMillen Mar 7 '13 at 21:25 possible duplicate of error C2106: '=' : left operand must be l-value in C –Bo Persson Mar 7 '13 at 21:29 thanks for the quick reply - strcpy worked just fine :) –Dex D here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error C2106: '=' : left operand must be l-value with `!=` C++ up vote -2 down vote favorite I have absolutely no idea why my compiler is throwing this error: "Error 1 error C2106: '=' : left operand must be l-value" with this line of code: while ((input != 1 && input != 2 && input != 3 && choice = 1) || (input != 1 && input != 2 && input != 3 && input != 4 && input != 5 && input != 6 && choice = 1) || std::cin.fail()){} The error appears to want input, which is a short, to be modifiable, but != is not a modifier, it's a checker. What is going on? c++ share|improve this question edited Feb 21 '15 at 6:52 asked Feb 21 '15 at 6:41 LarryK 165110 5 Change your choice = 1 to choice == 1 statements. –volerag Feb 21 '15 at 6:44 4 "There's no reason for my compiler to be throwing this error" Throw those assumptions out of the window if you want to learn how to solve these problems yourself. –Lightness Races in Orbit Feb 21 '15 at 6:48 @LightnessRacesinOrbit I thought it was a typo. –volerag Feb 21 '15 at 6:49 2 that's why in some coding standards it's recommended to write the constant first: 1 == choice –Lưu Vĩnh Phúc Feb 21 '15 at 6:51 1 What's with all the downvotes?! –LarryK Feb 21 '15 at 6:58 | show 6 more comments 1 Answer 1 active oldest votes up vote 7 down vote accepted Operator precedence dictates that your first sub-condition input != 1 && input != 2 && input != 3 && choice = 1 is parsed as (input != 1 && input != 2 && input != 3 && choice) = 1 The left-hand side of = is not an lvalue, just like your compiler told you. What were you trying to say by that strange combination of operators? share|improve this answer answered Feb 21 '15 at 6:50 AnT 201k25289522 That was a stupid mistake. Thanks! I'm not sure if I ever would have found that. –LarryK Feb 21 '15 at 6:51 1 It's a pity that there's no "language lawyer" badge...it takes a certain mentality to look past the obvious "=" versus "==" issue and explain the resulting error message. –Jim Lewis Feb 21 '15 at 7:00 add a comment| Your Answer draft savedMust Be Lvalue Jquery