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Error C2106 '=' Left Operand Must Be L-value C++

ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the left operand must be l-value in c Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: error c2106: '=' : left operand must be l-value in c Sign up error C2106: '=' : left operand must be l-value up vote 2 down vote favorite Looking at the other questions regarding error C2106, I am still lost as to what the issue is with my code. While compiling I

C++ Must Be A Modifiable Lvalue

get the following errors: c:\driver.cpp(99): error C2106: '=' : left operand must be l-value c:\driver.cpp(169): error C2106: '=' : left operand must be l-value The line of code is as follows: payroll.at(i) = NULL; //Line 99 payroll.at(count++) = ePtr; //Line 169 I am failing to understand why this error is being thrown. In this project I have changed my driver.cpp from an array of employee object pointers to a custom Vector template that I made. I declare the Vector as follows... //Declare

Must Be Lvalue Javascript

an Vector to hold employee object pointers MyVector payroll; Any help is appreciated... c++ templates vector share|improve this question edited Jul 29 '13 at 18:00 Ehsan 19k32646 asked Jul 29 '13 at 17:58 KQball 27115 4 What does MyVector::at return? –tohava Jul 29 '13 at 18:00 5 MyGuess : YourVector::at() must be returning by value which is the problem. –Nawaz Jul 29 '13 at 18:03 @tohava this is what it returns... 'return myArray[n];' unless the reference is greater than the vector size then it returns the value that was passed into the function. –KQball Jul 29 '13 at 18:13 1 @KQball: What is the return type (that determines how you return what you return)? –Nawaz Jul 29 '13 at 18:24 add a comment| 4 Answers 4 active oldest votes up vote 10 down vote This error is being thrown for the same reason you can't do something like this: 36 = 3; Your version of Vector::at should be returning a reference rather than a value. Lvalues are called Lvalues because they can appear on the left of an assignment. Rvalues cannot appear on the left side, which is why we call them rvalues. You can't assign 3 to 36 because 36 is not an lvalue, it is an rvalue, a temporary. It doesn't have a memory address. For the same reason, you cannot assign NULL to payroll.at(i). Your definition: template V MyVector::at(int n) What it should be: template

Search Username Password Remember Me? Register Lost Password? facebook google twitter rss Free Web Developer Tools Advanced Search  Forum Programming Languages C Programming Trouble initializing array must be lvalue jquery of structs, error C2106: '=' : left operand must be l-valu Thread:

Expression Must Be A Modifiable Lvalue

Trouble initializing array of structs, error C2106: '=' : left operand must be l-valu Share This Thread  visual studio 2016 Tweet This + 1 this Post To Linkedin Subscribe to this Thread  Subscribe to This Thread November 19th, 2003,07:43 PM #1 No Profile Picture Scoobiez View Profile View http://stackoverflow.com/questions/17930948/error-c2106-left-operand-must-be-l-value Forum Posts  Junior Member Devshed Newbie (0 - 499 posts)  Join Date Nov 2003 Location FL Posts 6 Rep Power 0 Trouble initializing array of structs, error C2106: '=' : left operand must be l-valu [FONT=courier new] I am trying to initialize and array of structs....struct is called pb_entry and the array is phone_book. When I follow "correct"syntax http://forums.devshed.com/programming-42/trouble-initializing-array-structs-error-c2106-left-operand-valu-99683.html I get the following error: error C2106: '=' : left operand must be l-value Here is the segment of my code that applys(I assure that the rest of the code is correct since it is quite simple): typedef struct { char last_name[15]; char first_name[15]; char mid_init[3]; char address[50]; char phone_num[15]; }pb_entry; int j = 0; pb_entry phone_book[SIZE]; for(j=0; j<=SIZE; j++) { phone_book[j].last_name = " "; phone_book[j].first_name = " "; phone_book[j].mid_init = " "; phone_book[j].address = " "; phone_book[j].phone_num = " "; } Basic jist of the code it to construct a phone book. This segment(and again, I've only posted relevant code) initializes the array of structs to be "blank". However when I compile I get the error noted above. SIZE is declared to be 100 Any insight on what it means? What is l-value? Sorry newbie here. Thanks for any input! Regards Faq Reply With Quote November 19th, 2003,08:56 PM #2 dwise1_aol View Profile View Forum Posts  Contributing User Devshed Supreme Being (6500+ posts)              

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