Mysql Error Code 1248
Contents |
here for a quick overview of the site Help Center Detailed answers to any mysql error code 1248. every derived table must have its own alias questions you might have Meta Discuss the workings and policies
Duplicate Column Name
of this site About Us Learn more about Stack Overflow the company Business Learn more about mysql derived table hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow
Mysql Union
is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MYSQL ERROR 1248 (42000): Every derived table must have its own alias up vote 4 down vote favorite 1 I cant for the life of me figure out why this mysql join is erroring SELECT * FROM SELECT c.city_id, p.prop_ynow_id, p.propertyid, p.prop_add_value, p.name, picture, ifnull(p.address,'') as`location`, ifnull(city,'')as`city`, ifnull(ShortCut,'') as `state`, ifnull(p.zip,'') as `zip`, min(if(pr.minrent = 0,99999999,pr.minrent)) as minrent, max(pr.maxrent) as maxrent, '' as service, hood_id, ifnull(p.phone,'') as `phone`, latitude, longitude, min(CAST(pu.fullBath AS UNSIGNED)) as`minbath`, max(CAST(pu.fullBath AS UNSIGNED)) as`maxbath`, min(CAST(pu.Bed AS UNSIGNED)) as`minbed` , max(CAST(pu.Bed AS UNSIGNED)) as`maxbed`, '' as url, '' as source_id, '' as source_name, '' as addresscode, '' as citycode, '' as ctime, '' as paid, '' as similar_url, '' as created_at, '' as updated_at, '' as city_name, '' as service_listing_id FROM wiki_city_list c join propertyinfo p on c.city_id=p.city join ynow_rentwiki.Property_Unitlayout pu on p.prop_ynow_id=pu.P_Ident join (SELECT CAST(substring_index(if(Rent >0 ,Rent,RentLow),'.',1) AS UNSIGNED) as minrent, CAST(substring_index(if(Rent >0,Rent,Renthigh),'.',1) AS UNSIGNED) as maxrent,PRE_Ident,P_Ident,UNL_Ident,RTY_Ident from ynow_rentwiki.Property_rents where P_Ident in (3958, 4576, 4577) and (Rent!='' or (Rentlow!='' and Renthigh!='')) ) as pr on pu.UNL_Ident=pr.UNL_Ident join state s on (p.state = s.stateid OR p.state = s.ShortCut ) WHERE pu.Status='Active' and
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this
Mysql Group By
site About Us Learn more about Stack Overflow the company Business Learn more
Left Join
about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error Code: 1248. http://stackoverflow.com/questions/3363918/mysql-error-1248-42000-every-derived-table-must-have-its-own-alias Every derived table must have its own alias No solution found for query up vote 2 down vote favorite I am getting an error while using this query in MySQL. The query logic is correct and I have tried it in Oracle and it's running fine, but I'm getting an error when running this in MySQL. I looked at previous questions on StackOverflow, but http://stackoverflow.com/questions/27619026/error-code-1248-every-derived-table-must-have-its-own-alias-no-solution-found didn't find something to help me. Here is the query: select * from (select PM.ID, PM.Name, PM.TIMEOUT, PMS.PROCESS_MONITOR_ID, PMS.PROCESS_START_DATE from RATOR_IMP.PROCESS_MONITOR as PM JOIN RATOR_IMP.PROCESS_MONITOR_STATISTIC as PMS ON PM.ID = PMS.PROCESS_MONITOR_ID WHERE PM.ENABLED=1 and (PM.NAME='SDRRATINGENGINE11' or PM.NAME='WORKFLOWENGINE1') order by PMS.PROCESS_START_DATE desc) limit 10000; And here is the error: Error Code: 1248. Every derived table must have its own alias No soultion found for query mysql sql alias derived-table share|improve this question edited Jun 30 '15 at 5:21 Tristan Tao 386416 asked Dec 23 '14 at 11:01 user1930857 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted You need to provide an alias for the subquery, like so: select * from (select PM.ID, PM.Name, PM.TIMEOUT, PMS.PROCESS_MONITOR_ID, PMS.PROCESS_START_DATE from RATOR_IMP.PROCESS_MONITOR as PM JOIN RATOR_IMP.PROCESS_MONITOR_STATISTIC as PMS ON PM.ID = PMS.PROCESS_MONITOR_ID WHERE PM.ENABLED=1 and (PM.NAME='SDRRATINGENGINE11' or PM.NAME='WORKFLOWENGINE1') order by PMS.PROCESS_START_DATE desc) as s limit 10000; From the documentation, Subqueries are legal in a SELECT statement's FROM clause. The actual syntax is: SELECT ... FROM (subquery) [AS] name ... The [AS] name clause is mandatory, because every table in a FROM clause must have a name. Any columns in
Community Podcasts MySQL.com Downloads Documentation Section Menu: MySQL Forums :: Newbie :: Error Code: 1248. Every derived table must have its own alias New Topic Advanced http://forums.mysql.com/read.php?10,635879,635879 Search Error Code: 1248. Every derived table must have its own alias Posted by: Dileep Vakkalanka () Date: October 12, 2015 03:22PM for simple insert statement INSERT INTO `ap_workflow1` (`UniqueID`,`LinmarUID`,`InvNumber`, http://www.webdeveloper.com/forum/showthread.php?251363-RESOLVED-Every-Table-Derived-Must-Have-An-Alias `PONumber`,`Attachments`) select * from ( SELECT `UniqueID`,`LinmarUID`,`InvNumber`, `PONumber`,`Attachments` FROM `ap_workflow`) ; I'm getting Code: 1248. Every derived table must have its own alias ( both are in same schema mysql error )-- any suggestions and if insert table is moved to another schema what will be issues for insert ? MySQL Query Navigate:Previous Message•Next Message Options:Reply•Quote Subject Written By Posted Error Code: 1248. Every derived table must have its own alias Dileep Vakkalanka 10/12/2015 03:22PM Re: Error Code: 1248. Every derived table must have its own alias Phillip Ward 10/13/2015 mysql error code 05:44AM already answered on this page Peter Brawley 10/13/2015 11:52PM Sorry, you can't reply to this topic. It has been closed. powered by phorum Content reproduced on this site is the property of the respective copyright holders. It is not reviewed in advance by Oracle and does not necessarily represent the opinion of Oracle or any other party. Contact Sales USA: +1-866-221-0634 Canada: +1-866-221-0634 Germany: +49 89 143 01280 France: +33 1 57 60 83 57 Italy: +39 02 249 59 120 UK: +44 207 553 8447 Japan: 0120-065556 China: 10800-811-0823 India: 0008001005870 More Countries» Contact Us Online» Products MySQL Enterprise Edition MySQL Standard Edition MySQL Classic Edition MySQL Cluster CGE MySQL Embedded (OEM/ISV) Services Training Certification Consulting Support Downloads MySQL Community Server MySQL Cluster MySQL Fabric MySQL Utilities MySQL Workbench About MySQL Contact Us How to Buy Partners Job Opportunities Site Map Documentation MySQL Reference Manuals MySQL Workbench Expert Guides Topic Guides MySQL Cluster Legal Legal Policies Your Privacy Rights Terms of Use Trademark Policy Contributor Agreement © 2015, Oracle Corporation and/or its affiliates
Alias If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 6 of 6 Thread: [RESOLVED] Every Table Derived Must Have An Alias Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 09-19-2011,09:20 AM #1 kbc1 View Profile View Forum Posts Registered User Join Date Aug 2007 Posts 94 [RESOLVED] Every Table Derived Must Have An Alias Hi all I have created a query to select data from two different tables but I am getting the following error message: "mysql every derived table must have its own alias" My query should basically search different database fields of mutiple tables for the same keyword which a user has submitted through the search field. Can anyone highlight the error or provide the fix? SELECT * FROM ( SELECT name AS filmname, url AS filmurl, MATCH(tags) AGAINST ('primary') AS newscore FROM tblfilms WHERE MATCH (tags) AGAINST ('primary') UNION SELECT feedurl AS feedname, MATCH(tags) AGAINST ('primary') AS newscore FROM tblrssfeeds WHERE MATCH (tags) AGAINST ('primary') ) ORDER BY newscore DESC Any advice would be greatly appreciated. Doug Reply With Quote 09-19-2011,04:31 PM #2 ranatanveer View Profile View Forum Posts Visit Homepage Registered User Join Date Sep 2011 Posts 2 Use something like: SELECT tblfilms.name ............. Rana Tanveer Affordable Programmers dot com Reply With Quote 09-20-2011,03:25 AM #3 kbc1 View Profile View Forum Posts Registered User Join Date Aug 2007 Posts 94 Thanks for the advice but this hasn't changed anything - I still get the same error message. Reply With Quote 09-20-2011,06:11 AM #4 criterion9 View Profile View Forum Posts B.S. CIS, MPM, CSM Join Date Jan 2009 Posts 3,346