Mysql Error Display
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Mysql Odbc Error
us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is mysql server error a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up how to display MySql error in php up vote 14 down vote favorite In http://php.net/manual/en/mysqli.error.php PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message whenever the query fails but I am having hard time looking for the reason behind this failure. Unfortunately, I couldn't find it because the error is not specified on the web page. My question is, is there any way http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query); if (!$this->result) { printf("Query failed: %s\n", mysqli_connect_error()); exit; } $r = mysqli_query($this->db_link, $query); if($r==false) printf("error: %s\n", mysqli_errno($this->db_link)); php mysql share|improve this question asked Sep 1 '12 at 12:16 Traveling Salesman 56131640 You can just use: $this->db_link->error to get the last error message. For all errors use $this->db_link->error_list. –hakre Sep 1 '12 at 12:31 add a comment| 7 Answers 7 active oldest votes up vote 17 down vote accepted Use this: mysqli_query($this->db_link, $query) or die(mysqli_error($this->db_link)); # mysqli_query($link,$
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log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Display the error message returned form Mysql up vote 0 down vote favorite I need to get the whole error message returned from MySQL and assign it to @error_string : DECLARE CONTINUE HANDLER FOR SQLEXCEPTION BEGIN SET @error_string = 'SQLEXCEPTION_ERROR_MESSAGE'; <-- here END; Is there any alternative, thanks. mysql mysql-5.5 error-handling share|improve this question edited May 13 at 21:40 asked May 13 at 11:12 Mr. LD 326113 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote accepted From MySQL manual: DECLARE CONTINUE HANDLER FOR SQLEXCEPTION BEGIN GET DIAGNOSTICS CONDITION 1 code = RETURNED_SQLSTATE, error_string = MESSAGE_TEXT; END; I am just not sure about the use of local vs. user variables. User ones are visible for entire session and written in the @var form and if you need them, try to just adding @ to the var names in that statement. share|improve this answer answered May 14 at 10:42 jkavalik 3,8691318 Is that working also for MySQL v5.1.73 ? –Mr. LD May 16 at 8:57 1 @YassineLAADIDI seems to be only 5.6+ unfortunately and I did not find a way to emulate it. –jkavalik May 16 at 9:04 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the priv