Mysql Error Nr. 1005
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Regions Error Code 1005
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Can't Create Table (errno 150) Mysql
MySQL Foreign Key Error 1005 errno 150 up vote 31 down vote favorite 8 I'm doing a small DataBase with MySQL Workbench. I have a main table, called "Immobili", which has a Primary Key composed by four columns: (Comune, Via, Civico, Immobile). Now, I also have three other tables, wich have the same primary key (Comune, Via, Civico, Immobile), but these fields are regions unable to process request 1005 also referenced to the table Immobili. First question: Can I make a Primary Key that is also a Foreign Key? Second Question: When I try to export the changes it says: Executing SQL script in server # ERROR: Error 1005: Can't create table 'dbimmobili.condoni' (errno: 150) CREATE TABLE IF NOT EXISTS `dbimmobili`.`Condoni` ( `ComuneImmobile` VARCHAR(50) NOT NULL , `ViaImmobile` VARCHAR(50) NOT NULL , `CivicoImmobile` VARCHAR(5) NOT NULL , `InternoImmobile` VARCHAR(3) NOT NULL , `ProtocolloNumero` VARCHAR(15) NULL , `DataRichiestaSanatoria` DATE NULL , `DataSanatoria` DATE NULL , `SullePartiEsclusive` TINYINT(1) NULL , `SullePartiComuni` TINYINT(1) NULL , `OblazioneInEuro` DOUBLE NULL , `TecnicoOblazione` VARCHAR(45) NULL , `TelefonoTecnico` VARCHAR(15) NULL , INDEX `ComuneImmobile` (`ComuneImmobile` ASC) , INDEX `ViaImmobile` (`ViaImmobile` ASC) , INDEX `CivicoImmobile` (`CivicoImmobile` ASC) , INDEX `InternoImmobile` (`InternoImmobile` ASC) , PRIMARY KEY (`ComuneImmobile`, `ViaImmobile`, `CivicoImmobile`, `InternoImmobile`) , CONSTRAINT `ComuneImmobile` FOREIGN KEY (`ComuneImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ComuneImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `ViaImmobile` FOREIGN KEY (`ViaImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ViaImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `CivicoImmobile` FOREIGN KEY (`CivicoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`CivicoImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `InternoImmobile` FOREIGN KEY (`InternoImmobile` ) REFERENCES `dbimmobili`.`Im
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Overflow the company Business Learn more about hiring developers or posting ads with us error code 10005 Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community mysql can't create table errno 150 foreign key of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error code 1005, SQL state HY000: Can't create table errno: 150 up vote 3 down vote http://stackoverflow.com/questions/4063141/mysql-foreign-key-error-1005-errno-150 favorite 4 I'm trying to create a table but the script fails as soon as my netbeans errors the first table of DB. How can this be solved? CREATE TABLE filmy ( Film_Id int NOT NULL, Nazwa varchar(250), Adres varchar(250), Data_Utworzenia date, Komentarz varchar(250), Gat_Id int, Sub_Id int, Aut_Id int, User_Id int, Primary Key (Film_Id), CONSTRAINT fk_GatFilmy FOREIGN KEY (Gat_Id) REFERENCES gatunek(Gat_Id), CONSTRAINT fk_SubFilmy FOREIGN KEY (Sub_Id) REFERENCES subgatunek(Sub_Id), CONSTRAINT fk_AutFilmy http://stackoverflow.com/questions/8070336/error-code-1005-sql-state-hy000-cant-create-table-errno-150 FOREIGN KEY (Aut_Id) REFERENCES autor(Aut_Id), CONSTRAINT fk_UserFilmy FOREIGN KEY (User_Id) REFERENCES users(User_Id) ) mysql database mysql-error-1005 share|improve this question edited Nov 9 '11 at 19:21 p.campbell 56.1k49187271 asked Nov 9 '11 at 19:19 Malyo 1,08651942 add a comment| 5 Answers 5 active oldest votes up vote 10 down vote accepted Use show innodb status - buried in the output (around the middle) is a "last foreign key error" section. It'll explain exactly why the table creation failed. usually it's due to a reference FK field not existing (typo, wrong table), or there's a field-type mismatch. FK-linked fields must match definitions exactly. A char(1) field can't be FK'd to a char(5) field, etc... Note: In MySQL 5.5, the command for this is show engine innodb status (thanks kewpiedoll99) share|improve this answer edited Sep 19 '13 at 13:18 Enno Shioji 16.3k54993 answered Nov 9 '11 at 19:26 Marc B 273k24233352 +1 you reminded me about type mis-matches. –gbn Nov 9 '11 at 19:29 Thanks! I've found out that the problem was defining referenced to tables, after the references in ,,main'' table. –Malyo Nov 9 '11 at 19:47 1 Wow! show innodb status is priceless for debugging. Thank you very much! –kewpiedoll99 Feb 28 '12 at 15:35 3 o
Communication Skills Training Interpersonal Skills Training Blog About Blog Troy Fawkes / Archives / Solved: MySQL ERROR 1005: Can't create table (errno: 150) (Foreign Key) Nov 27 Solved: MySQL ERROR 1005: Can't create table (errno: https://www.troyfawkes.com/solved-mysql-error-1005-cant-create-table-errno-150/ 150) (Foreign Key) November 27, 2011 Troy Fawkes 8 Comments Archives Share on http://www.terminally-incoherent.com/blog/2007/07/09/mysql-error-1005-can%E2%80%99t-create-table-errno-150/ Facebook Share 0 Share on TwitterTweet 0 Share on Google Plus Share 0 Share on Pinterest Share 0 Share on LinkedIn Share 0 This is another stupid error. It has to do with trying to successfully set foreign keys in MySQL. ERROR 1005: Can't create table (errno: 150) Great, that's fantastic. Here's an example mysql error of where this error will occur. CREATE TABLE main(
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id)
);
CREATE TABLE other(
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
main_id INT NOT NULL,
PRIMARY KEY(id),
FOREIGN KEY(main_id) REFERENCES main(id)
); So I'm trying to make the table "other" reference the table "main" through the foreign key "main_id" and, if you try it, it'll throw an Error 150. Want the solution? can't create table The foreign key "main_id" has to have the exact same type as the primary key that it references. In the example, "main_id" in the table "other" has the type INT NOT NULL while "id" in the table "main" has the type "INT UNSIGNED NOT NULL" and also AUTO_INCREMENT, but that isn't something we have to worry about. To make things incredibly clear, here's the working example. CREATE TABLE main( id INT UNSIGNED NOT NULL AUTO_INCREMENT, PRIMARY KEY(id) ); CREATE TABLE other( id INT UNSIGNED NOT NULL AUTO_INCREMENT, main_id INT UNSIGNED NOT NULL, PRIMARY KEY(id), FOREIGN KEY(main_id) REFERENCES main(id) ); To solve ‘MySQL ERROR 1005: Can't create table (errno: 150)‘ you likely just have to ensure that your foreign key has the exact same type as the primary key. Hope it helps. Share on Facebook Share 0 Share on TwitterTweet 0 Share on Google Plus Share 0 Share on Pinterest Share 0 Share on LinkedIn Share 0 Facebook Twitter Tumblr Pinterest Google+ LinkedIn E-Mail About The Author My name is Troy Boileau but I go by Troy Fawkes. I'm a digital marketer working in Toronto. On top of that, my passions include social skills, networking and dating; subjects that I've been semi-professionally invol
WordPress Plugin IE 6.0 does not understand overflow:auto MySQL: Error 1005 Can’t create table (errno: 150) Posted on July 9, 2007 by Luke Maciak tein.co/1715 This error has been driving me insane all morning. Every time I was trying to create a new InnoDB table with a foreign key constraint I would get the following error: Error 1005 Can’t create table ‘.\mydb\#company.frm’ (errno: 150) My SQL looked something like this: CREATE TABLE company ( `id` INT(32) AUTO_INCREMENT NOT NULL, `name` VARCHAR(50), `cfo` VARCHAR(50), `ceo` VARCHAR(50), `address` text, `tel` VARCHAR(15), `fax` VARCHAR(15), `email` VARCHAR(50), `general_type` enum('broker', 'manufacturer', 'wholesaler', 'service', 'distributor', 'retailer', 'healthcare', 'processor'), `specific_type` VARCHAR(50), `lender_id` INT(32), PRIMARY KEY (id), CONSTRAINT `fk_lender` FOREIGN KEY (`lender_id`) REFERENCES `client` (`lender_id`) ON UPDATE CASCADE, CONSTRAINT `fk_specific_type` FOREIGN KEY (`specific_type`) REFERENCES `specific_type` (`specific_type`) ON UPDATE CASCADE ) ENGINE = InnoDB I kept getting that damn error every single time. At first I figured this was a OS level file access permission issue. But this is not the case - it is just a silly, misleading message. I started googling for it and found some good tips on how to avoid this error at VerySimple Dev Blog. I spent over two hours testing all possible solutions listed in that post. Both tables - client and specific_type were InnoDB. The respective keys were the same type. The charset and collate attributes were set to default in both. And then it hit me. It turns out that my problem was simple - you need to have an index on every field that will be a foreign key. I kinda figured that this would happen automatically, like with primary key, but it doesn't. You need to create the index manually. My updated query looks like this: CREATE TABLE `company` ( `id` INT(32) NOT NULL AUTO_INCREMENT, `name` VARCHA