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Java.net.malformedurlexception No Protocol In Java

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Java.net.malformedurlexception No Protocol Jaxb

java.net.MalformedURLException: no protocol up vote 95 down vote favorite 19 I am getting Java exception like: java.net.MalformedURLException: no protocol My program is trying to parse an XML string by using: Document dom; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); dom = db.parse(xml); The XML string contains: String xml = ""+ " "+ " "+ " 50d69ff9-8cf3-4c20-afe5-63a9047348ad"+ " eb791540-ad6d-48a3-914d-d74f57d88179"+ " "+ " "+ " "+ " "+ " Valid User"+ " "+ " true"+ " 999993_310661843"+ " "+ " "+ " \n"+ " \n"; Any suggestions about what is causing this error? java xml exception share|improve this question edited Nov 20 '11 at 8:50 JJJ 24.8k95377 asked Nov 10 '09 at 8:56 user206641

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies stringbufferinputstream deprecated of this site About Us Learn more about Stack Overflow the company java.net.malformedurlexception no protocol xml version= 1.0 encoding= utf-8 standalone= yes Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges

Documentbuilder Parse Xml String

Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a http://stackoverflow.com/questions/1706493/java-net-malformedurlexception-no-protocol minute: Sign up java.net.MalformedURLException: no protocol: XML up vote -2 down vote favorite I am trying to output an XML String into a .xml file for debugging purpose. My String looks like this: System.out.println("xmlString = \n" + xmlString); =========================================================== INFO: xmlString = 0 2 true source_t:ST xml http://stackoverflow.com/questions/23027382/java-net-malformedurlexception-no-protocol-xml ... Now, the following code is to output the String into XML file. try { System.out.println("Writing xmlString to xml file"); File file = new File("xmlString.xml"); // if file doesnt exists, then create it if (!file.exists()) { file.createNewFile(); } FileWriter fw = new FileWriter(file.getAbsoluteFile()); BufferedWriter bw = new BufferedWriter(fw); bw.write(xmlString); bw.close(); System.out.println("Done writing file"); } catch (IOException e) { e.printStackTrace(); } But this is the error I got from output log: INFO: Writing xmlString to xml file INFO: Done writing file SEVERE: java.net.MalformedURLException: no protocol: No file is created. Can someone tell me what does this mean? And how to solve this? Thanks in advance ====================================================================================== Edit (I initially though that the error lies at the FileWritter, which is why I didn't post the whole code): I have edited my post to display my whole code. This code is actually called by a JSP file. Which passes the xmlString public class SAXParserClass { //Declare as public since it needs to be redefined for appending into ArrayList public static String row[] = new String[5]; //id, full_message_t, source_t, news_t, link_t public ArrayList XMLReader(String xmlStr

Search Username Password Remember Me? Register Lost Password? facebook google twitter rss Free Web Developer Tools Advanced Search  Forum Programming Languages - More XML Programming java.net.MalformedURLException: http://forums.devshed.com/xml-programming-19/java-net-malformedurlexception-protocol-134187.html no protocol Thread: java.net.MalformedURLException: no protocol Share This Thread  Tweet This + 1 this Post To Linkedin Subscribe to this Thread  Subscribe to This Thread March 26th, 2004,09:10 AM #1 No Profile Picture Derek720HT View Profile View Forum Posts  Registered User Devshed Newbie (0 - 499 posts)  Join Date Mar 2004 Posts 1 Rep Power no protocol 0 java.net.MalformedURLException: no protocol Anyone here run into this Exception? I've got an XML document that I can parse fine when reading it from a file. I'm trying to set something up where I receive the encoded contents of the doc through a request parameter in a .jsp. When I try to parse the contents I get a java.net.MalformedURLException: no java.net.malformedurlexception no protocol protocol. Seems kind of obscure since my XML isn't referring to any other documents. Faq Reply With Quote April 1st, 2004,02:23 AM #2 No Profile Picture bricker42 View Profile View Forum Posts  Moderator =(8^(|) Devshed Intermediate (1500 - 1999 posts)  Join Date Feb 2002 Location Sacramento, CA Posts 1,710 Rep Power 16 You can't parse an xml string using the same method that you use to parse an xml file. If you try using the same method java will try to interpret the xml string as a url and you will get the error you're seeing. If you're working with xml in java I'd recommend using dom4j. It's fast and has the easiest to use API that I've found. It has a DocumentHelper.parse() function that will take an xml string and return a Document. If you use straight JAXP I think you'll need to wrap the xml string in a StringReader. -james Faq Reply With Quote February 25th, 2005,04:06 PM #3 No Profile Picture bcaverly View Profile View Forum Posts  Registered User

 

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