Access 2007 Compile Error Object Required
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Access Vba Compile Error Object Required
more about Stack Overflow the company Business Learn more about hiring developers or posting compile error object required excel macro ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community run time error 424 object required vba Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Trying to trouble Object required error in VBA up vote
Compile Error Object Required Vba
0 down vote favorite I got this problem. I have a form that retrieves a table data using the forms' record source property. When the form's opened, I set its record source property to a module's public method RetrieveMembers. Here's the code below. Private Sub Form_Open(Cancel As Integer) 'set Form's record source property to retrieve a Members table Me.RecordSource = mod_JoinMember.RetrieveMembers End Sub 'mod_JoinMember Class Public Function RetrieveMembers() As
Runtime Error 91
String Dim strSQL As String Set strSQL = "SELECT tbl_Member.Title, tbl_Member.Gender, tbl_Member.LastName, tbl_Member.DateofBirth, tbl_Member.Occupation, tbl_Member.PhoneNoWork, tbl_Member.PhoneNoHome, tbl_Member.MobileNo, tbl_Member.Email, tbl_Member.Address, tbl_Member.State, tbl_Member.Postcode FROM tbl_Member;" RetrieveMembers = strSQL End Function Object required error is thrown. I couldn't comprehend this compile error. I see no wrong with my code since recordsource is a String type property. And my module's function Retrievemembers is returning a String value. Why is it that it's not satisfied with this? sql compiler-errors access-vba share|improve this question asked Jan 30 '12 at 4:43 awongCM 44541330 what line is the error thrown on? (I suspect in code not shown...) –Mitch Wheat Jan 30 '12 at 4:49 It's thrown at the Public Function RetrieveMembers as String line. Just a little info - while the database application is a MS Access 2003, I'm running MS Access 2007 software on my laptop. FYI –awongCM Jan 30 '12 at 12:23 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted Thanks for your help. I fixed it. The reason was because String is not really an Object to begin with. So the 'Set' keyword is not needed - since you don't need to explicitly declare String-type objects any
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Set Vba
us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is error 1004 vba a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Compile Error: Object Required VBA up vote 0 down vote favorite I'm new to http://stackoverflow.com/questions/9059437/trying-to-trouble-object-required-error-in-vba VBA. I'm trying to write a script that cleans up some data from an experiment. I keep getting an error saying "Object Required" and it highlights pold. Does anyone have any idea why? As for the script, I'm trying to go down a column of participant numbers and map out what range each participant is in. There are around 30 lines per participant, and I want to define that as http://stackoverflow.com/questions/11355911/compile-error-object-required-vba values in an array. Sub Cleanthismofoup() Dim pranges(1 To 50) As Long Dim pbegin As Range Dim pend As Range Dim pold As Integer Dim pnew As Integer Dim pcell As Range Dim pcounter As Long Dim i As Long Set pcell = Range("A1:A1") Set pbegin = Range("A2:A2") Set pold = Range("B2:B2").Value pcounter = 0 'for every item, store value in pnew ' move down one line. Check pnew = pold ' if it is, do again. else create new range For i = 1 To rngl pcell = pcell.Offset(-1, 0) pnew = pcell.Cells.Value If pnnew <> pold Then pcell = pend If pcell = pend Then counter = counter + 1 pranges(counter) = pbegin counter = counter + 1 pranges(counter) = pend pbegin = pcell.Offset(-1, 0) Else: pold = pnew End If i = i + 1 Next End Sub excel-vba share|improve this question asked Jul 6 '12 at 4:37 user1505743 111 which line it is encountering an error on? –Craig T Jul 6 '12 at 4:44 You seem to have a mix of pnew and pnnew going on but pnnew isn't declared anywhere. Add Option Explicit to the top of the module if it's not there already –barrowc Jul 11 '12 at
VBA Code & Other Help Excel Help Solved: Compiler error: Object required. If this is your first visit, be sure to check http://www.vbaexpress.com/forum/showthread.php?34091-Solved-Compiler-error-Object-required out the FAQ by clicking the link above. You may http://www.pcreview.co.uk/threads/compile-error-object-required.3832807/ have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 3 of 3 Thread: Solved: Compiler error: Object required. object required Thread Tools Show Printable Version Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 09-18-2010,06:46 AM #1 Birch81 View Profile View Forum Posts View Blog Entries View Articles VBAX Regular Joined Apr 2010 Posts 46 Location Solved: Compiler error: Object required. Hello. Iīm having a bit compile error object problems solving my problem. I canīt seem to figure out where the problem is? I get an compiler error saying Object required. I have the following code. Global CellNyStdInvEgen As Double Global CellNyStdInvFaelles As Double Global CellNyTaetLavFaelles As Double Global CellNyTaetLavEgen As Double Global CellNyLejlFaelles As Double Global CellNyUngdomFaelles As Double Global CellNyEnfasede As Double Global CellNyLevOver25A As Double Global CellNyPrKW As Double Global CellNyFremtid As Double Global CellNyTotal As Double Global TestType As String Sub AssignCells() ' Ny Installation If ActiveWorkbook.Worksheets(1).Range("F12").Value <> "" Then CellNyStdInvEgen = ActiveWorkbook.Worksheets(1).Range("F12").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F13").Value <> "" Then CellNyStdInvFaelles = ActiveWorkbook.Worksheets(1).Range("F13").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F14").Value <> "" Then CellNyTaetLavFaelles = ActiveWorkbook.Worksheets(1).Range("F14").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F15").Value <> "" Then CellNyTaetLavEgen = ActiveWorkbook.Worksheets(1).Range("F15").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F16").Value <> "" Then CellNyLejlFaelles = ActiveWorkbook.Worksheets(1).Range("F16").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F17").Value <> "" Then CellNyUngdomFaelles = ActiveWorkbook.Worksheets(1).Range("F17").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F18").Value <> "" Then CellNyEnfasede = ActiveWorkbook.Worksheets(1).Range("F18").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F20").Value <> "" Then CellNyLevOver25A = ActiveWorkbook.Worksheets(1).Range("F20").Value ElseIf ActiveWorkbook.Worksheets(1).Range("F21").Value <> "" Then CellNyPrKW = ActiveWorkbook.Worksheets(1).Range("F21").Value ElseIf ActiveWor
to write a macro for Outlook 2007, and getting nonsensical compile errors. For example: The following script results in "Compile error: Object required" Sub TestScript() Dim x As Integer Set x = 2 End Sub Am I doing something wrong or is my Outlook VBA just broken? brookh, Jun 13, 2009 #1 Advertisements brookh Guest RE: Compile error: Object required [ANSWER] The "object required" error refers to the "Set" statement, which is only used for assigning objects. When assigning simple variables, do not use "Set". The correct code is: Sub TestScript() Dim x As Integer ' Set x = 2 results in "Compiler error: Object required" x = 2 End Sub "brookh" wrote: > I'm trying to write a macro for Outlook 2007, and getting nonsensical compile > errors. For example: The following script results in "Compile error: Object > required" > > Sub TestScript() > Dim x As Integer > Set x = 2 > End Sub > > Am I doing something wrong or is my Outlook VBA just broken? brookh, Jun 13, 2009 #2 Advertisements Michael Bauer [MVP - Outlook] Guest The Set statement is used only for object variables; but you have declared x as Integer, so x=2 would do it. -- Best regards Michael Bauer - MVP Outlook : Outlook Categories? Category Manager Is Your Tool : VBOffice Reporter for Data Analysis & Reporting :