Bash Interrupt Script On Error
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Bash Script Stop On Error
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Bash Stop Script After Time
Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join bash stop script if command fails them; it only takes a minute: Sign up Stop on first error [duplicate] up vote 115 down vote favorite 28 Possible Duplicate: Automatic exit from bash shell script on error How can I have bash stop on the first command failure, without putting stuff like this all through my code? some_prog || exit 1 some_other_prog || exit 1 bash bash terminate script share|improve this question asked Aug 13 '10 at 6:45 Matt Joiner 41.2k43213382 marked as duplicate by martin clayton, Barmar, Toto, codesparkle, Emil Vikström Oct 13 '12 at 10:31 This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question. add a comment| 1 Answer 1 active oldest votes up vote 237 down vote accepted Maybe you want set -e: http://www.davidpashley.com/articles/writing-robust-shell-scripts.html#id2382181 share|improve this answer answered Aug 13 '10 at 6:50 Alok Singhal 48.8k1290125 31 Be aware of set -e gotchas: mywiki.wooledge.org/BashFAQ/105 –Kris Jun 9 '15 at 10:57 1 @Kris thanks for the link, very interesting. –Alok Singhal Jun 10 '15 at 3:45 2 @Kris, you just broke my heart. I thought -e was infallible. –Trenton Sep 30 '15 at 3:17 add a comment| Not the answer you're looking for? Browse other questions tagged bash or ask your own question. asked 6 years ago viewed 69579 times active 6 years ago Linked 276 Automatic exit from bash shell script on er
Bash Prompts About Writing Robust Bash Shell Scripts Many people hack together shell scripts quickly to do simple tasks, but these soon take on a life of their own. Unfortunately shell scripts are full of subtle effects which result in scripts failing in unusual ways. It's possible to write scripts which minimise
Bash Terminate Script From Function
these problems. In this article, I explain several techniques for writing robust bash scripts. Use set bash exit on error with message -u How often have you written a script that broke because a variable wasn't set? I know I have, many times. chroot=$1 ... rm
Shell Script Error Handling
-rf $chroot/usr/share/doc If you ran the script above and accidentally forgot to give a parameter, you would have just deleted all of your system documentation rather than making a smaller chroot. So what can you do about it? Fortunately bash provides http://stackoverflow.com/questions/3474526/stop-on-first-error you with set -u, which will exit your script if you try to use an uninitialised variable. You can also use the slightly more readable set -o nounset. david% bash /tmp/shrink-chroot.sh $chroot= david% bash -u /tmp/shrink-chroot.sh /tmp/shrink-chroot.sh: line 3: $1: unbound variable david% Use set -e Every script you write should include set -e at the top. This tells bash that it should exit the script if any statement returns a non-true return value. The benefit of using -e is that it prevents errors snowballing into http://www.davidpashley.com/articles/writing-robust-shell-scripts/ serious issues when they could have been caught earlier. Again, for readability you may want to use set -o errexit. Using -e gives you error checking for free. If you forget to check something, bash will do it or you. Unfortunately it means you can't check $? as bash will never get to the checking code if it isn't zero. There are other constructs you could use: command if [ "$?"-ne 0]; then echo "command failed"; exit 1; fi could be replaced with command || { echo "command failed"; exit 1; } or if ! command; then echo "command failed"; exit 1; fi What if you have a command that returns non-zero or you are not interested in its return value? You can use command || true, or if you have a longer section of code, you can turn off the error checking, but I recommend you use this sparingly. set +e command1 command2 set -e On a slightly related note, by default bash takes the error status of the last item in a pipeline, which may not be what you want. For example, false | true will be considered to have succeeded. If you would like this to fail, then you can use set -o pipefail to make it fail. Program defensively - expect the unexpected Your script should take into account of the unexpected, like files missing or directories not being created. There are several things you can do to prevent errors in these situations. For example
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us http://unix.stackexchange.com/questions/82224/how-to-make-bash-abort-the-execution-of-a-script-on-syntax-error Learn more about Stack Overflow the company Business Learn more about hiring developers or http://tldp.org/LDP/abs/html/exit-status.html posting ads with us Unix & Linux Questions Tags Users Badges Unanswered Ask Question _ Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody on error can answer The best answers are voted up and rise to the top How to make bash abort the execution of a script on syntax error? up vote 14 down vote favorite 5 To be on safe side, I'd like bash abort the execution of a script if it encounters a syntax error. To my surprise, I can't achieve this. (set -e is not enough.) Example: #!/bin/bash # Do bash stop script exit on any error: set -e readonly a=(1 2) # A syntax error is here: if (( "${a[#]}" == 2 )); then echo ok else echo not ok fi echo status $? echo 'Bad: has not aborted execution on syntax error!' Result (bash-3.2.39 or bash-3.2.51): $ ./sh-on-syntax-err ./sh-on-syntax-err: line 10: #: syntax error: operand expected (error token is "#") status 1 Bad: has not aborted execution on syntax error! $ Well, we can't check $? after every statement to catch syntax errors. (I expected such safe behavior from a sensible programming language... perhaps this must be reported as a bug/wish to bash developers) More experiments if makes no difference. Removing if: #!/bin/bash set -e # exit on any error readonly a=(1 2) # A syntax error is here: (( "${a[#]}" == 2 )) echo status $? echo 'Bad: has not aborted execution on syntax error!' Result: $ ./sh-on-syntax-err ./sh-on-syntax-err: line 6: #: syntax error: operand expected (error token is "#") status 1 Bad: has not aborted execution on syntax error! $ Perhaps, it's related to exercise 2 from http://mywiki.wooledge.org/BashFAQ/105 and has something to do with (( )). But I find it still unreasonable to continue executing afte a syntax error. No, (( )) makes no differen
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The exit command terminates a script, just as in a C program. It can also return a value, which is available to the script's parent process.Every command returns an exit status (sometimes referred to as a return status or exit code). A successful command returns a 0, while an unsuccessful one returns a non-zero value that usually can be interpreted as an error code. Well-behaved UNIX commands, programs, and utilities return a 0 exit code upon successful completion, though there are some exceptions.Likewise, functions within a script and the script itself return an exit status. The last command executed in the function or script determines the exit status. Within a script, an exit nnn command may be used to deliver an nnn exit status to the shell (nnn must be an integer in the 0 - 255 range).When a script ends with an exit that has no parameter, the exit status of the script is the exit status of the last command executed in the script (previous to the exit).#!/bin/bash COMMAND_1 . . . COMMAND_LAST # Will exit with status of last command. exitThe equivalent of a bare exit is exit $? or even just omitting the exit.#!/bin/bash COMMAND_1 . . . COMMAND_LAST # Will exit with status of last command. exit $?#!/bin/bash COMMAND1 . . . COMMAND_LAST # Will exit with status of last command.