Excel Visual Basic Error 2015
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring excel vba error 2015 evaluate developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question excel vba error codes x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; excel macro on error it only takes a minute: Sign up Excel VBA find string : Error 2015 up vote 1 down vote favorite I have to following code snippet ... Public Sub FindText(path As String, file As String) Dim Found As Range
Excel Formula Error
myText = "test(" MacroBook = ActiveWorkbook.Name ' Open the File Workbooks.Open path & file, ReadOnly:=True, UpdateLinks:=False For Each ws In Workbooks(file).Worksheets With ws Set Found = .UsedRange.Find(What:=myText, LookIn:=xlFormulas, _ LookAt:=xlPart, MatchCase:=False) If Not Found Is Nothing Then ' do stuff ' ... I see in the debugger that Found contains Error 2015! The sheet contains the text I want in the formula. Any ideas why I'm getting the error? Thanks excel vba excel-vba find share|improve this question edited Feb 25 excel function error '14 at 13:15 asked Feb 25 '14 at 12:22 Rueful Rabbit 3127 1 it's because your formula in the sheet returns #VALUE! error. You can handle it using IsError: If Not IsError(Found) Then –simoco Feb 25 '14 at 12:36 is this a sub or function? please, show complete code. –KazimierzJawor Feb 25 '14 at 12:43 1 Bravo Simoco, nice catch! –Rueful Rabbit Feb 25 '14 at 13:21 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted As follow up from comments to the Q, Error 2015 occurs because your formula in the sheet returns #VALUE! error. You can handle it using IsError: If Not Found Is Nothing Then If Not IsError(Found) Then ' do sth End If End If share|improve this answer edited Feb 25 '14 at 16:41 answered Feb 25 '14 at 13:41 simoco 26.7k93552 is there a way of finding which formula is giving the error? –user3540466 Dec 30 '15 at 16:30 add a comment| up vote 0 down vote You don't need to use 'Set' in your code. You only use this to assign a reference to an object. Try:- For Each ws In Workbooks(file).Worksheets With ws Found = .UsedRange.Find(What:=myText, LookIn:=xlFormulas, _ LookAt:=xlPart, MatchCase:=False) If Not Found Is Nothing Then ' do stuff ' ... Hopefully this should work. share|improve this answer answered Feb 25 '14 at 12:28 Mat Richardson 2,579114
formulas as strings and have Excel VBA compute them for you. Only recently I discovered that some of the cells in a workbook contained #VALUE? instead of a sound value. After excel macro on error goto 0 some investigation I found out that, without raising any error at application level
Excel Macro On Error Resume Next
(in VBA), the Application.Evaluate function failed consistently with this error whenever a particular condition occurred. This condition is related to
Excel Macro On Error Exit Sub
limits in the underlying software layer of Excel, the one that runs Application.Evaluate. Apparently this particular error occurs when the parsed function returns a string value having a length above 255 characters. As http://stackoverflow.com/questions/22014093/excel-vba-find-string-error-2015 long as the length of the string is less than or equal to 255 characters, the return value is the desired string. Above 255 characters, the function "crashes". In my case, I was not immediately attended on this error because I used a Variant to store the returned value from Application.Evaluate (sample code): Dim vValue As Variant vValue = Application.Evaluate("GetData()") ' Error 2015 saved in vValue if https://dutchgemini.wordpress.com/2009/08/07/error-2015-using-application-evaluate-in-excel-vba/ GetData returns 255+ characters ActiveCell.Value = vValue If I would have used a String to store the value, I would probably have gotten a "Runtime Error 13 - Type Mismatch" with Excel booming out of my routine without any debugging possibility (sample code): Dim sValue As String sValue = Application.Evaluate("GetData()") ' Run-time error if GetData() returns 255+ characters ActiveCell.Value = sValue To catch problems, I now completed code with an If statement (sample code): Dim vValue As Variant vValue = Application.Evaluate("GetData()") If (VBA.VarType(vValue) = vbError) Then ActiveCell.Value = "String Overflow on GetData()" Else ActiveCell.Value = vValue End If There seem to be more Excel functions that suffer from this 255 character limit, but could not establish which. For the moment, I will apply some workarounds until it gets solved by Microsoft. Dutch Like this:Like Loading... Related Comments (3) 3 Comments » Thanks for this, I was passing through a #value error as I was resetting a combo control Cell link to 0, by defining the field as String trapped the error allowing the "on error goto XXXX" to work as required Comment by John Allott -- June 21, 2012 @ 11:42 pm | Reply The error trapp
Way | Trading Add-ins For Excel | Convert Excel Into Calculating Web Pages Excel Web Pages | Produce Clean Efficient VBA Code Every Time | Build Automated http://www.ozgrid.com/forum/showthread.php?t=54231 Trading Models In Excel | Excel Web Pages | Excel Video Training Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts What's New? Advanced Search Forum HELP FORUMS Excel General error 2015 Excel Training / Excel Dashboards Reports If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have on error to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. If you don't like Google AdSense in the posts, register or log in above. Click here to view the relaunched Ozgrid newsletter. Results 1 to 6 of 6 Thread: error 2015 Thread Tools Show Printable excel macro on Version Search Thread Advanced Search July 19th, 2006 #1 jetted View Profile View Forum Posts Senior Member Join Date 16th June 2004 Location Canada Quebec Posts 260 error 2015 Hi everyone I am getting an "error 2015" and I don't why! Can anyone help me? resultat= Error 2015 VB: Range("c2").Select newvalue = " " newvalue1 = " " For Each rngC In rngJbn rngC = Trim(rngC) If rngC.Value <> newvalue And rngC.Value <> "ab-" Then 'MsgBox "****" & rngC & "***" Resultat = Application.CountIf(Range("C2:C" & Range("C" & Rows.Count).End(xlUp).Row).SpecialCells(xlCellTypeVisible), rngC) Last edited by jetted; July 19th, 2006 at 21:00. Excel Video Tutorials / Excel Dashboards Reports Reply With Quote July 19th, 2006 #2 Batman View Profile View Forum Posts Super Moderator Join Date 8th September 2004 Location Northampton, England Posts 3,368 Re: error 2015 Hi jetted, Without being able to see all your code, I suspect that the problem relates to the use of SpecialCells within the CountIf function. SpecialCells is likely to return a range of non-contiguous cells, assuming that you have hidden rows in the range, but CountIf can't cope with anything other than a single range of cells, e.g