Datediff Overflow Error
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn sharepoint the datediff function resulted in an overflow more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags the datediff function resulted in an overflow performance dashboard Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, difference of two datetime columns caused overflow helping each other. Join them; it only takes a minute: Sign up SQL Server: datediff function resulted in an overflow up vote 7 down vote favorite 3 What does this error mean and how can I avoid datediff seconds overflow it? The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart. I am not using the datediff function. I am doing this query where Timestamp is a datetime type: SELECT TOP 10 * from vSomeView WHERE TimestampUTC >= '2009-08-13 22:17:00' What could I be doing wrong? I'm using SQL Server 2008. sql-server share|improve this question edited Aug 13 '09
Datediff Milliseconds Sql Server
at 23:34 asked Aug 13 '09 at 23:21 da what's happening in the view? –jimconstable Aug 13 '09 at 23:23 Based on the name "vSomeView", it sounds like you are querying against a view. If so, what is the view definition? Perhaps it is using datepart? –Philip Kelley Aug 13 '09 at 23:23 2 Does vSomeView use the DateDiff? –shahkalpesh Aug 13 '09 at 23:23 I think timestamp is a reserved word.. but it looks like you are trying to use it as a column name? Either specify the table name first, and/or choose another column name. –RiddlerDev Aug 13 '09 at 23:27 1 Please post the view definition. Also, please check the objects referenced in the views, on the off-chance that they're also views or maybe even functions. –Philip Kelley Aug 14 '09 at 13:56 | show 5 more comments 3 Answers 3 active oldest votes up vote 12 down vote SQL Server maybe doing a DATEDIFF internally for the comparison and if the two dates are much more than 68 years apart (and the internal DATEDIFF is by seconds), DATEDIFF can error as the output of DATEDIFF is an INT. I've bumped into this before (using DATEDIFF directly) and resolved by casting DATETIME's to DECIMALs as follows: DECLARE @d1 DATETIME DECLARE @d2 DATETIME DECLARE @n1 AS
up Recent PostsRecent Posts Popular TopicsPopular Topics Home Search Members Calendar Who's On Home »
Datediff Bigint
SQL Server 2008 » T-SQL (SS2K8) » DATEDIFF function resulted in an arithmetic overflow error converting expression to data type datetime. overflow on... DATEDIFF function resulted in an overflow on one instance not the other Rate Topic Display Mode mssql datediff Topic Options Author Message SSSoliceSSSolice Posted Thursday, August 5, 2010 9:00 AM SSC Veteran Group: General Forum Members Last Login: Friday, September 9, 2011 8:51 AM Points: 291, Visits: 389 http://stackoverflow.com/questions/1275208/sql-server-datediff-function-resulted-in-an-overflow Any idea why I get the "datediff function resulted in an overflow... error on one instance of SQL Server 2008 and not the other. Instance A - operational dbInstance B - reporting db (transactional replication from 'A')When I use the operation data store to reference a particular table I do not get the error. When I point the query to use http://www.sqlservercentral.com/Forums/Topic964359-392-1.aspx the reporting copy of that table I then get the overflow error.ABS(CONVERT(BIGINT,DateDiff(SS, s.dteAssignEndTS, c.dteFirstAssigned)))Any help is greatly appreciated. Post #964359 HowardWHowardW Posted Thursday, August 5, 2010 9:05 AM Ten Centuries Group: General Forum Members Last Login: Monday, November 3, 2014 8:05 AM Points: 1,191, Visits: 9,892 What are the data types of the two input columns in your datediff? Post #964364 LowellLowell Posted Thursday, August 5, 2010 9:09 AM SSChampion Group: General Forum Members Last Login: Today @ 6:44 AM Points: 14,471, Visits: 38,100 the error is related to the actual data being tested/datediffed. one instance has data that is out of range.when you use datediff with seconds, there can only be something like a 67 year gap; after that the #seconds is greater than an int.switch to datediff(minute and you'll fix the issue...if you are datediffing something that is 90 years, you don't need the # seconds difference anyway.select DateDiff(SS,getdate(),'1900-01-01')Msg 535, Level 16, State 0, Line 1Difference of two datetime columns caused overflow at runtime.do this instead: get minutes, multiply by 60 for seconds.ABS(CONVERT(BIGINT,DateDiff(minute, s.dteAssignEndTS, c.dteFirstAssigned) * 60)) Lowell--he
Server 2016 December 12, 2015Sql Server, Sql Server 2016DATEDIFF_BIG, DATEDIFF_BIG function in Sql, DATEDIFF_BIG in Sql, DATEDIFF_BIG in Sql http://sqlhints.com/tag/the-datediff-function-resulted-in-an-overflow/ 2016, DATEDIFF_BIG in Sql Server 2016, Msg 535 Level 16 State https://www.experts-exchange.com/questions/27896290/SQL-Date-Diff.html 0 Line 1, Sql, Sql 2016, Sql Server, Sql Server 2016, The datediff function resulted in an overflowBasavaraj Biradar DATEDIFF_BIG is one of the new function introduced in Sql Server 2016. It gives the difference between the two dates in the units specified by the overflow error DatePart parameter and the returned unit is of type bigint. This function like DATEDIFF function returns the number of the specified datepart boundaries crossed between the specified startdate and enddate. The difference between these two functions is the return type. DATEDIFF functions return type is INT, whereas the DATEDIFF_BIG functions return type is BIGINT. Syntax: the datediff function DATEDIFF_BIG ( datepart , startdate , enddate ) [ALSO READ] Difference between DATEDIFF and DATEDIFF_BIG functions in Sql Server The request for this new function was submitted on the Microsoft connect site some time back in 2008 by Erland Sommarskog. With DATEDIFF function for milliseconds the maximum difference between startdate and enddate is 24 days, 20 hours, 31 minutes and 23.647 seconds. For second, the maximum difference is 68 years. This is because the return type of the DATEDIFF function is INT and INT datatypes Min and Max value is: -2,147,483,648 to +2,147,483,647. But with DATEDIFF_BIG function the maximum difference is very high as the return type is bigint and it’s Min and Max value is: -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807. Example 1: Basic example SELECT DATEDIFF_BIG(DAY, GETDATE(), GETDATE()+1) 'DateDiff Big' RESULT: ALSO READ: How to get difference between two dates in Years, Months and days in Sql Server Example 2: Below example demonstrates how DATEDIFF and DATEDIF_BIG functions behave differently when the milliseconds difference between
for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Ask a Question Ask for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Expand Search Submit Close Search Login Join Today Products BackProducts Gigs Live Careers Vendor Services Groups Website Testing Store Headlines Experts Exchange > Questions > SQL Date Diff Want to Advertise Here? Solved SQL Date Diff Posted on 2012-10-11 Query Syntax 2 Verified Solutions 20 Comments 1,471 Views Last Modified: 2012-10-16 I get the following error. The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart anybody know how to fix the issue. 0 Question by:aneilg Facebook Twitter LinkedIn Google LVL 9 Best Solution byGianpiero Rossi this work in my side (CODE) Go to Solution 20 Comments LVL 9 Overall: Level 9 Query Syntax 2 Message Expert Comment by:Gianpiero Rossi2012-10-11 could you post the Sql command? 0 LVL 3 Overall: Level 3 Query Syntax 1 Message Expert Comment by:concepcionmark2012-10-11 yes and the data type of the columns involved 0 Message Author Comment by:aneilg2012-10-11 TSM.[SessLastOut] datetime TSM.[Time] then insert the results into ActualListRunH3 nvarchar CONVERT(varchar(6), DATEDIFF(second,TSM.[SessLastOut], TSM.[Time])/3600) + ':' + RIGHT('0' + CONVERT(varchar(2), (DATEDIFF(second, TSM.[SessLastOut], TSM.[Time]) % 3600) / 60), 2) AS ActualListRunH3, example 2011-12-16 15:27:00.000 - 2011-12-16 08:40:00.000 result as HH:MM 06:47 0 LVL 9 Overall: Level 9 Query Syntax 2 Message Expert Comment by:Gianpiero Rossi2012-10-11 thedate diff return an int value that can be too big, so try in this way CONVERT(varchar(6), (CAST(DATEDIFF(minute,TSM.[SessLastOut],[TSM.Time]) AS BIGINT) * 60)/3600) + ':' + RIGHT('0' + CONVERT(varchar(2), <