Error Overlaps With Fastethernet0/0
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172.16 0.0 Overlaps With Fastethernet0 0
Meta Discuss the workings and policies of this site About Us overlaps with serial0/0/0 Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with this ip address and/or subnet mask is not allowed for use on a port us Network Engineering Questions Tags Users Badges Unanswered Ask Question _ Network Engineering Stack Exchange is a question and answer site for network engineers. Join them; it https://learningnetwork.cisco.com/thread/54871 only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Overlapping serial interfaces? (Packet Tracer) [closed] up vote 1 down vote favorite Today I tried configuring some practice assignments at home, with packet tracer. But whenever I http://networkengineering.stackexchange.com/questions/16221/overlapping-serial-interfaces-packet-tracer try to configure and activate the serial interfaces it responds with "198.162.10.0 overlaps with Serial0/0/1" or Serial0/0/0. To make it easier to understand I will give the IP Addressing table: R1: FA0/1:- 160.24.65.1 - 255.255.255.0 S0/0/0: - 198.162.10.1 - 255.255.255.0 S0/0/1: - 198.162.10.9 - 255.255.255.0 R2: S0/0/0: - 198.162.10.2 - 255.255.255.0 S0/0/1: - 198.162.10.5 - 255.255.255.0 R3: FA0/1: - 160.24.65.65 - 255.255.255.0 S0/0/0: - 198.162.10.10 - 255.255.255.0 S0/0/1: - 198.162.10.6 - 255.255.255.0 What am I doing wrong? To the ones who answered, thank you for helping me, but it was not quite what I was after. You see I have to use the 198.162.10.0/24 network for serial links, and 160.24.65.0/24 for local networks. So switching masks might solve it but not within the "rules" of this. To further explain I will put the whole addressing table here: ![enter image description here][1] The topology for the addressing for those who are interested: ![enter image description here][2] Example of a working one with similar networks. ![enter image
Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of http://serverfault.com/questions/510266/cisco-router-configuration-subnet this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Server Fault Questions Tags Users Badges Unanswered Ask Question _ Server https://www.experts-exchange.com/questions/24410603/CCNA-Exam-Router's-configuration.html Fault is a question and answer site for system and network administrators. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can overlaps with answer The best answers are voted up and rise to the top Cisco router configuration subnet up vote 0 down vote favorite I am configuring a router to three different subnet as follow. Sub1: 192.168.1.1-254 255.255.248.0 Sub2: 192.168.2.1-254 255.255.248.0 Sub3: 192.168.3.1-254 255.255.248.0 In my cisco router I am doing the following. Fa0/0 (config-if)# ip address 192.168.1.1 255.255.248.0 This works. However, when i go to overlaps with fastethernet configure my fa1/0. i got the following. (config-if)# ip address 192.168.2.1 255.255.248.0 % 192.168.0.0 overlaps with FastEthernet0/0 How do i resolve this problem? cisco ip router subnet interface share|improve this question asked May 23 '13 at 14:15 user1817081 131127 1 serverfault.com/questions/49765/how-does-ipv4-subnetting-work –TheCleaner May 23 '13 at 14:26 add a comment| 2 Answers 2 active oldest votes up vote 4 down vote accepted The router is correct, because with that subnet mask those addresses do overlap. 192.168.2.1/21, which is what your command tries to configure, is part of a subnet that includes everything from 192.168.1.1 through 192.168.7.255. What you mean to configure is 192.168.2.1/24 which is a mask of 255.255.255.0. You may find it useful to use a subnet calculator (ex: http://www.subnet-calculator.com/ or on my Linux workstations I use the "sipcalc" package). share|improve this answer answered May 23 '13 at 14:21 LapTop006 6,0761325 add a comment| up vote 1 down vote You have a /21 mask (255.255.255.248) The first interface (192.168.1.1/21) is then in this subnet: Address: 192.168.1.1 11000000.10101000.00000 001.00000001 Netmask: 255.255.248.0 = 21 11111111.11111111.11111 000.00000000 Wildcard: 0.0.7.255 00000000.00000000.00000 111.11111111 Network: 192.168.0.0/21 11000000.10101000.00000 000.00000000 HostMin: 192.168.0.1 11000000.10101000.00000 000.00000001 HostMax: 192.168.7.254 11000000.10101000.00000 111.111111
for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Ask a Question Ask for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Expand Search Submit Close Search Login Join Today Products BackProducts Gigs Live Careers Vendor Services Groups Website Testing Store Headlines Experts Exchange > Questions > CCNA Exam: Router's configuration Want to Advertise Here? Solved CCNA Exam: Router's configuration Posted on 2009-05-14 TCP/IP Routers Switches / Hubs 2 Verified Solutions 2 Comments 1,755 Views Last Modified: 2012-08-14 Hi, 1) This is related to the CCNA Exam. 2) This is related to the discussion at one of the prep test 3) There is an error of this router's configuration: R1#config t R1(config)#int fa0/0 R1(configi-if)#ip address 192.168.1.17 255.255.255.0 R1(config-if)#no shutdown R1(config-if)#exit R1(config)#int s0/0 R1(config-if)#ip address 192.168.1.65 255.255.255.240 R1(config-if)#no shutdown / 192.168.1.0 overlaps with FastEthernet0/0 4)The given answer: The subnet mask of the FastEthernet interface should be changed to 255.255.255.240 5)My question: Please say it with your own wordings, but you can give any "links" if necessary: i) Could you show me why we have to change the subnet mask of the FastEthernet interface to 255.255.255.240 6) Thank you tjie 0 Question by:tjie Facebook Twitter LinkedIn Google LVL 8 Best Solution byludo_friend ip address 192.168.1.17 255.255.255.0 specifies that the address is part of the 192.168.1.0/24 subnet (fyi) 24 mask bits = 255.255.255.0 28 mask bits = 255.255.255.240 192.168.1.0/24 subnet has a Go to Solution 2 Comments LVL 8 Overall: Level 8 Routers 6 Switches / Hubs 4 Message Accepted Solution by:ludo_friend2009-05-14 ip address 192.168.1.17 255.255.255.0 specifies that the address is part of the 192.168.1.0/24 subnet (fyi) 24 mask bits = 255.255.255.0 28 mask bits = 255.255.255.240 192