Calculate The Error In Wavelength Measurement
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Percent Error Calculator
hiring developers or posting ads with us Physics Questions Tags Users Badges Unanswered Ask Question _ how to calculate percent error in chemistry Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. Join them; it only takes a percent error definition minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Error propagation from frequency to wavelength up vote 0 down vote favorite
Can Percent Error Be Negative
I have measured a value for a frequency of $1.07 \times 10^{10} \pm 5 \times 10^7) \text{ Hz}$. Obviously it is very simple to find the wavelength from this frequency value, which I have (using $c=2.9979 \times 10^8$). However I am lost as to finding the error for the wavelength. The values I keep calculating for the error keep coming out as 2 orders of magnitude or more from the wavelength, which is very counter-intuitive. Please
Negative Percent Error
help! homework-and-exercises frequency error-analysis wavelength share|cite|improve this question edited Dec 7 '14 at 18:31 Qmechanic♦ 63.7k989239 asked Dec 7 '14 at 17:52 Alex Wilkins 61 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote if error in wavelength is $\delta \lambda$ and error in frequency is $\delta f$ then $${\delta f \over f} = {\delta \lambda \over \lambda}$$ so $${\delta \lambda } = \lambda {\delta f \over f}$$ The formula above should give you something more reasonable for the error in the wavelength. More generally if $$ X=kA^n$$ where k is a perfectly known constant $$ \delta X= X ~|n|{\delta A \over A}$$ share|cite|improve this answer edited Dec 7 '14 at 18:10 answered Dec 7 '14 at 18:04 tom 5,2961124 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged homework-and-exercises frequency error-analysis wavelength or ask your own question. asked 1 year ago viewed 351 times active 1 year ago Upcoming Events 2016 Community Moderator Election ends in 6 days Blog Stack Overflow Podcast #89 - The
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What Is A Good Percent Error
Travel Yahoo Products International Argentina Australia Brazil Canada France Germany India Indonesia Italy Malaysia Mexico New Zealand Philippines Quebec Singapore Taiwan percent error chemistry definition Hong Kong Spain Thailand UK & Ireland Vietnam Espanol About About Answers Community Guidelines Leaderboard Knowledge Partners Points & Levels Blog Safety Tips Science & Mathematics Mathematics Next How do I find the error http://physics.stackexchange.com/questions/151035/error-propagation-from-frequency-to-wavelength in my experiment? (Wavelength measurement of microwaves)? In this experiment I found the wavelength of some microwaves from an ordinary klystron using three methods: 1. generating a standing wave and measuring the location of intensity peaks (which would occur at every 1/2 wavelength) 2. Using a double slit setup and measuring the angles of deflection 3. Using a... show more In this experiment I found the wavelength of some https://answers.yahoo.com/question/?qid=20090928083737AAIIC7Z microwaves from an ordinary klystron using three methods: 1. generating a standing wave and measuring the location of intensity peaks (which would occur at every 1/2 wavelength) 2. Using a double slit setup and measuring the angles of deflection 3. Using a Michelson interferometer each of the methods got me similar results in which the mean wavelength was 2.81 cm and the standard deviation about .10 Of course, because there is no "accepted value" in this experiment the old (measured - accepted) / accepted * 100 thing doesn't work...that's middle school stuff and I'm tired of people trying to give me that as an answer. I realize that the standard deviation can be used, but how do I relate the data given (σ and µ) to the percent error? Follow 1 answer 1 Report Abuse Are you sure you want to delete this answer? Yes No Sorry, something has gone wrong. Trending Now Thomas Rhett Detroit Tigers Khloe Kardashian Tiger Woods Car Insurance iPhone 7 John Cena VA Loans Georgia Lottery Becky Lynch Answers Best Answer: The "Standard Error" is just σ/√(n), where "n" is the number of measurements. Or, in percentage terms, 100σ/(µ√(n)). This is actually the estimated standard deviation of the measured avera
happens that there will approximately some error in the instruments due to negligence in measuring precisely. These approximation values with errors when used http://www.tutorvista.com/physics/formula-for-relative-error in calculations may lead to larger errors in the values. There are two ways to measure errors commonly - absolute error and relative error.The absolute error tells about how much the approximate measured value varies from true value whereas the relative error decides how incorrect a quantity is from the true value.Eg: A carpenter is given a task to find percent error the length of the showcase. Due to his negligence he takes the value as 50.32 m whereas the actual precise value is 50.324 m. In this case to measure the errors we use these formulas. What is Relative Error? Back to Top Suppose the measurement has some errors compared to true values.Relative error decides how incorrect a quantity calculate the error is from a number considered to be true. Unlike absolute error where the error decides how much the measured value deviates from the true value the relative error is expressed as a percentage ratio of absolute error to the true value tells what's the error percentage? How to Calculate the Relative Error? Back to Top To calculate the relative error use the following way:Observe the true value (x) and approximate measured value (xo). Then find the absolute deviation using formulaAbsolute deviation $\Delta$ x = True value - measured value = x - xoThen substitute the absolute deviation value $\Delta$ x in relative error formula given belowRelative error = $\frac{\Delta\ x}{x}$Substitute the values and get the relative error. What is the Formula for Relative Error? Back to Top The relative error formula is given byRelative error =$\frac{Absolute\ error}{Value\ of\ thing\ to\ be\ measured}$ = $\frac{\Delta\ x}{x}$.In terms of percentage it is expressed asRelative error = $\frac{\Delta\ x}{x}$ $\times$ 100 % Here $\Delta$ x and x are absolute error and true value of the measurement. Relative ErrorProblems Back