Error Resource Id #5 Php
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Resource Id 8 Php Mysql
am getting a Resource ID #5 error up vote 1 down vote favorite This is a part of my code, and the echo is to test the value and it gives me Resource ID #5 $id = mysql_query("SELECT id FROM users WHERE firstname='$submittedfirstname' AND lastname='$submittedlastname' AND email='$submittedemail'") or die(mysql_error()); $counter = mysql_num_rows($id); echo $id; I am just getting into programming, and lately seeing lot of php mysql resource id #3 Resource ID outputs/errors while working with Databases. Can someone correct the error in my code? And explain me why it isnt giving me the required output? php share|improve this question asked Mar 17 '12 at 22:26 Kishor 1,25221019 1 If you're just getting into programming, you shouldn't learn the mysql_* functions. Learn PDO or mysqli instead. –Maerlyn Mar 18 '12 at 13:10 I had this but it was because I had an old print_r($my->adapter) in my code. I commented it out. –johnny Nov 17 '15 at 18:55 add a comment| 4 Answers 4 active oldest votes up vote 4 down vote accepted This is not an error. This is similar to when you try to print an array without specifying an index, and only the string "Array" is printed. You can access the actual data contained within that resources (which you can think of as a collection of data) using functions like mysql_fetch_array(). In fact, if there were an error here, the value of $id would not be a resource. I usually use the is_resource() function to verify that everything is alright before using variables which are supposed to contai
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Mysql_query Returns Resource Id #5
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What Is Resource Id In Php
Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; http://stackoverflow.com/questions/9754320/figuring-out-why-i-am-getting-a-resource-id-5-error it only takes a minute: Sign up resource id #4 Why am I getting this? up vote 3 down vote favorite I have a pretty basic forum template I am working on for testing purposes When I create a topic, and press submit, the proccess updates the database but doesn't output on the screen. Why is this? and Why http://stackoverflow.com/questions/13189764/resource-id-4-why-am-i-getting-this am I getting a Resource id #4 when I echo the $result from this code below:
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us http://stackoverflow.com/questions/12686304/mysql-error-resource-id5 Learn more about Stack Overflow the company Business Learn more about hiring developers or http://www.webdeveloper.com/forum/showthread.php?132454-Resource-id-5 posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up mysql error resource id#5 up vote 1 down vote resource id favorite I have this little code snippet, but it's not really working right now. I always have the resource id#5 error. I searched in google for a few pointers but didn't found mutch to pass this issue. Here my code ".mysql_error()); echo $result_1; ?> Error: Resource id #5 php mysql share|improve this question asked Oct 2 '12 at 7:44 Johnny000 94711741 Whats in "load_db.php" ? –BugFinder Oct 2 '12 at 7:45 is in load_db.php –Johnny000 Oct 2 '12 at 7:46 nevermind...... –ashiaka Oct 2 '12 at 7:47 add a comment| 2 Answers 2 active oldest votes up vote 4 down vote accepted You are using twice mysql_query(), remove mysql_query() from $sql: $var1 = mysql_real_escape_string($_POST["gender_1"]); $var2 = mysql_real_escape_string($_POST["gender_2"]); $var3 = mysql_real_escape_string($_POST["age"]); $sql = "SELECT url FROM links WHERE gender ='".$var1."' AND gender1 ='".$var2."' AND age ='".$var3."'"; $result_1 = mysql_query($sql) OR die("Error: $sql ".mysql_error()); then loop in results: while($row = mysql_fetch_array($result_1)){ print_r($row); } share|improve this answer edited Oct 2 '12 at 7:49 answered Oct 2 '12 at 7:47 Mihai Iorga 28.1k105479 Thanks for the pointer! But still getting Resource id #5 –Johnny000 Oct 2 '12 at 7:50 And you did exactly like I said? –Mihai Iorga Oct 2 '12 at 7:51 I was too quick, the loop thing wasn't posted yet. Now it's working! Thanks alot! –Johnny00
be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 6 of 6 Thread: Resource id #5 ??? Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 12-22-2006,12:48 AM #1 72newbie View Profile View Forum Posts Registered User Join Date Dec 2005 Posts 193 Resource id #5 ??? hi, I'm trying to get a script working but keep getting an error, Resource id #5 here's the code: PHP Code:
$dbh=mysql_connect($dbhost,$dbuser,$dbpass)
ordie(mysql_error());
mysql_select_db("home_protree")ordie(mysql_error());
//Getallthedatafromthetable
$result=mysql_query("SELECTAVG(rctt)FROMname")
ordie(mysql_error());
echo"