Python Socket.error Errno 35 Resource Temporarily Unavailable
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Errno 35 Resource Deadlock Avoided
Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. python oserror errno 35 resource temporarily unavailable Join them; it only takes a minute: Sign up Python socket error no 35 up vote 0 down vote favorite I have a strange problem. Trying to write a network app in python. Currently I am using osx python socket resource temporarily unavailable and I have troubles with sockets. My code works fine on debian, but when I try to use recv(buff_size) on a connected tcp socket I get this error: socket.error: [Errno 35] Resource temporarily unavailable python sockets networking tcp share|improve this question asked Feb 13 at 7:49 Fulaphex 1248 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote accepted Are you using non-blocking sockets, or timeouts? According to this table, Errno 35 is EAGAIN
Python Ioerror "resource Temporarily Unavailable"
on OSX; according to Apple man pages recv(2): [EAGAIN] The socket is marked non-blocking, and the receive operation would block, or a receive timeout had been set, and the timeout expired before data were received. It could also be possible that socket.setdefaulttimeout was called with non-zero value (in which case socket.getdefaulttimeout would return non-none value. See also Spurious recv() EAGAIN on OSX?; Blocking socket returns EAGAIN. share|improve this answer edited Feb 13 at 9:12 answered Feb 13 at 8:11 Antti Haapala 43.6k1076116 I didn't set sockets to be either blocking or non blocking. I thought they are blocking by default. When I have set it manually to blocking, it works. –Fulaphex Feb 13 at 8:14 But in an example, that I got from some tutorial I don't see setting socket to blocking and yet recv() just blocks the socket till something comes to the socket. –Fulaphex Feb 13 at 8:17 Yeah, I'd expect them to be blocking as well, but maybe something else is setting a default. –Antti Haapala Feb 13 at 8:22 What confuses me most, is that on debian it is blocking by default, on mac sometimes it is blocking when You don't specify and sometimes not. Messy. But it teaches user, to always take care of everything and make sure, that everything is how he wants it to be –Fulaphex F
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions errno 11 resource temporarily unavailable python Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is "oserror: [errno 11] resource temporarily unavailable" a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Errno 35 (EAGAIN) returned on
Errno List
recv call up vote 2 down vote favorite 1 I have a socket which waits for recv and then after receiving data, sends data forward for processing. However, then it again goes for recv, and this time it receives nothing returns -1 and when http://stackoverflow.com/questions/35377454/python-socket-error-no-35 printed the errno it prints 35 (which is EAGAIN). This happens only on MAC OS Lion operating system, for other OS this runs perfectly fine do{ rc = recv(i, buffer, sizeof(buffer), 0); if (rc < 0){ printf("err code %d", errno); } if(rc == 0){ //Code for processing the data in buffer break; } .... }while(1); EDIT: Corrected indentation and errno c osx sockets share|improve this question edited Jan 30 '13 at 2:30 Celada 15.2k22953 asked Jan 30 '13 at 1:37 VijayKumar 13629 ESRCH is an unusual http://stackoverflow.com/questions/14595269/errno-35-eagain-returned-on-recv-call error for a recv() call. Is this a normal network (e.g. IP) socket or socket with a "special" protocol like netlink. Also, please pay attention to your indentation. Although it is not the case, it looks like your if(rc == 0){ ... } block is inside the if (rc < 0){ ... } block, which can't possibly work. –Celada Jan 30 '13 at 2:13 @Celada - Am sorry it was supposed to be errno 35, sorry for the typo... –VijayKumar Jan 30 '13 at 2:20 Whatever the error code is, please post the name of the error instead of its numeric code if you can. You tagged your question osx so I'm looking up the numeric values on MacOS and 35 is EAGAIN, but it's not necessarily the same on every OS. But the names (by and large) so have the same meaning across OSes. By giving the name of the error, you will enable some people to help you who don't have access to MacOS systems so they can find out for themselves. –Celada Jan 30 '13 at 2:29 1 EGAIN means that the kernel has no data to feed your receive buffer with. What about performing a select() call on your socket file descriptor before posting a recv()? –Asblarf Jan 30 '13 at 2:32 Did you set the socket to non-blocking mode? –Nikolai N Fetissov Jan 30 '13 at 2:34 | show 4 more comments 2 Answers 2 active oldest votes up vote 4 down vote accepted You either set the sock
here for a quick overview of the site Help Center Detailed answers to any questions http://stackoverflow.com/questions/39145357/python-error-socket-error-errno-11-resource-temporarily-unavailable-when-s you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community resource temporarily of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python error: “socket.error: [Errno 11] Resource temporarily unavailable” when sending image up vote 1 down vote favorite I want to make a program that accesses images from files, encodes them, and sends them to resource temporarily unavailable an server. Than the server is supposed to decode the image, and save it to file. I tested the image encoding itself, and it worked, so the problem lies in the server and client connection. Here is the server: import socket import errno import base64 from PIL import Image import StringIO def connect(c): try: image = c.recv(8192) return image except IOError as e: if e.errno == errno.EWOULDBLOCK: connect(c) def Main(): host = '138.106.180.21' port = 12345 s = socket.socket(socket.AF_INET, socket.SOCK_STREAM, socket.IPPROTO_TCP) s.setsockopt(socket.SOL_SOCKET,socket.SO_REUSEADDR,1) s.bind((host, port)) s.listen(1) while True: c, addr = s.accept() c.setblocking(0) print "Connection from: " + str(addr) image = c.recv(8192)#connect(c) imgname = 'test.png' fh = open(imgname, "wb") if image == 'cusdom_image': with open('images.png', "rb") as imageFile: image = '' image = base64.b64encode(imageFile.read()) print image fh.write(image.decode('base64')) fh.close() if __name__ == '__main__': Main() And here is the client: import socket import base64 from PIL import Image import StringIO import os, sys ip = '138.106.180.21' port = 12345 print 'Add e