10035 Socket Error Connect
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/1010708/10035-error-on-a-blocking-socket Us Learn more about Stack Overflow the company Business Learn more about hiring http://stackoverflow.com/questions/11647046/non-blocking-socket-error-is-always developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up 10035 error on a blocking socket socket error up vote 2 down vote favorite Does anyone have any idea what could cause a 10035 error (EWOULDBLOCK) when reading on a blocking socket with a timeout? This is under Windows XP using the .NET framework version 3.5 socket library. I've never managed to get this myself, but one of my colleagues is getting it all the time. He's sending reasonably large amounts of data to socket error 10054 a much slower device and then waiting for a response, which often gives a 10035 error. I'm wondering if there could be issues with TCP buffers filling up, but in that case I would expect the read to wait or timeount. The socket is definitely blocking, not non-blocking. .net sockets share|improve this question asked Jun 18 '09 at 3:56 Andrew add a comment| 3 Answers 3 active oldest votes up vote 1 down vote What seems to be happening is that the error occurs when retrying after a timeout on a read. After the timeout (10060) I re-send data and wait for a reply. The timeout seems to set the socket to non-blocking mode, even though the debugger shows Blocking set to true on the .Net socket object, and I immediately get the 10035 error. If I explicitly set Blocking to true on the socket before retrying the 10035 error goes away. This looks like a bug, or possibly a feature, in Winsock or .Net. share|improve this answer answered Jun 24 '09 at 3:53 Andrew bugzilla.novell.com/show_bug.cgi?id=599488 –Lex Li Apr 25 '10 at 1:39 add a comment| up vote 1 down vote probably it
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up non-blocking socket,error is always up vote 5 down vote favorite 1 sock.setblocking(0) try: data = sock.recv(1024) except socket.error, e: if e.args[0] == errno.EWOULDBLOCK: print 'EWOULDBLOCK' else: if not data: #recv over sock.close() print 'close=================' else: print 'recv ---data---------' poem += data all above code is in a loop.using non-blocking socket(just want to test 'non-blocking socket') to get data. But always print 'EWOULDBLOCK',i don't know why? python sockets share|improve this question edited Jul 25 '12 at 13:09 asked Jul 25 '12 at 9:48 zhenyuyang 5618 Add all the code including setting up the socket and what Python version and OS you are running on. –StefanE Jul 25 '12 at 10:41 1 For reference: os.strerror(e.args[0]) will print you the error string. –Alex Oct 21 '15 at 8:40 add a comment| 2 Answers 2 active oldest votes up vote 7 down vote accepted The socket is non-blocking so recv() will raise an exception if there is no data to read. Note that errno.EWOULDBLOCK = errno.EAGAIN = 11. This is Python's (well the OS really) way of telling you to try the recv() again later. I note that you close the socket each time you get this exception. That's not going to help at all. Your code should be something like this: import socket, errno, time sock = socket.socket() sock.connect(('hostname', 1234)) sock.setblocking(0) while True: try: data = sock.recv(1024) if not data: print "connection closed" sock.close() break else: print "Received %d bytes: '%s'" % (len(data), data) except socket.error, e: if e.args[0] == errno.EWOULDBLOCK: print 'EWOULDBLOCK' time.sleep(1) # short delay, no tight loops else: print e break For this sort of thing, the select module is usually the way to go. share|improve this answer answered Jul 25 '12 at 12:10 mhawke 39k53350 thanks.I find the problem is i miss time.sleep(1).without it the print is all ''EWOULDBLOCK''.so why 'no tight loops' is indispensable? –zhenyuyang Jul 25 '12 at 13:04 @zhenyuyang I don't understand 'I miss'