Php Show Sql Error
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policies of this site About Us Learn more about Stack Overflow the i cannot select mysql database company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users mysql_errno Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes http://php.net/manual/en/function.mysql-error.php a minute: Sign up how to display MySql error in php up vote 14 down vote favorite In PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message whenever the query fails but I am having hard time looking http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php for the reason behind this failure. Unfortunately, I couldn't find it because the error is not specified on the web page. My question is, is there any way to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query); if (!$this->result) { printf("Query failed: %s\n", mysqli_connect_error()); exit; } $r = mysqli_query($this->db_link, $query); if($r==false) printf("error: %s\n", mysqli_errno($this->db_link)); php mysql share|improve this question ask
& Database Submit Sign UP Login × Login Username Password Login Cancel Not a member? Sign Up Forgot Password? Contact Us PHP MySQL http://www.plus2net.com/php_tutorial/php_mysql_query.php query with error printing How to write SQL using PHP to handle the data http://jason.pureconcepts.net/2013/04/common-debugging-php-mysql/ in MySQL database? In any database driven script we have to update, add, modify, data in the tables. By using PHP we can do all this using different functions available in PHP. We will start with very basic function, which will execute any query written in sql and can be applied to MySQL sql error database. SQL Structured Query Language or popularly known as SQL is an universal language to handle database. An introduction and different types of sql command like select, insert, update etc you will get in the sql section of this site. There are some advance SQL commands like left join, linking of tables etc to study. If you are not comfortable with SQL any time you can php show sql refer the materials in sql section. There are three steps invoved in this process. Connection to database Build the query and execute Display the data First ensure that you have established your mysql connection through PHP. To get the full details on php mysql connection you can read the article here. If you are using PDO then start with PDO connection string here. PHP Functions & SQL Let us start with the function required to execute one query in PHP. Once you have connection established then we can execute sql command by using PHP function mysql_query(). Here is the syntax of the function. Let us first write the query and store in a variable. We will write a query to create table.$query="CREATE TABLE student ( id int(2) NOT NULL auto_increment, name varchar(50) NOT NULL default '', class varchar(10) NOT NULL default '', mark int(3) NOT NULL default '0', PRIMARY KEY (id) ) TYPE=MyISAM"; We have stored the sql create query in a variable $query and we will pass this as a parameter to the function like below. $rt=mysql_query($query); The above command will execute the query ( stored in variable $query) and we can check the status of
I see many questions on StackOverflow about database issues. This post aims to provide a checklist to help diagnose common issues. While this post contains PHP and MySQL code samples, this debugging checklist applies to other database platforms. First, debugging is hard. Especially debugging database issues. Often times the best approach is to systematically rule out what cannot be the problem. This checklist adopts such an approach from a low to high level. Can you connect to the database outside your application? Verify you can connect to your database by logging into MySQL from the command line. mysql -u dbuser -p -h localhost database If you have a specific database user for your application, be sure to verify their credentials as well. If you do not have command line access, you can use another database administration tool (e.g. PHPMyAdmin). If you cannot connect to the database, you need to start at the beginning: Ensure MySQL is running, your database exists, and your credentials are correct. Can you connect to the database inside your application? Verify you can connect to the database from PHP. Test with a separate script to also rule out bugs in your codebase: query($sql)) { echo 'Error: ', $mysqli->error; } In this case, we’d see that $bad_var is not set. As such, the query becomes: SELECT column FROM table WHERE column = Note: This code above is a contrived example of a dynamic query. If you do not see what else is wrong with this query, please read about SQL injection. You can debug in any order. Top down or bottom up. Just remember this is by no means exhaustive. Nonetheless, following this debugging checklist will help diagnose a majority of your database issues. Please share other common database debugging you use. Find this inter