Avoid Stack Overflow Error Java
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Stackoverflow Error Java
takes a minute: Sign up Java: How to avoid StackOverflowException up vote 10 down vote favorite 2 I'm writing a function that will call itself up to about 5000 times. Ofcourse, I get a StackOverflowException. Is there any way that I can rewrite this code in a fairly simple way?: void checkBlocks(Block b, int amm) { //Stuff that might issue a how to avoid stack overflow in recursion java return call Block blockDown = (Block) b.getRelative(BlockFace.DOWN); if (condition) checkBlocks(blockDown, amm); Block blockUp = (Block) b.getRelative(BlockFace.UP); if (condition) checkBlocks(blockUp, amm); //Same code 4 more times for each side } By the way, what is the limitation of how deep we may call the functions? Thanks! java stack-overflow share|improve this question asked Apr 9 '12 at 12:52 Henrik Karlsson 3,59321534 stackoverflow.com/questions/214741/… –Balaswamy Vaddeman Apr 9 '12 at 13:01 add a comment| 6 Answers 6 active oldest votes up vote 13 down vote accepted Maybe using a stack? void checkBlocks(Block b, int amm) { Stack
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Avoid Stack Overflow Recursion C#
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or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community http://stackoverflow.com/questions/10073471/java-how-to-avoid-stackoverflowexception of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up java.lang.StackOverflowError due to recursion up vote 4 down vote favorite 2 My problem is that I usually get a java.lang.StackOverflowError when I use recursion. My question is - why does recursion cause stackoverflow so much http://stackoverflow.com/questions/18368406/java-lang-stackoverflowerror-due-to-recursion more than loops do, and is there any good way of using recursion to avoid stack overflow? This is an attempt to solve problem 107, it works well for their example but runs out of stack space for the problem it self. //-1 16 12 21 -1 -1 -1 16 -1 -1 17 20 -1 -1 12 -1 -1 28 -1 31 -1 21 17 28 -1 18 19 23 -1 20 -1 18 -1 -1 11 -1 -1 31 19 -1 -1 27 -1 -1 -1 23 11 27 -1 public class tries { public static int n=7,min=Integer.MAX_VALUE; public static boolean[][] wasHere=new boolean[n][60000]; public static void main(String[] args) { int[] lines=new int[n]; Arrays.fill(lines, -1000); lines[0]=0; int[][] networkMatrix=new int[n][n]; Scanner reader=new Scanner(System.in); int sum=0; for(int k=0; k This Site Careers Other all forums Forum: Beginning Java How to avoid stack overflow error when using recursion? Louis Lewis Ranch Hand Posts: 86 posted 3 years ago I'm trying to write a chess program with the netbeans GUI creator. So far I've got the visual part of the program down; https://coderanch.com/t/618521/java/java/avoid-stack-overflow-error-recursion I've created a chess board that will set up on command, and with pieces that you can move anywhere on the board by clicking them twcie (once to select, once to move), and now I'm trying to add restrictions to only https://www.quora.com/Why-does-my-recursive-binary-search-get-a-stack-overflow-error allow legal moves. In order to do this, I created a separate class, which I'm calling Referee, with several methods, all of which build on each other to finally determine whether or not a given move is legal (for example, one method stack overflow checks if a move is legal only in terms of how different pieces are allowed to move, another determines, given a certain position, and using the first method, if either player is in check, and then a final method uses both the surface review based on move capabilites and the position review based on check to decide once and for all if a move is legal). Anyway, the details aren't super important, but the main point is that there are several methods within overflow error java this class, all of which build on each other, and thus need to be called within the class itself. However, the class also has one method that I need to call from the main class (the full review, to determine if a move is legal). In order to be able to call methods from the Referee class within the main class, and the Referee class, I created a separate object in each class (ref1 inside Referee class, and ref2 inside the main class). However, I'm now having trouble with a stack overflow error. The error comes up on the object creation in the main class; I guess what's happening is that when I create the ref2 object, it has to have its own ref1 object, which in turn has to have its own ref1 object, etc. etc., on to infinity. public static void main(String args[]) { Referee ref2 = new Referee(); //the stack overflow error is happening here } public class Referee { Referee ref1 = new Referee(); } Does anyone know how to redesign my class set up such that I don't run into this error? I can't figure out a way to call the referee methods from within the referee class without causing this error, although I guess that it is possible since I have seen recursion sucessfully done before. Help would be much appreciated. Maneesh Godbole Saloon Keeper Posts: 11196 15 I like... posted 3 years ago The root cause is Referee re Computer ProgrammingWhy does my recursive binary search get a stack overflow error?I have written this code in Java, but I get stack over flow error. public static int recursiveBinarySearch(int[] array, int l, int r, int x){ l = 0; r = array.length-1; if(l<=r){ int mid = l + (r-l)/2; if(array[mid] == x) return mid; if(array[mid]>x) return recursiveBinarySearch(array, l, mid-1, x); if(array[mid]