Cause Of Stack Overflow Error
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Stackoverflow Exception In Java
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Fix Stack Overflow Error
up What actually causes a Stack Overflow error? [duplicate] up vote 204 down vote favorite 36 This question already has an answer here: What is a StackOverflowError? 11 answers I've looked everywhere and can't find a solid answer. According to the documentation, Java throws a java.lang.StackOverflowError error under the following circumstance: Thrown when a stack overflow occurs because an application recurses too stack overflow error windows xp deeply. But this raises two questions: Aren't there other ways for a stack overflow to occur, not only through recursion? Does the StackOverflowError happen before the JVM actually overflows the stack or after? To elaborate on the second question: When Java throws the StackOverflowError, can you safely assume that the stack did not write into the heap? If you shrink the size of the stack or heap in a try/catch on a function that throws a stack overflow, can you continue working? Is this documented anywhere? Answers I am not looking for: A StackOverflow happens because of bad recursion. A StackOverflow happens when the heap meets the stack. java jvm stack-overflow share|improve this question edited Mar 4 '14 at 21:54 hichris123 6,536113257 asked Mar 4 '14 at 20:46 retrohacker 1,66231024 marked as duplicate by Jarrod Robersonjava Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed. Dec 28 '15 at 21:24 This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question. 96 +1
may consist of a limited amount of address space, often determined at the start of the program. The size of the call stack depends on many factors, including the programming language, machine architecture, multi-threading, and amount of
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available memory. When a program attempts to use more space than is available on
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the call stack (that is, when it attempts to access memory beyond the call stack's bounds, which is essentially a buffer overflow), stack overflow line error the stack is said to overflow, typically resulting in a program crash.[1] Contents 1 Infinite recursion 2 Very deep recursion 3 Very large stack variables 4 See also 5 References 6 External links Infinite recursion[edit] http://stackoverflow.com/questions/22182669/what-actually-causes-a-stack-overflow-error Main article: Infinite recursion The most common cause of stack overflow is excessively deep or infinite recursion, in which a function calls itself so many times that the space needed to store the variables and information associated with each call is more than can fit on the stack.[2] An example of infinite recursion in C. int foo() { return foo(); } The function foo, when it is invoked, continues to invoke itself, https://en.wikipedia.org/wiki/Stack_overflow allocating additional space on the stack each time, until the stack overflows resulting in a segmentation fault.[2] However, some compilers implement tail-call optimization, allowing infinite recursion of a specific sort—tail recursion—to occur without stack overflow. This works because tail-recursion calls do not take up additional stack space.[3] C compiler options will effectively enable tail-call optimization; compiling the above simple program using gcc with -O1 will result in a segmentation fault, but not when using -O2 or -O3, since these optimization levels imply the -foptimize-sibling-calls compiler option. Other languages, such as Scheme, require all implementations to include tail-recursion as part of the language standard.[4] Very deep recursion[edit] A recursive function that terminates in theory but causes a call stack buffer overflow in practice can be fixed by transforming the recursion into a loop and storing the function arguments in a stack. This is always possible, because the class of primitive recursive functions is equivalent to the class of LOOP computable functions. Consider this example in C++-like pseudocode: void function (argument) { if (condition) function (argument.next); } stack.push(argument); while (!stack.empty()) { argument = stack.pop(); if (condition) stack.push(argument.next); } A primitive recursive function like the one on the left side can always be transformed into a loop like on the right side. Very large stack variables[edit]
My Publications Saturday, July 4, 2009 Diagnosing and Resolving StackOverflowError A recent JavaWorld Community forum message (Stack Overflow after instantiating new object) reminded me that the basics of the StackOverflowError are not always understood well by people new http://marxsoftware.blogspot.com/2009/07/diagnosing-and-resolving.html to Java. Fortunately, the StackOverflowError is one of the easier of the runtime errors to debug and in this blog posting I will demonstrate how easy it often is to diagnose a StackOverflowError. Note that the potential for stack overflow is not limited to Java.Diagnosing the cause of a StackOverflowError can be fairly straightfoward if the code has been compiled with the debug option turned on so that stack overflow line numbers are available in the resulting stack trace. In such cases, it is typically simply a matter of finding the repeating pattern of line numbers in the stack trace. The pattern of repeating line numbers is helpful because a StackOverflowError is often caused by unterminated recursion. The repeating line numbers indicate the code that is being directly or indirectly recursively called. Note that there are situations stack overflow error other than unbounded recursion in which a stack overflow might occur, but this blog posting is limited to StackOverflowError caused by unbounded recursion.The relationship of recursion gone bad to StackOverflowError is noted in the Javadoc description for StackOverflowError that states that this Error is "Thrown when a stack overflow occurs because an application recurses too deeply." It is significant that StackOverflowError ends with the word Error and is an Error (extends java.lang.Error via java.lang.VirtualMachineError) rather than a checked or runtime Exception. The difference is significant. The Error and Exception are each a specialized Throwable, but their intended handling is quite different. The Java Tutorial points out that Errors are typically external to the Java application and thus normally cannot and should not be caught or handled by the application.I will demonstrate running into StackOverflowError via unbounded recursion with three different examples. The code used for these examples is contained in three classes, the first of which (and the main class) is shown next. I list all three classes in their entirety because line numbers are significant when debugging the StackOverflowError.StackOverflowErrorDemonstrator.javapackage dustin.examples.stackoverflow;import java.io.IOException;import java.io.OutputStream;/** * This class demonstrates different ways that a StackOverflowError might * occur. */public class StackOverflowErrorDemonstrator{ private static